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24-Bld-A6 Geotechnical Materials and Analysis · December 2017

Question 5 of 7

Nivaar worked solution (AI-drafted; not reviewed by a licensed engineer)

Notes on this paper

07-Bld-A6 Geotechnical Materials and Analysis — National Exam, December 2017. Closed book, 3 hours; drawing instruments and either a Casio or Sharp approved calculator required; the formula sheet and influence charts printed at the back of the exam are reproduced/used inline where needed. Section A (Questions 1–3, 40 marks, answer all) and Section B (Questions 4–7, 20 marks each, the paper asks for any three of four) — all seven questions are answered below.

Reference texts: B. M. Das, Principles of Geotechnical Engineering, 9th ed. (phase relations, seepage/flow nets, stress distribution, consolidation, shear strength); R. F. Craig / J. Knappett, Craig's Soil Mechanics, 9th ed. (flow nets, effective-stress strength parameters); Canadian Foundation Engineering Manual (CFEM), 4th ed.

Check — assumptions and source notes for this paper. (1) Question 4's flow net (Nf = 5 flow channels, Nd = 14 equipotential drops, point A read as three drops upstream of the downstream exit, exit-field length ≈ 2 m) is used with a soil total unit weight of 20 kN/m³. (2) Question 5(ii)'s "approximate" method is extended from the formula sheet's centre-of-rectangle formula to a corner point (point A here is not centred on the loaded area) using the standard mirror/quartering superposition trick, valid because the approximate formula is linear in load exactly like the exact one. (3) Question 6's least-squares fit through the three effective-stress points gives an intercept of −0.7 kPa — not distinguishable from zero with only three data points — so c′ is taken as 0, consistent with the expected behaviour of a normally consolidated clay. (4) Question 7's figure shows three distinct layer thicknesses — H1 = 1.5 m (sand above the water table), H2 = 1.5 m (sand below the water table), H3 = 2 m (the clay layer, void ratio e = 0.75) — and all three values are used below.

Question 5 (6 + 14 = 20 marks)

Question text not reproduced: the examination questions are © Engineers and Geoscientists BC. Open the official past paper (linked at the top of this page) to read the question, then follow the worked solution below.

(i) Assumptions of elastic (Boussinesq-type) stress theory: the soil is treated as a semi-infinite, homogeneous, isotropic, linearly elastic half-space; it is assumed weightless (only the stress INCREMENT due to the applied load is computed, superposed on the existing in-situ stress); the load acts at/on the surface of the half-space with no other loads present; and the material never yields — stress and strain remain proportional at every load level.

Limitations: real soil is not linearly elastic (stiffness changes with confining stress and strain level, especially as failure is approached); natural deposits are layered and generally get stiffer with depth, not homogeneous; many soils (particularly clays) are anisotropic (different stiffness vertically vs. horizontally), contrary to the isotropic assumption; the theory ignores a rigid layer at finite depth (a real shallow rigid stratum concentrates stress more than the idealised infinite half-space predicts); and it takes no account of footing size, rigidity, or embedment beyond the loaded area itself. Despite these idealisations, field measurements generally agree with Boussinesq-based predictions well enough for routine settlement and stress-distribution design, which is why the method remains standard practice.

sigma_z depth z (down) stress decays with depth horizontal distance from load axis shallow depth mid depth greater depth
Typical variation of vertical stress with depth (left) and with horizontal distance from the load axis at three depths (right), due to a point load — the classic Boussinesq "pressure bulb": narrower and taller near the surface, wider and flatter with depth.

(ii) Given. The loaded area in Figure 2 is a 7 m × 4 m rectangle (5 m + 2 m wide, 1 m + 3 m deep), loaded at q = 100 kPa; point A sits at the internal division of these dimensions — 5 m from one side and 2 m from the other (width-wise), 1 m from one edge and 3 m from the other (length-wise) — so A is a shared corner of four sub-rectangles that together tile the whole loaded area.

A 5 m × 1 m 2 m × 1 m 5 m × 3 m 2 m × 3 m 5 m 2 m 1 m 3 m q = 100 kPa (uniform over whole 7 m × 4 m area)
Figure 2 — rectangular loaded area, split into four sub-rectangles sharing corner A, for superposition.

Find. The increase in vertical stress $\Delta\sigma_z$ at 2.0 m depth below A, by two methods, and a comparison.

Approach. Method 1 (exact): since A is not a corner of the actual loaded rectangle, decompose the area into four rectangles that DO share a corner at A and sum the exact Boussinesq corner-influence factors from the formula sheet. Method 2 (approximate): the formula sheet's approximate formula $\sigma_z=qBL/[(B+z)(L+z)]$ is written for the CENTRE of a B×L rectangle; mirroring the loaded rectangle about corner A produces a $2B\times2L$ rectangle centred exactly on A, so the corner stress equals one quarter of that larger rectangle's centre-formula stress — giving $\sigma_{z,corner}\approx qBL/[(2B+z)(2L+z)]$, applied to each of the same four sub-rectangles.

  1. Method 1 — exact corner superposition. With $z=2$ m, the influence factor $I(m,n)$ (formula sheet, $m=B/z,\,n=L/z$) evaluated for each sub-rectangle: $$I(2.5,0.5)=0.136,\quad I(1,0.5)=0.120,\quad I(2.5,1.5)=0.227,\quad I(1,1.5)=0.194,$$ $$\Delta\sigma_z = q\sum I = 100(0.136+0.120+0.227+0.194) = 100(0.677) \boxed{=\ 67.7\ \text{kPa}}.$$
  2. Method 2 — approximate (2:1-type) corner formula. Applying $\sigma_{z,corner}=qBL/[(2B+z)(2L+z)]$ to the same four sub-rectangles: $$\underbrace{10.4}_{5\times1}+\underbrace{8.3}_{2\times1}+\underbrace{15.6}_{5\times3}+\underbrace{12.5}_{2\times3} \boxed{=\ 46.9\ \text{kPa}}.$$
  3. Compare. The two methods differ by about 30% (67.7 kPa exact vs. 46.9 kPa approximate). The approximate method assumes the load spreads uniformly at a fixed 2(vertical):1(horizontal) slope from the loaded edges in every direction, which understates the stress concentration directly beneath a point close to the centre of mass of the loaded area (as A effectively is here, sitting well inside the 7×4 m footprint) — the exact Boussinesq solution captures that concentration more faithfully. The approximate method's convenience (a single closed-form calculation with no charts or superposition of transcendental influence factors) is traded for reduced accuracy near heavily loaded interior points; it is best reserved for quick preliminary estimates or for points once a filled-in area is small.
Question 5(ii) — final results
QuantityValue
Method 1 (exact Boussinesq superposition)67.7 kPa
Method 2 (approximate, quartered 2:1-type)46.9 kPa
Difference≈ 31% (approximate method lower)