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04-BS-12 · May 2018

Question 3 of 13: Benzene Metabolism — Arene Oxide and Phenol

Nivaar worked solution (AI-drafted; not reviewed by a licensed engineer)

Notes on this paper

National Exam 04-BS-12, Organic Chemistry — May 2018. 3 hours, closed-book examination (one Casio/Sharp-approved calculator and one hand-written aid sheet permitted); NOTES on page 1 state that TEN (10) questions constitute a complete exam paper and only the first 10 as they appear in the answer book are marked, but this sitting prints 13 numbered questions — every question and sub-part below is answered in full.

Reference texts: McMurry, Organic Chemistry, 9th ed. (drug acid–base/salt pharmacokinetics, steroid/bile-acid amphiphilicity, arene-oxide metabolism, cyclopropane stereochemistry and CIP assignment, reaction-energy diagrams, ester equilibria and intramolecular effective molarity, SN2 stereochemistry at a common stereocentre, named-drug synthesis design, epoxide ring-opening stereochemistry, mass-spectral formula discrimination, opioid IR/NMR structure elucidation, keto–enol tautomerism and conjugation/acidity, and condensation-polymer monomer identification). Every molecular formula, mass-balance, exact-mass, and stereochemical (R/S) assignment below.

Question 3: Benzene Metabolism — Arene Oxide and Phenol (equal value)

Question text not reproduced: the examination questions are © Engineers and Geoscientists BC. Open the official past paper (linked at the top of this page) to read the question, then follow the worked solution below.

benzene
→
arene oxide
→
phenol

a) Oxidation state classification. Benzene (C6H6) → arene oxide (C6H6O) adds one oxygen atom across a ring C=C without removing any hydrogens — this is an oxidation (cytochrome P450 inserts an epoxide oxygen, consuming O2 and NADPH). Arene oxide → phenol is an intramolecular isomerisation (the "NIH shift"): the strained epoxide opens to a benzylic-type cation stabilised by the ring, a 1,2-hydride shift relocates one ring hydrogen, and loss of H+ restores aromaticity as the phenol. No oxygen or hydrogen atom is gained or lost overall in this second step (C6H6O → C6H6O), so it is classified as neither an oxidation nor a reduction.

b) Why phenol is more water-soluble, and why that matters. Phenol's –OH group is a strong hydrogen-bond donor and acceptor, so phenol molecules hydrogen-bond directly with water, whereas benzene has no polar functional group and can only engage water through weak induced-dipole interactions (benzene's water solubility is only ∼0.18 g/100 mL vs. phenol's fully miscible-at-body-temperature behaviour). This matters physiologically because the kidney excretes compounds through an aqueous filtrate (urine); a purely hydrophobic molecule like benzene would simply re-partition back into fatty tissue/cell membranes rather than staying dissolved in urine, so the body cannot eliminate it efficiently until it has been converted to a polar, water-soluble metabolite (phenol, and downstream conjugates such as phenyl sulfate or phenyl glucuronide) that will actually stay dissolved in the aqueous excretory pathway.