24-Bld-A1 Elementary Structural Analysis · May 2018
Question 8 of 8: Virtual work — truss deflections at L 1 and L 2
Nivaar worked solution (AI-drafted; not reviewed by a licensed engineer)
Notes on this paper
National Exams May 2018 — 07-BLD-A1 Elementary Structural Analysis, 3 hours, closed book (approved Casio/Sharp calculator only). Answer ALL of Questions 1–5; answer ONLY ONE of Questions 6, 7 or 8 (this solution set, per pipeline convention, answers all three optional questions).
Given. A cantilever truss: L1(0,0), L2(4.2,0), L3(7.2,0), U1(4.2,3), U2(7.2,3) [pinned to a wall]; L3 rests on a roller against a vertical face (horizontal reaction only). Loads: 21 kN down at L1, 14 kN down at U1. $$AE=3.9\times10^4\text{ kN}$$ throughout.
Find. The vertical deflections at L1 and L2.
Cantilever truss (8): pinned at U2, rollered horizontally at L3; loads at L1 and U1.
Approach. Method of joints for the real member forces $$N$$, then virtual work: apply a unit vertical load at L1 (then separately at L2) to get the virtual forces $$n$$, and sum $$\Delta=\Sigma nNL/AE$$ over all 7 members.
Real member forces (method of joints, working from L1 toward the supports).$$N_{L1U1}=\boxed{+36.13\text{ kN (T)}},\quad N_{L1L2}=\boxed{-29.4\text{ kN (C)}},\quad N_{L2U1}=\boxed{-35.0\text{ kN (C)}}$$$$N_{U1U2}=\boxed{+29.4\text{ kN (T)}},\quad N_{L2L3}=\boxed{-64.4\text{ kN (C)}},\quad N_{L2U2}=\boxed{+49.50\text{ kN (T)}},\quad N_{L3U2}=0$$ (Check: $$R_{y,U2}=21+14=35\text{ kN}$$ ✓.)
Virtual system 1 — unit load at L1. Solving the same truss for a 1 kN downward load at L1 alone gives, member by member, the $$n_1$$ column used below.
Virtual system 2 — unit load at L2. Likewise for a 1 kN downward load at L2 alone.
Sum$$\Delta=\Sigma n N L/AE$$$$\Delta_{L1}=\boxed{38.0\text{ mm}}\ \downarrow,\qquad \Delta_{L2}=\boxed{12.6\text{ mm}}\ \downarrow$$
Member forces and virtual-work table (L=length, N=real force, n1/n2=virtual forces for unit loads at L1/L2)
Member
L (m)
N (kN)
n1
n2
L1–L2
4.200
−29.40
−1.400
0
L2–L3
3.000
−64.40
−2.400
−1.000
U1–U2
3.000
+29.40
+1.400
0
L1–U1
5.161
+36.13
+1.7205
0
L2–U1
3.000
−35.00
−1.000
0
L2–U2
4.243
+49.50
+1.4142
+1.4142
L3–U2
3.000
0
0
0
Quantity
Value
ΔL1
38.0 mm, downward
ΔL2
12.6 mm, downward
Check: L3’s support is drawn resting against a vertical face (horizontal reaction only) — not a conventional vertical roller — which is what makes the truss determinate; a vertical reaction there would over-restrain it by one degree.