22-Agric-A1 Applied Plant, Animal or Human Physiology · May 2015
Question 6 of 6: Number of Supplemental LED Lights Required
Nivaar worked solution (AI-drafted; not reviewed by a licensed engineer)
Notes on this paper
Paper format. 04-Agric-A1 Applied Plant Physiology, National Exams
May 2015 — a three-hour closed-book examination; one of two approved
calculator models (Casio or Sharp) is permitted. All six (6) printed questions constitute a
complete exam paper totaling 100 marks, and all six are worked here.
Reference texts. L. Taiz, E. Zeiger, I.M. Møller and A. Murphy,
Plant Physiology and Development, 6th ed. (plant tissue types, photosynthesis,
water potential and osmosis, phytochrome-mediated photoperiodism); E. Runkle, Daily
Light Integral: A Useful Tool for Greenhouse Growers, Michigan State University
Extension (DLI, greenhouse light transmission, supplemental lighting design); ASABE
Standards (American Society of Agricultural and Biological Engineers) (greenhouse
environment engineering).
Question 6: Number of Supplemental LED Lights Required (20 marks)
Find. The number of Blue/Red LED lights needed to supply the 7.4
mol·m⁻²·d⁻¹ supplemental DLI.
Approach. Convert the required supplemental DLI (a daily photon total)
into the instantaneous combined PPFD needed over a full day, then divide by the output of
one light to get the light count, rounding up since a fraction of a light cannot be
installed.
Check: the question gives no
photoperiod for the supplemental lighting itself, so the DLI-to-PPFD conversion below
integrates over a full 24 h day (86,400 s), consistent with the "per day" (d⁻¹)
units used throughout the question. In practice supplemental fixtures would run only
during a chosen photoperiod at a correspondingly higher instantaneous output over fewer
hours — the total daily photon delivery, and hence the light count derived here, is
unchanged by that choice as long as the same total DLI is delivered.
Convert the supplemental DLI target to a combined PPFD.
$$\text{PPFD}_{\text{required}} = \frac{\Delta\text{DLI} \times 10^{6}}
{t_{\text{day}}} = \frac{7.4 \times 10^{6}}{86{,}400} = \boxed{85.65\ \mu\text{mol}
\cdot\text{m}^{-2}\cdot\text{s}^{-1}}$$
Divide by the output of one LED light.
$$n = \frac{\text{PPFD}_{\text{required}}}{\text{output per light}} =
\frac{85.65}{0.51} = 167.9$$
Rounding up (a fractional light cannot be installed, and the count must at least meet the
target):
$$n = \boxed{168\ \text{Blue/Red LED lights}}$$