Nivaar worked solution (AI-drafted; not reviewed by a licensed engineer)
Notes on this paper
04-BS-7 Mechanics of Fluids — National Examinations, May 2014. Three (3) hours, closed book. Section A: Calculative (9 questions, do 7); Section B: Analytical/Graphical (4 questions, do 3). Ten questions constitute a complete paper (50 marks). Every printed question is solved below, including the two "extra" questions in each Section beyond the minimum required.
6 (angled rearward, propelling the nozzle forward)
Number of front jets
1 (fires forward, opposing the pull)
Find. The net axial (pulling) force developed by the nozzle.
Fig. Q8 — drain-cleaning nozzle: the six rearward-angled side jets (26° from the centreline) give a net forward reaction that pulls the hose into the drain, partly offset by the forward-firing front jet.
Approach. Each orifice is a small free jet with velocity from Bernoulli (approach velocity neglected); the six rearward-angled side jets each contribute a forward thrust reaction proportional to cos(26°), opposed by the single forward-firing front jet's full reaction.
Jet velocity and thrust per orifice.
$$V=\sqrt{{\frac{{2p}}{{\rho}}}}=\sqrt{{\frac{{2\times6\times10^6}}{{1000}}}}=109.5\text{{ m/s}}$$
$$a=\frac{{\pi}}{{4}}(0.002)^2=3.142\times10^{{-6}}\text{{ m}}^2,\quad Q_j=aV=3.44\times10^{{-4}}\text{{ m}}^3/\text{{s}}$$
$$F_{{jet}}=\rho Q_j V = 1000\times3.44\times10^{{-4}}\times109.5 = 37.7\text{{ N (per orifice)}}$$
Front jet (retarding, full axial reaction).
$$F_{{front}} = F_{{jet}} = 37.7\text{{ N, opposing insertion}}$$
Side jets (six, rearward at 26° — radial components cancel by symmetry, axial component drives the nozzle forward).
$$F_{{side,axial}} = 6\,F_{{jet}}\cos26^\circ = 6\times37.7\times0.8988 = 203.3\text{{ N}}$$