Nivaar worked solution (AI-drafted; not reviewed by a licensed engineer)
Notes on this paper
National Exams — December 2013 — 04-Agric-A4, Fluid Flow. Three-hour, open-book exam; a Casio or Sharp approved calculator is permitted. Format: four questions constitute a complete paper, with a choice between 1a/1b and between 4a/4b; all questions require calculation. Both alternatives are solved below for completeness.
Reference texts: White, Fluid Mechanics (7th/8th ed., McGraw-Hill) — open-channel hydraulics (hydraulic jump, gradually varied flow over a bump), pipe friction (Colebrook–White), rotating control volumes (sprinkler reaction), and turbomachinery (pump performance curves, affinity laws).
Question 1b: Subcritical Flow Over a Bump (choose 1a or 1b — equal value)
Given. A wide brick channel carries uniform (normal) flow at a very mild longitudinal slope $S_0 = 0.02^{\circ}$ (an angle, not a percent grade — see the callout below), Manning roughness $n=0.015$. A smooth bump of height $\Delta z = 0.10\ \text{m}$ sits on the bed; the minimum water depth over its crest is $y_2 = 0.50\ \text{m}$, and the source states the resulting surface profile is a slight depression.
Quantity
Value
Manning's $n$ (brickwork)
0.015
Bed slope, $S_0$
$0.02^{\circ}$ ($\tan S_0 = 3.491\times10^{-4}$)
Bump height, $\Delta z$
0.10 m
Minimum depth over bump, $y_2$
0.50 m
Check: the source prints the slope with a degree symbol, "$0.02^{\circ}$" — taken literally (a very flat channel, $\tan(0.02^\circ)=3.49\times10^{-4}$) rather than as a 2% grade. Only this reading gives subcritical upstream flow ($Fr_1<1$), consistent with the problem's own statement that the bump causes a depression in the water surface (a 2% grade would make the approach flow supercritical, and a positive bump in supercritical flow raises the surface instead).
Find. The velocity over the bump crest, $V_2$, and the flow rate per unit width, $q$.
Figure 1b — Subcritical approach flow ($y_1$, normal depth) accelerates over a positive bump; the free surface dips even though the bed rises, the classic (non-intuitive) open-channel Venturi effect.
Approach. The upstream depth $y_1$ is unknown, but two independent relations pin it down together with the discharge $q$: Manning's equation ties $q$ to the normal depth $y_1$ at the given slope, and the frictionless energy equation across the short bump ties $y_1$ to the known crest depth $y_2$. Solve the two simultaneously (iteratively), keeping the subcritical root.
Frictionless energy equation across the bump. Taking the upstream bed as datum ($z_1=0$, $z_2=\Delta z$),
$$y_1+\frac{V_1^2}{2g} = \Delta z + y_2 + \frac{V_2^2}{2g}, \qquad V_2 = \frac{q}{y_2}.$$
Solve simultaneously (iterating on $y_1$). Substituting $q=1.246\,y_1^{5/3}$ into the energy equation and searching for the subcritical root ($Fr_1<1$) between $y_1=0.6$–$0.65$ m gives
$$\boxed{y_1 \approx 0.623\ \text{m}}, \qquad q = 1.246(0.623)^{5/3} \approx \boxed{q \approx 0.567\ \text{m}^2/\text{s}}.$$
Check: $V_1=q/y_1=0.909\ \text{m/s}$, $Fr_1=V_1/\sqrt{gy_1}=0.37<1$ (subcritical, consistent with a surface depression), and the crest Froude number $Fr_2 = V_2/\sqrt{gy_2}$ stays below 1 as well (crest depth $y_2=0.50\ \text{m}$ exceeds the local critical depth $y_c\approx0.32\ \text{m}$), so the bump does not choke the flow.
Velocity over the bump.
$$V_2 = \frac{q}{y_2} = \frac{0.567}{0.50} = \boxed{V_2 \approx 1.13\ \text{m/s}}.$$