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04-BS-11 · December 2018

Question 5 of 7: CaO Coordination Number; Porosity/Grain Size in Ceramics; Weibull Statistics

Nivaar worked solution (AI-drafted; not reviewed by a licensed engineer)

Notes on this paper

National Exam 04-BS-11, Properties of Materials — December 2018. 3 hours, closed-book examination (approved Casio or Sharp calculator only). Notes on the paper state that any five questions constitute a complete paper and only the first five questions appearing in the answer book are marked, with all questions of equal value. All seven questions are solved below for completeness.

Reference texts: Callister & Rethwisch, Materials Science and Engineering: An Introduction, 9th ed. (crystal structure and density, polymers and vulcanization, mechanical properties/tensile testing, phase transformations and heat treatment, corrosion, ceramics and the Weibull distribution, diffusion).

Question 5: CaO Coordination Number; Porosity/Grain Size in Ceramics; Weibull Statistics (20 marks)

Question text not reproduced: the examination questions are © Engineers and Geoscientists BC. Open the official past paper (linked at the top of this page) to read the question, then follow the worked solution below.

Given. (a) $r_{Ca^{2+}}=0.100$ nm, $r_{O^{2-}}=0.140$ nm. (b)–(c) General ceramic microstructure (porosity, grain size) and brittle-fracture behaviour.

Find. (a) Predicted coordination number of Ca$^{2+}$ in CaO. (b) How porosity and grain size affect tensile strength. (c) Why ceramic failure is treated statistically, and how the Weibull distribution is used.

Approach

(a) uses the standard radius-ratio rule: the cation-to-anion radius ratio is compared against the geometric thresholds for each coordination number. (b)–(c) are answered from brittle fracture-mechanics reasoning: ceramics fail from the propagation of their most severe pre-existing flaw, so anything that changes the size/severity of that flaw population changes strength.

  1. (a) Radius ratio. $$\frac{r_{Ca^{2+}}}{r_{O^{2-}}}=\frac{0.100}{0.140}$$ $$\boxed{\text{ratio}\approx0.714}$$ This falls in the range $0.414\le\text{ratio}<0.732$, which predicts coordination number 6 (octahedral coordination). This matches the observed structure of CaO, which crystallizes in the rock-salt (NaCl-type) arrangement with CN$=6$ for both Ca$^{2+}$ and O$^{2-}$.
  2. (b) Effect of porosity. Pores act simultaneously as (i) stress concentrators — geometrically similar to internal cracks — and (ii) a reduction of the effective load-bearing cross-section. Increasing the volume fraction of porosity $P$ reduces strength roughly exponentially, $\sigma\approx\sigma_0\exp(-nP)$ (the Ryshkewitch–Duckworth-type relation), because pores are typically the largest, most severe flaws present and directly control the Griffith fracture stress $\sigma_f\propto1/\sqrt{a}$ (flaw size $a$).
  3. (b) Effect of grain size. Finer grain size increases strength, both through a Hall–Petch-type mechanism ($\sigma_y=\sigma_0+Kd^{-1/2}$, grain boundaries impede whatever elementary process initiates fracture) and, more importantly for ceramics, because the size of the largest intrinsic flaw (a grain-boundary or triple-point microcrack) tends to scale with grain size $d$ — a finer grain structure has a smaller maximum flaw size, which by the Griffith relation directly raises the fracture strength. Fine-grained ceramics are therefore both stronger and more consistent (narrower strength scatter).
  4. (c) Why statistics are needed. Ceramics have essentially no plasticity to blunt or redistribute stress around a crack tip, so failure is governed entirely by the single most severe pre-existing flaw (pore, inclusion, machining damage) in the loaded volume — a "weakest-link" process, analogous to a chain failing at its weakest link, rather than a deterministic bulk-average property like a metal's yield strength. Because flaw size, location and orientation vary randomly from specimen to specimen, and larger specimens/components sample a larger flaw population (and so, statistically, contain a more severe worst flaw), measured strength is inherently scattered and size-dependent — a single strength number is not physically meaningful for design.
  5. (c) The Weibull distribution. The standard statistical model is the survival probability $$P_{surv}(\sigma)=\exp\!\left[-\left(\frac{V}{V_0}\right)\left(\frac{\sigma}{\sigma_0}\right)^m\right]$$ where $m$ is the Weibull modulus (a large $m$ means a narrow, consistent strength distribution — a reliable material with a tightly controlled flaw population; a small $m$ means wide scatter, dominated by a few severe outlier flaws), $\sigma_0$ is a characteristic (scale) strength, and the $V/V_0$ ratio captures the size effect. Designers select an allowable design stress corresponding to an acceptably low probability of failure — not a simple safety factor on a mean strength — and $m$ itself is reported as a key quality/reliability metric for structural ceramics.
QuantityResult
(a) Ca$^{2+}$/O$^{2-}$ radius ratio0.714
(a) Predicted coordination number6 (octahedral) — matches rock-salt CaO
(b) Porosity effectStrength falls roughly exponentially with pore fraction
(b) Grain-size effectFiner grains → higher, more consistent strength
(c) Statistical modelWeibull: $P_{surv}=\exp[-(V/V_0)(\sigma/\sigma_0)^m]$