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24-Bld-A1 Elementary Structural Analysis · May 2018

Question 8 of 8: Virtual work — truss deflections at L 1 and L 2

Nivaar worked solution (AI-drafted; not reviewed by a licensed engineer)

Notes on this paper

National Exams May 2018 — 07-BLD-A1 Elementary Structural Analysis, 3 hours, closed book (approved Casio/Sharp calculator only). Answer ALL of Questions 1–5; answer ONLY ONE of Questions 6, 7 or 8 (this solution set, per pipeline convention, answers all three optional questions).

Reference texts: Hibbeler, Structural Analysis, 10th ed.; Kassimali, Structural Analysis, 6th ed.

Question 8: Virtual work — truss deflections at L1 and L2 (22 marks)

Question text not reproduced: the examination questions are © Engineers and Geoscientists BC. Open the official past paper (linked at the top of this page) to read the question, then follow the worked solution below.

Given. A cantilever truss: L1(0,0), L2(4.2,0), L3(7.2,0), U1(4.2,3), U2(7.2,3) [pinned to a wall]; L3 rests on a roller against a vertical face (horizontal reaction only). Loads: 21 kN down at L1, 14 kN down at U1. $$AE=3.9\times10^4\text{ kN}$$ throughout.

Find. The vertical deflections at L1 and L2.

L1L2L3U1U221 kN14 kN
Cantilever truss (8): pinned at U2, rollered horizontally at L3; loads at L1 and U1.

Approach. Method of joints for the real member forces $$N$$, then virtual work: apply a unit vertical load at L1 (then separately at L2) to get the virtual forces $$n$$, and sum $$\Delta=\Sigma nNL/AE$$ over all 7 members.

  1. Real member forces (method of joints, working from L1 toward the supports). $$N_{L1U1}=\boxed{+36.13\text{ kN (T)}},\quad N_{L1L2}=\boxed{-29.4\text{ kN (C)}},\quad N_{L2U1}=\boxed{-35.0\text{ kN (C)}}$$ $$N_{U1U2}=\boxed{+29.4\text{ kN (T)}},\quad N_{L2L3}=\boxed{-64.4\text{ kN (C)}},\quad N_{L2U2}=\boxed{+49.50\text{ kN (T)}},\quad N_{L3U2}=0$$ (Check: $$R_{y,U2}=21+14=35\text{ kN}$$ ✓.)
  2. Virtual system 1 — unit load at L1. Solving the same truss for a 1 kN downward load at L1 alone gives, member by member, the $$n_1$$ column used below.
  3. Virtual system 2 — unit load at L2. Likewise for a 1 kN downward load at L2 alone.
  4. Sum $$\Delta=\Sigma n N L/AE$$ $$\Delta_{L1}=\boxed{38.0\text{ mm}}\ \downarrow,\qquad \Delta_{L2}=\boxed{12.6\text{ mm}}\ \downarrow$$
Member forces and virtual-work table (L=length, N=real force, n1/n2=virtual forces for unit loads at L1/L2)
MemberL (m)N (kN)n1n2
L1–L24.200−29.40−1.4000
L2–L33.000−64.40−2.400−1.000
U1–U23.000+29.40+1.4000
L1–U15.161+36.13+1.72050
L2–U13.000−35.00−1.0000
L2–U24.243+49.50+1.4142+1.4142
L3–U23.000000
QuantityValue
ΔL138.0 mm, downward
ΔL212.6 mm, downward
Check: L3’s support is drawn resting against a vertical face (horizontal reaction only) — not a conventional vertical roller — which is what makes the truss determinate; a vertical reaction there would over-restrain it by one degree.
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