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04-BS-12 · December 2015

Question 2 of 5: Alkane/Haloalkane Nomenclature & Hydrogenation

Nivaar worked solution (AI-drafted; not reviewed by a licensed engineer)

Notes on this paper

National Exam 04-BS-12, Organic Chemistry — December 2015. 3 hours, closed-book examination; any non-programmable calculator permitted. Answer ALL FIVE problems; each problem is of equal value (20 points), and the lettered sub-parts of a given problem may be treated independently.

Reference texts: McMurry, Organic Chemistry, 9th ed. (functional-group identification, degree of unsaturation, acid-catalysed alcohol dehydration and alkene/arene hydration, alkane nomenclature, catalytic hydrogenation, ester/disulfide isomers, acid-catalysed transesterification mechanism, Markovnikov addition, nitration, carbon classification, benzylic oxidation, diazonium/Sandmeyer synthesis).

Question 2: Alkane/Haloalkane Nomenclature & Hydrogenation (20 marks)

Question text not reproduced: the examination questions are © Engineers and Geoscientists BC. Open the official past paper (linked at the top of this page) to read the question, then follow the worked solution below.

a) Reading each name back into a structure is just locating the parent chain length from the suffix (heptane=7C, octane=8C, pentane=5C) and hanging each cited substituent off the numbered backbone carbon.

(i) 2,3,5-Trimethyl-4-propylheptane.

2,3,5-trimethyl-4-propylheptaneCH3CH3CH2CH2CH3CH3
Fig. Q2a(i)

Condensed: CH3CH(CH3)CH(CH3)CH(CH2CH2CH3)CH(CH3)CH2CH3 — formula C13H28.

(ii) 4-Isobutyl-2,5-dimethylheptane.

4-isobutyl-2,5-dimethylheptaneCH3CH2CH(CH3)CH3CH3
Fig. Q2a(ii)

Condensed: CH3CH(CH3)CH2CH(CH2CH(CH3)CH3)CH(CH3)CH2CH3 — formula C13H28 (a constitutional isomer of part (i) — same formula, different connectivity).

(iii) 3-Chloro-5-iodo-4-methyloctane.

3-chloro-5-iodo-4-methyloctaneClCH3I
Fig. Q2a(iii)

Condensed: CH3CH2CHClCH(CH3)CHICH2CH2CH3 — formula C9H18ClI.

(iv) 1-Bromo-2-chlorohexane.

1-bromo-2-chlorohexaneBrCl
Fig. Q2a(iv)

Condensed: CH2BrCHClCH2CH2CH2CH3 — formula C6H12BrCl.

(v) 2,2,4-Trimethylpentane (iso-octane).

2,2,4-trimethylpentane (iso-octane)CH3CH3CH3
Fig. Q2a(v)

Condensed: CH3C(CH3)2CH2CH(CH3)CH3 — formula C8H18 (the reference compound defining octane rating 100).

b) Two additions to a π-system.

(i) Vinylcyclopropane + HBr. The two alkene carbons are not equivalent: the internal one is attached directly to the strained three-membered ring. Protonating the terminal CH2 places the resulting positive charge on the ring-adjacent carbon, where it is stabilised well beyond an ordinary secondary cation — the cyclopropane ring's bent, high-p-character C–C bonds can donate electron density into the adjacent empty p-orbital much like an allylic/benzylic system (the "cyclopropylcarbinyl cation" effect). Markovnikov's rule and this extra ring stabilisation agree, so Br− captures the ring-adjacent carbon:

vinylcyclopropane
HBr
→
(1-bromoethyl)cyclopropaneBrCH3
Fig. Q2b(i) — Markovnikov addition; the cation forms on the ring-adjacent carbon

$$\mathrm{\text{cyclopropyl-CH{=}CH}_2 + HBr \longrightarrow \boxed{\text{cyclopropyl-CHBr-CH}_3}}$$

Product: (1-bromoethyl)cyclopropane.

(ii) Benzene + H2. Pt/C forces the reduction of all three ring π-bonds; aromaticity's extra resonance stabilisation makes this markedly slower than an isolated-alkene hydrogenation, but Pt/C still drives it to completion:

benzene
H2 (3 eq.)
→
Pt/C
cyclohexane
Fig. Q2b(ii) — forcing catalytic hydrogenation saturates all three ring double bonds

$$\mathrm{C_6H_6 + 3H_2 \xrightarrow{Pt/C} \boxed{C_6H_{12}}}$$

Product: cyclohexane.

PartResult
a(i)–(v)five structures/condensed formulas above
b(i)(1-bromoethyl)cyclopropane
b(ii)cyclohexane