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04-BS-1 · May 2018

Question 1 of 8: Nonhomogeneous Euler–Cauchy Equation

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National Exams — May 2018 — 04-BS-1 Mathematics. Three-hour, closed-book exam (one double-sided aid sheet permitted, approved calculator allowed). Format: eight questions offered; any five constitute a complete paper and only the first five appearing in the answer book are marked. All eight are solved below for completeness.

Reference texts: Kreyszig, Advanced Engineering Mathematics (10th ed., Wiley) — ODEs, systems of ODEs, tangent planes, line/surface integrals, Stokes'/divergence theorems, Lagrange multipliers; Stewart, Calculus: Early Transcendentals (9th ed., Cengage) — vectors, gradients, constrained optimization.

Question 1: Nonhomogeneous Euler–Cauchy Equation (20 marks)

Question text not reproduced: the examination questions are © Engineers and Geoscientists BC. Open the official past paper (linked at the top of this page) to read the question, then follow the worked solution below.

Given. An Euler–Cauchy (equidimensional) ODE $x^2y''-4xy'+6y=3x^4$.

Find. The general solution $y(x)$ (two arbitrary constants).

Approach. Solve the homogeneous equation with the power trial $y=x^m$, then, since the forcing power $x^4$ is not one of the homogeneous roots, find a particular solution with the matching trial $y_p=Ax^4$.

  1. Homogeneous solution. Substituting $y=x^m$: $x^2m(m-1)x^{m-2}-4xmx^{m-1}+6x^m=[m(m-1)-4m+6]x^m=0\Rightarrow m^2-5m+6=0=(m-2)(m-3)$, so $m=2,3$ and $$y_h(x)=C_1x^2+C_2x^3.$$
  2. Particular solution. Since $x^4$ is not an Euler-compatible root here, try $y_p=Ax^4$: $y_p'=4Ax^3,\ y_p''=12Ax^2$. Substituting, $$x^2(12Ax^2)-4x(4Ax^3)+6(Ax^4)=(12A-16A+6A)x^4=2Ax^4=3x^4\ \Rightarrow\ A=\frac32.$$
  3. Assemble the general solution. $$y(x)=C_1x^2+C_2x^3+\frac32x^4.$$

$$y(x)=\boxed{C_1x^2+C_2x^3+\tfrac32x^4}$$

QuantityResult
Homogeneous roots$m=2,3$
Particular solution$\tfrac32x^4$
$y(x)$$C_1x^2+C_2x^3+\tfrac32x^4$
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