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23-Chem-A1 Process Balances and Chemical Thermodynamics · May 2017

Question 3 of 6: Sensible Heat Lost by a Cooling Flue Gas

Nivaar worked solution (AI-drafted; not reviewed by a licensed engineer)

Notes on this paper

16-Chem-A1, May 2017 — three-hour, open-book examination. The paper is in two parts: Part A (Questions 1–3, process mass & energy balances) and Part B (Questions 4–6, chemical thermodynamics). Candidates answer two questions from each part; all six are worked below as a complete study resource.

Reference texts (this subject). Felder & Rousseau, Elementary Principles of Chemical Processes, 4th ed. (mass & energy balances, combustion, recycle/purge); Smith, Van Ness & Abbott, Introduction to Chemical Engineering Thermodynamics, 8th ed. (fugacity, activity coefficients, generalized correlations, equations of state); property data from the paper's appended Smith–Van Ness tables (App. B critical constants; App. E Lee/Kesler charts).

Question 3: Sensible Heat Lost by a Cooling Flue Gas (Part A)

Question text not reproduced: the examination questions are © Engineers and Geoscientists BC. Open the official past paper (linked at the top of this page) to read the question, then follow the worked solution below.

Given. Mole fractions CO₂ 0.12, H₂O 0.13, O₂ 0.02, N₂ 0.73; heat-capacity coefficients $C_p^\circ = a + bT + cT^2$ (kJ/kmol·K); cool 10 kmol from $T_1=650\ \text{K}$ to $T_2=300\ \text{K}$.

Component$a$$b\times10^{3}$$c\times10^{6}$
CO₂21.3564.27−41.01
H₂O32.490.0813.21
O₂26.0111.76−2.35
N₂29.60−5.1513.19

Find. The sensible heat released, $Q$, on cooling the 10 kmol from 650 K to 300 K.

Approach. Mole-average the polynomial coefficients, integrate $C_p$ over the temperature interval for one kmol, then scale to 10 kmol.

  1. Mixture heat-capacity coefficients. For an ideal-gas mixture the extensive $C_p$ is additive, so the coefficients are mole-weighted sums: $$a_m = \sum y_i a_i = 28.91,\quad b_m = 4.199\times10^{-3},\quad c_m = 6.378\times10^{-6}\ \ (\text{kJ/kmol}\cdot\text{K})$$
  2. Integrate the heat capacity. The sensible heat per kmol between $T_1$ and $T_2$ is $$q = a_m\,\Delta T + \frac{b_m}{2}\left(T_2^2 - T_1^2\right) + \frac{c_m}{3}\left(T_2^3 - T_1^3\right)$$ $$q = 28.91(350) + \tfrac{4.199\times10^{-3}}{2}(3.325\times10^{5}) + \tfrac{6.378\times10^{-6}}{3}(2.4763\times10^{8}) = 10120 + 698 + 526 = 11344\ \text{kJ/kmol}$$
  3. Scale to 10 kmol. The magnitude of heat lost on cooling is $$Q = 10\,q = \boxed{1.134\times10^{5}\ \text{kJ} \approx 113.4\ \text{MJ}}$$
QuantityValue
Mixture $a_m,\ b_m,\ c_m$28.91,  4.199×10⁻³,  6.378×10⁻⁶
Heat per kmol (650→300 K)11 344 kJ/kmol
Heat lost by 10 kmol113.4 MJ