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04-BS-7 · May 2014

Question 8 of 13: Drain-Cleaning Nozzle Thrust

Nivaar worked solution (AI-drafted; not reviewed by a licensed engineer)

Notes on this paper

04-BS-7 Mechanics of Fluids — National Examinations, May 2014. Three (3) hours, closed book. Section A: Calculative (9 questions, do 7); Section B: Analytical/Graphical (4 questions, do 3). Ten questions constitute a complete paper (50 marks). Every printed question is solved below, including the two "extra" questions in each Section beyond the minimum required.

Reference texts: White, Fluid Mechanics, 8th ed. (fluid statics & capillarity Ch.2; Bernoulli/energy equation Ch.3; pipe friction & the Moody chart Ch.6; drag on immersed bodies Ch.7; buoyancy Ch.2; momentum & jet propulsion Ch.3).

Question 8 — Drain-Cleaning Nozzle Thrust (5 marks)

Question text not reproduced: the examination questions are © Engineers and Geoscientists BC. Open the official past paper (linked at the top of this page) to read the question, then follow the worked solution below.

Given.

QuantityValue
Orifice diameter (all 7)2 mm
Supply pressure6 MPa
Side-jet angle from centreline26°
Number of side jets6 (angled rearward, propelling the nozzle forward)
Number of front jets1 (fires forward, opposing the pull)

Find. The net axial (pulling) force developed by the nozzle.

front jet (forward) side jet, 26° from axis (rearward) (6 side jets around circumference) Fⁿ₦₄
Fig. Q8 — drain-cleaning nozzle: the six rearward-angled side jets (26° from the centreline) give a net forward reaction that pulls the hose into the drain, partly offset by the forward-firing front jet.

Approach. Each orifice is a small free jet with velocity from Bernoulli (approach velocity neglected); the six rearward-angled side jets each contribute a forward thrust reaction proportional to cos(26°), opposed by the single forward-firing front jet's full reaction.

  1. Jet velocity and thrust per orifice. $$V=\sqrt{{\frac{{2p}}{{\rho}}}}=\sqrt{{\frac{{2\times6\times10^6}}{{1000}}}}=109.5\text{{ m/s}}$$ $$a=\frac{{\pi}}{{4}}(0.002)^2=3.142\times10^{{-6}}\text{{ m}}^2,\quad Q_j=aV=3.44\times10^{{-4}}\text{{ m}}^3/\text{{s}}$$ $$F_{{jet}}=\rho Q_j V = 1000\times3.44\times10^{{-4}}\times109.5 = 37.7\text{{ N (per orifice)}}$$
  2. Front jet (retarding, full axial reaction). $$F_{{front}} = F_{{jet}} = 37.7\text{{ N, opposing insertion}}$$
  3. Side jets (six, rearward at 26° — radial components cancel by symmetry, axial component drives the nozzle forward). $$F_{{side,axial}} = 6\,F_{{jet}}\cos26^\circ = 6\times37.7\times0.8988 = 203.3\text{{ N}}$$
  4. Net pulling force. $$F_{{net}} = F_{{side,axial}}-F_{{front}} = 203.3-37.7 = \boxed{{165.6\text{{ N}}}}$$
QuantityResult
Jet velocity (each orifice)109.5 m/s
Thrust per orifice37.7 N
Net forward (pulling) force165.6 N