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04-BS-12 · May 2017

Question 4 of 13: Amygdalin & Mandelic Acid — Stereocentres, Enantiomers, Optical Rotation

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Notes on this paper

National Exam 04-BS-12, Organic Chemistry — May 2017. 3 hours, closed-book examination (no textbook aid beyond one double-sided aid sheet); a Casio or Sharp approved calculator is permitted. The paper prints thirteen questions using plain "Question N:" numbering; all thirteen are answered in full below.

Reference texts: McMurry, Organic Chemistry, 9th ed. (functional-group reactivity, amide/β-lactam resonance, stereochemistry and specific rotation, SN1/SN2 and epoxide-opening regiochemistry, cyclohexane conformational analysis, IR/NMR spectroscopy, electrophilic aromatic substitution and multi-step synthesis design, polymer/step-growth chemistry); Atkins, Physical Chemistry, 11th ed. (entropy of intramolecular vs. intermolecular reactions).

Question 4: Amygdalin & Mandelic Acid — Stereocentres, Enantiomers, Optical Rotation

Question text not reproduced: the examination questions are © Engineers and Geoscientists BC. Open the official past paper (linked at the top of this page) to read the question, then follow the worked solution below.

amygdalin — mandelonitrile β-gentiobioside (two glucopyranose rings + the benzylic nitrile carbon)

(a) Eleven stereocentres. Tracing the structure: each of amygdalin's two glucopyranose rings contributes five stereocentres (the anomeric carbon plus C2, C3, C4, C5 — the standard count for a cyclic hexopyranose), and the benzylic carbon bearing –OH/–CN/phenyl/the glycosidic oxygen (the mandelonitrile carbon) is an eleventh. 2 rings × 5 + 1 = 11 stereocentres (the count of potential stereocentres does not depend on which configuration is assigned at each centre). The maximum number of stereoisomers is $$2^{11}=2048.$$

(b) Mandelic acid, PhCH(OH)COOH, has a single stereocentre (the benzylic carbon bearing OH, COOH, phenyl and H):

(R)-mandelic acid
(S)-mandelic acid

(c) A 60:40 mixture of R and S is a partially resolved sample; its observed rotation scales with the enantiomeric excess, not with the raw 60% alone, because the 40% S-fraction cancels an equal 40% of the R-fraction's rotation (racemic pairs contribute nothing):

Given. $[\alpha]_{\text{pure R}}=-154$; sample is 60% R, 40% S.

Find. $[\alpha]_{\text{obs}}$ of the mixture.

  1. Enantiomeric excess. $$\mathrm{ee}=0.60-0.40=0.20\ (20\%)$$
  2. Observed rotation scales linearly with ee. $$[\alpha]_{\text{obs}}=\mathrm{ee}\times[\alpha]_{\text{pure R}}=0.20\times(-154)=\boxed{-30.8^{\circ}}$$ The mixture is R-enriched, so it rotates plane-polarised light in the same (negative) sense as pure R, just scaled down to 20% of the pure compound's magnitude.
QuantityValue
Stereocentres in amygdalin11
Max. stereoisomers2048
ee of the mandelic acid sample20%
[α]obs−30.8°