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22-Agric-B2 Structural Design for Agricultural, Biosystems, and Food Industries · December 2017

Question 3 of 6: Timber Lintel B1 and Post P1

Nivaar worked solution (AI-drafted; not reviewed by a licensed engineer)

Notes on this paper

National Exams — 04-Agric-B2, Structural Design of Agricultural, Biosystems and Food Industries — December 2017. 3-hour duration, open-book exam. Question 1 is mandatory; the exam asks for 4 of Questions 2–6 — all five are answered below as a complete study resource.

Reference texts: CSA O86-09, Engineering Design in Wood (attached Tables 6.3.1A/6.3.1D); CSA A23.3-04/14, Design of Concrete Structures (attached reinforcement-ratio Table 2.1); National Building Code of Canada (NBCC) Part 4, structural loads and load combinations; CSA A23.1/A23.2, Concrete Materials and Methods of Concrete Construction; Breyer et al., Design of Wood Structures — ASD/LRFD (shearwall/diaphragm design); MWPS-1, Structures and Environment Handbook (agricultural building loads and details).

Question 3: Timber Lintel B1 and Post P1 (20 marks)

Question text not reproduced: the examination questions are © Engineers and Geoscientists BC. Open the official past paper (linked at the top of this page) to read the question, then follow the worked solution below.

3a) Lintel B1 design

Given.

QuantityValue
Beam total length / post spacing8.4 m (2.4 m overhang + 3.6 m span + 2.4 m overhang)
Point loads8 × 30 kN at 1.2 m centres (already-factored design reactions from the roof truss, see the check note)
Member38×286 mm (2×12) SPF No.1, built up in $n$ plies
SPF No.1/No.2, Table 6.3.1A$f_b=11.8$ MPa, $f_v=1.5$ MPa
Strength modification factorsall $K=1.0$ (given); $\phi_b=0.9$, $\phi_v=0.9$ (CSA O86)

Find. The number of 38×286 plies $n$ required for lintel B1.

P1P13030303030303030kN(direct-to-post loads shown grey; beam design loads red)2.4 m3.6 m2.4 mB1 (multi-ply 38×286 SPF No.1)
Figure 3: beam B1 elevation. Two of the eight 30 kN loads land directly on posts P1 (grey) and bypass the beam; the beam itself carries the remaining six (red).

Approach. Build the shear and bending-moment diagram for the two-support, double-overhang beam under the six beam-applied loads, size the built-up section for the governing (largest-magnitude) moment, then check shear.

  1. Reactions. By symmetry each post carries half of the beam's own six 30 kN loads: $$R_{P1}=\frac{6(30)}{2}=\boxed{90.0\ \text{kN each post}}$$
  2. Moment diagram. Because the two heavily loaded 2.4 m overhangs (two 30 kN loads each) dominate, the beam is in hogging (top fibre tension) over its entire length — the main span never reaches a positive (sagging) moment. The peak occurs directly over each post: $$M_f = -30(2.4)-30(1.2) = -108.0\ \text{kN}\cdot\text{m at each post}$$ (mid-span moment is a lesser $-72.0$ kN·m by comparison, so the post section governs). Peak shear, approaching each post from the overhang side, is $V_f=30+30=60.0$ kN.
  3. Size the built-up section for bending. A single 38×286 ply has $S=bh^2/6=38(286)^2/6=518{,}041\ \text{mm}^3$, and with $n$ plies acting together, $S_n=nS$: $$M_r=\phi_b f_b S_n = 0.9(11.8)(n\times518{,}041)\times10^{-6}=5.50\,n\ \text{kN}\cdot\text{m}$$ Requiring $M_r\ge108.0$: $n\ge108.0/5.50=19.6\Rightarrow\boxed{n=20\ \text{plies}}$.
  4. Check shear for the selected 20-ply section, $A_{20}=20(38)(286)=217{,}360\ \text{mm}^2$: $$V_r=\phi_v f_v\left(\tfrac{2}{3}\right)A_{20}=0.9(1.5)\left(\tfrac{2}{3}\right)(217{,}360)\times10^{-3}=195.6\ \text{kN} \gg 60.0\ \text{kN} \ \checkmark$$ Shear does not govern; bending controls the design.
Check: the 30 kN point loads are taken as already-factored (ULS) design reactions from the truss (no separate D/L split is given for them, unlike Question 2's joint loads), consistent with the question describing them simply as "applied truss loads." A 20-ply built-up 38×286 section (760 mm overall width) is unusually large for a site-built multi-ply header — in practice a glulam or LVL header would likely be substituted — but this is the section size the given SPF No.1 material and stated loads require.
QuantityValue
Post reaction (each), $R_{P1}$90.0 kN
Governing factored moment, $M_f$ (at posts, hogging)108.0 kN·m
Governing factored shear, $V_f$60.0 kN
Required plies, $n$ (bending governs)20 × 38×286 SPF No.1

3b) Post P1 verification

Given.

QuantityValue
Post section140×140 mm SPF No.1 (Table 6.3.1D), $A=19{,}600\ \text{mm}^2$
$f_c$ (compression parallel to grain)8.7 MPa
$K_{Zc}$ (size factor, given)1.14
$K_c$ (slenderness factor, given)0.70
Wind-induced bending stress ratio, $M_f/M_r$0.32 (given)
Axial load, $P_f$beam reaction 90.0 kN + direct truss load 30.0 kN = 120.0 kN

Find. Whether post P1 satisfies the CSA O86 combined axial-plus-bending interaction check.

Approach. Compute the factored compressive resistance $P_r$ with the two given modification factors, then apply the combined-loading interaction $P_f/P_r+M_f/M_r\le1.0$ using the stated 32% bending ratio.

  1. Factored compressive resistance. $$P_r=\phi_c f_c A K_{Zc} K_c = 0.8(8.7)(19{,}600)(1.14)(0.70)\times10^{-3}=\boxed{108.9\ \text{kN}}$$
  2. Axial demand. Post P1 receives half of beam B1's reaction plus the one 30 kN truss load that lands directly on it (Figure 3): $$P_f=90.0+30.0=\boxed{120.0\ \text{kN}}$$
  3. Combined interaction check. $$\frac{P_f}{P_r}+\frac{M_f}{M_r}=\frac{120.0}{108.9}+0.32 = 1.10+0.32=\boxed{1.42 > 1.0}$$
Check: post species/grade is not explicitly stated for P1 in the source; SPF No.1 is assumed for consistency with the SPF No.1 lintel material specified in the same question. Even the bare axial ratio ($P_f/P_r=1.10$) already exceeds 1.0 before any bending is added — post P1, as sized, is not structurally adequate for the given loads; upsizing the post (e.g. to 184×184 mm or a stronger species/grade such as D Fir-L No.1) or adding an intermediate post to halve the tributary beam reaction would be required.
QuantityValue
Factored compressive resistance, $P_r$108.9 kN
Factored axial demand, $P_f$120.0 kN
$P_f/P_r$1.10
Combined interaction ratio1.42 (> 1.0 — inadequate)