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04-BS-7 · December 2014

Question 4 of 13: Radial Inflow Velocity to a Tank Drain

Nivaar worked solution (AI-drafted; not reviewed by a licensed engineer)

Notes on this paper

04-BS-7 Mechanics of Fluids — National Examinations, December 2014. Three (3) hours, closed book. Section A: Calculative (9 questions, do 7); Section B: Analytical/Graphical (4 questions, do 3). Ten questions constitute a complete paper (50 marks). Every printed question is solved below, including the two "extra" questions in each Section beyond the minimum required.

Reference texts: White, Fluid Mechanics, 8th ed. (fluid statics & buoyancy Ch.2; Bernoulli/energy & momentum equations Ch.3; pipe friction & the Moody chart Ch.6; drag on immersed bodies Ch.7).

Question 4 — Radial Inflow Velocity to a Tank Drain (5 marks)

Question text not reproduced: the examination questions are © Engineers and Geoscientists BC. Open the official past paper (linked at the top of this page) to read the question, then follow the worked solution below.

Given.

QuantityValue
Flow rate, Q0.300 L/s
Radius of interest, r100 mm

Find. The velocity V in the tank at r = 100 mm from the hole.

hole (outflow Q) r = 100 mm
Fig. Q4 — water approaches the drain hole radially; the imaginary hemispherical control surface of radius r = 100 mm (dashed) is the surface through which all of Q must pass.

Approach. By continuity, the same flow rate Q passes through every concentric hemispherical control surface surrounding the hole; that surface's area at radius r is 2πr² (a hemisphere, since the tank floor bounds the flow to the upper half-space only).

  1. Hemispherical surface area at r = 100 mm. $$A = 2\pi r^2 = 2\pi(0.100)^2 = \boxed{0.06283\text{ m}^2}$$
  2. Velocity from continuity. $$V = \frac{Q}{A} = \frac{3.00\times10^{-4}}{0.06283} = \boxed{4.775\times10^{-3}\text{ m/s} = 4.78\text{ mm/s}}$$
QuantityResult
Control-surface area at r = 100 mm0.0628 m²
Velocity, V4.78 mm/s