NivaarExam PrepOfficial exam papers ↗

22-Agric-A4 Fluid Flow · December 2013

Question 2 of 6: Subcritical Flow Over a Bump

Nivaar worked solution (AI-drafted; not reviewed by a licensed engineer)

Notes on this paper

National Exams — December 2013 — 04-Agric-A4, Fluid Flow. Three-hour, open-book exam; a Casio or Sharp approved calculator is permitted. Format: four questions constitute a complete paper, with a choice between 1a/1b and between 4a/4b; all questions require calculation. Both alternatives are solved below for completeness.

Reference texts: White, Fluid Mechanics (7th/8th ed., McGraw-Hill) — open-channel hydraulics (hydraulic jump, gradually varied flow over a bump), pipe friction (Colebrook–White), rotating control volumes (sprinkler reaction), and turbomachinery (pump performance curves, affinity laws).

Question 1b: Subcritical Flow Over a Bump (choose 1a or 1b — equal value)

Question text not reproduced: the examination questions are © Engineers and Geoscientists BC. Open the official past paper (linked at the top of this page) to read the question, then follow the worked solution below.

Given. A wide brick channel carries uniform (normal) flow at a very mild longitudinal slope $S_0 = 0.02^{\circ}$ (an angle, not a percent grade — see the callout below), Manning roughness $n=0.015$. A smooth bump of height $\Delta z = 0.10\ \text{m}$ sits on the bed; the minimum water depth over its crest is $y_2 = 0.50\ \text{m}$, and the source states the resulting surface profile is a slight depression.

QuantityValue
Manning's $n$ (brickwork)0.015
Bed slope, $S_0$$0.02^{\circ}$ ($\tan S_0 = 3.491\times10^{-4}$)
Bump height, $\Delta z$0.10 m
Minimum depth over bump, $y_2$0.50 m
Check: the source prints the slope with a degree symbol, "$0.02^{\circ}$" — taken literally (a very flat channel, $\tan(0.02^\circ)=3.49\times10^{-4}$) rather than as a 2% grade. Only this reading gives subcritical upstream flow ($Fr_1<1$), consistent with the problem's own statement that the bump causes a depression in the water surface (a 2% grade would make the approach flow supercritical, and a positive bump in supercritical flow raises the surface instead).

Find. The velocity over the bump crest, $V_2$, and the flow rate per unit width, $q$.

y₁ (normal) Δz = 10 cm y₂ = 50 cm V₁ V₂ bed rises 10 cm over bump
Figure 1b — Subcritical approach flow ($y_1$, normal depth) accelerates over a positive bump; the free surface dips even though the bed rises, the classic (non-intuitive) open-channel Venturi effect.

Approach. The upstream depth $y_1$ is unknown, but two independent relations pin it down together with the discharge $q$: Manning's equation ties $q$ to the normal depth $y_1$ at the given slope, and the frictionless energy equation across the short bump ties $y_1$ to the known crest depth $y_2$. Solve the two simultaneously (iteratively), keeping the subcritical root.

  1. Manning's equation for the approach flow (wide channel, $R_h\approx y_1$). $$V_1 = \frac{1}{n}y_1^{2/3}S_0^{1/2} \;\Rightarrow\; q = V_1y_1 = \frac{S_0^{1/2}}{n}\,y_1^{5/3} = \frac{(3.491\times10^{-4})^{1/2}}{0.015}\,y_1^{5/3} = 1.246\,y_1^{5/3}.$$
  2. Frictionless energy equation across the bump. Taking the upstream bed as datum ($z_1=0$, $z_2=\Delta z$), $$y_1+\frac{V_1^2}{2g} = \Delta z + y_2 + \frac{V_2^2}{2g}, \qquad V_2 = \frac{q}{y_2}.$$
  3. Solve simultaneously (iterating on $y_1$). Substituting $q=1.246\,y_1^{5/3}$ into the energy equation and searching for the subcritical root ($Fr_1<1$) between $y_1=0.6$–$0.65$ m gives $$\boxed{y_1 \approx 0.623\ \text{m}}, \qquad q = 1.246(0.623)^{5/3} \approx \boxed{q \approx 0.567\ \text{m}^2/\text{s}}.$$ Check: $V_1=q/y_1=0.909\ \text{m/s}$, $Fr_1=V_1/\sqrt{gy_1}=0.37<1$ (subcritical, consistent with a surface depression), and the crest Froude number $Fr_2 = V_2/\sqrt{gy_2}$ stays below 1 as well (crest depth $y_2=0.50\ \text{m}$ exceeds the local critical depth $y_c\approx0.32\ \text{m}$), so the bump does not choke the flow.
  4. Velocity over the bump. $$V_2 = \frac{q}{y_2} = \frac{0.567}{0.50} = \boxed{V_2 \approx 1.13\ \text{m/s}}.$$
QuantityResult
Normal (upstream) depth, $y_1$0.623 m
(a) Velocity over the bump, $V_2$1.13 m/s
(b) Flow rate per unit width, $q$0.567 m²/s