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04-BS-12 · May 2013

Question 4 of 5: Alkene Geometric Isomers, a Friedel–Crafts Mechanism, and Alkene Stability

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National Exam 04-BS-12, Organic Chemistry — May 2013. 3 hours, closed-book examination; no calculator allowed. Answer ALL FIVE problems; each problem is of equal value (20 points), and the lettered/numbered sub-parts of a given problem may be treated independently.

Reference texts: McMurry, Organic Chemistry, 9th ed. (functional groups, nomenclature, alkene addition reactions, electrophilic aromatic substitution, alkene stability).

Question 4: Alkene Geometric Isomers, a Friedel–Crafts Mechanism, and Alkene Stability (20 marks)

Question text not reproduced: the examination questions are © Engineers and Geoscientists BC. Open the official past paper (linked at the top of this page) to read the question, then follow the worked solution below.

(a) Cis and trans 2-hexene. Both isomers share the molecular formula $\text{C}_6\text{H}_{12}$ (one C=C, four degrees of freedom otherwise saturated); they differ only in the spatial arrangement of the two non-hydrogen groups across the C2=C3 double bond.

CH3HCH2CH2CH3Hcis-2-hexeneCH3HHCH2CH2CH3trans-2-hexene
Fig. Q4a — cis-2-hexene (methyl and propyl chain on the same side of the C=C) vs. trans-2-hexene (opposite sides). Both are C6H12.

(b) Friedel–Crafts acylation mechanism. AlCl3 is a Lewis acid catalyst that first activates the acyl chloride into an electrophilic acylium ion; the aromatic ring then attacks that electrophile, and the resulting non-aromatic arenium (Wheland) intermediate loses a proton to restore the aromatic sextet, giving acetophenone.

Step 1 — AlCl3 generates the acylium electrophileCH3-C(=O)-Cl + AlCl3[CH3-C≡O]+ + AlCl4-a Cl lone pair attacks the electron-poor Al; the C–Cl bond heterolyses, leaving a resonance-stabilised acylium cationStep 2 — the ring attacks the acylium ion, forming the arenium (Wheland) intermediatebenzeneCH3-C≡O+C(=O)CH3Harenium ion: +charge delocalisedover 3 ring carbons-H+ (to AlCl4-)C(=O)CH3acetophenoneStep 3 — loss of H+ restores aromaticity (+ HCl; AlCl3 is regenerated, so it is a true catalyst)
Fig. Q4b — Friedel–Crafts acylation of benzene with acetyl chloride/AlCl3: (1) acylium generation, (2) electrophilic attack by the ring, (3) loss of H+ restores aromaticity, regenerating AlCl3.
  1. Step 1 — generate the electrophile. The carbonyl chlorine's lone pair attacks the empty orbital on Al; the C–Cl bond heterolyses, giving the resonance-stabilised acylium cation $[\text{CH}_3\text{-C}{\equiv}\text{O}]^+$ and $\text{AlCl}_4^-$.
  2. Step 2 — electrophilic attack by the ring. A pair of the ring's delocalised π electrons attacks the acylium carbon, forming a new C–C bond and a cyclohexadienyl (arenium) cation whose positive charge is delocalised over three ring carbons; this carbon is now sp3, temporarily breaking full ring aromaticity.
  3. Step 3 — re-aromatisation. $\text{AlCl}_4^-$ removes the H on the sp3 ring carbon as H+, re-forming the aromatic sextet and giving $\boxed{\text{acetophenone, C}_6\text{H}_5\text{C(=O)CH}_3}$, plus HCl; AlCl3 is regenerated (it is a true catalyst, not a stoichiometric reagent).

(c) Ranking the three 1,2-diethylcyclohexene isomers by stability. Alkene stability increases with the number of carbon substituents directly on the two double-bond carbons themselves (more substitution → more hyperconjugative/inductive stabilisation of the π system) — a ring-carbon or alkyl-chain substituent on the alkene counts, but a substituent one bond further away (allylic, not on the alkene itself) does not add to this count.

EtEt(a)trisubstituted C=CEtEt(b)tetrasubstituted C=CEtEt(c)disubstituted C=C
Fig. Q4c — the same 1,2-diethylcyclohexane skeleton with the ring's one C=C in three different positions relative to the two ethyl groups.
  1. (a) Trisubstituted double bond. The C=C sits between one ethyl-bearing carbon and its unsubstituted ring neighbour. Counting carbon substituents directly on the two alkene carbons: the ethyl-bearing alkene carbon contributes its ring-neighbour and its ethyl group (2), the other alkene carbon contributes only its own ring-neighbour (1) plus an H — $2+1=\boxed{3}$ carbon substituents on the double bond (trisubstituted).
  2. (b) Tetrasubstituted double bond. The C=C sits directly between the two ethyl-bearing carbons. Each alkene carbon now carries both its ring-neighbour and its own ethyl group, with no H left on either alkene carbon: $2+2=\boxed{4}$ carbon substituents (tetrasubstituted) — the most stable of the three.
  3. (c) Disubstituted double bond. The C=C sits on the far side of the ring, away from both ethyl-bearing carbons; each alkene carbon carries only its own ring-neighbour plus an H: $1+1=\boxed{2}$ carbon substituents (disubstituted) — the fewest of the three, hence the least stable. The two ethyl groups here are merely spectator (allylic-or-further) substituents that do not touch the double bond at all.
PartResult
(a)cis-2-hexene & trans-2-hexene, both C6H12
(b)acetophenone, C8H8O (+ HCl; AlCl3 regenerated)
(c)increasing stability: (c) < (a) < (b); least stable = (c)