04-BS-9 · December 2017
Nivaar worked solution (AI-drafted; not reviewed by a licensed engineer)
National Exams — December 2017 — 04-BS-9 Basic Electromagnetics. Three-hour, closed-book exam (approved Casio/Sharp calculator only). Aids given: $\varepsilon_0=8.85\times10^{-12}$ F/m, $\mu_0=4\pi\times10^{-7}$ H/m, $e=1.6\times10^{-19}$ C. Format: eight questions offered; any five constitute a complete paper and only the first five appearing in the answer book are marked. All eight are solved below for completeness.
Reference texts: Sadiku, Elements of Electromagnetics / Hayt & Buck, Engineering Electromagnetics — Coulomb's law and superposition for discrete point charges, Gauss's law for cylindrical charge distributions and coaxial capacitors, the Biot–Savart/Ampère force between parallel currents, Biot–Savart on-axis loop fields, Faraday's law for a moving loop in a spatially varying field, and the point (differential) form of Gauss's law for recovering a charge distribution from a given field; Young & Freedman, University Physics with Modern Physics — Snell's law and refracted-ray time-of-flight geometry.
Question text not reproduced: the examination questions are © Engineers and Geoscientists BC. Open the official past paper (linked at the top of this page) to read the question, then follow the worked solution below.
Given.
| Quantity | Value |
|---|---|
| Turns $N$ | 10 |
| Loop area $A$ | 4 m$^2$ |
| Velocity $v$ (northward, $=dx/dt$) | 50 m/s |
| Field profile | $B(x)=B_0e^{-x/a}$, $B_0=10^{-6}$ T, $a=50$ m |
Find. The induced voltage (EMF) at the instant the loop is at $x=0$.
Approach. The flux depends on time only through the loop's position, $\Phi(t)=NAB(x(t))$; apply the chain rule $d\Phi/dt=(d\Phi/dx)(dx/dt)$ with $dx/dt=v$.
| Quantity | Result |
|---|---|
| $dB/dx$ at $x=0$ | $-2.000\times10^{-8}$ T/m |
| Induced EMF at $x=0$ | $4.000\times10^{-5}$ V ($40.00\ \mu$V) |