04-BS-10 · December 2016
Nivaar worked solution (AI-drafted; not reviewed by a licensed engineer)
National Exam 04-BS-10, Thermodynamics — December 2016. 3 hours, Closed-Book Exam (approved calculator and one double-sided 8.5x11-inch aid sheet permitted; property tables and charts supplied in an appendix, interpolation not required). Part A: answer 2 of Questions 1-3 (20 marks each). Part B: answer 4 of Questions 4-9 (15 marks each), for a 100-mark paper. Only the first two Part-A and first four Part-B questions as they appear in the answer book are marked. All nine questions (Part A complete, Part B complete) are solved below for completeness.
Reference texts: Cengel & Boles, Thermodynamics: An Engineering Approach, 8th ed.; Moran, Shapiro, Boettner & Bailey, Fundamentals of Engineering Thermodynamics, 8th ed. All state properties (water/steam, R-134a, air, N₂, CO₂) were computed from high-accuracy equations of state in place of printed property-table interpolation; every boxed numeric result.
Question text not reproduced: the examination questions are © Engineers and Geoscientists BC. Open the official past paper (linked at the top of this page) to read the question, then follow the worked solution below.
Given. Inlet: $P_1=500$ kPa, $T_1=900$ K, $V_1\approx0$. Exit: $P_2=100$ kPa, $T_2=600$ K, $V_2=100$ m/s. $\dot m=10$ kg/s.
Find. (a) $\dot W$ [kW]; (b) $A_2$ [m$^2$].
Include the exit kinetic-energy term in the steady-flow energy balance since the inlet velocity is negligible but the exit is not. The exit area then follows from the mass-flow/continuity relation $\dot m=\rho_2A_2V_2$, using the ideal-gas specific volume at the exit state.
| Quantity | Result |
|---|---|
| (a) $\dot W$ | 3209.9 kW |
| (b) $A_2$ | 0.1722 m² |