23-Chem-A5 Chemical Plant Design and Economics · December 2019
Nivaar worked solution (AI-drafted; not reviewed by a licensed engineer)
National Exams / EGBC — December 2019 — 16-Chem-A5 Chemical Plant Design and Economics. Three-hour closed-book examination; one aid sheet (both sides) and an approved Sharp/Casio calculator are permitted. Six questions are printed and any five constitute a complete paper (each worth 20 marks); all six are solved below for completeness. The two calculation questions (Q3, Q4) are worked with explicit engineering-economy factors; the four discussion questions (Q1, Q2, Q5, Q6) are answered as structured lists with supporting description, as the paper directs.
Reference texts: M. S. Peters, K. D. Timmerhaus & R. E. West, Plant Design and Economics for Chemical Engineers (5th ed., McGraw-Hill) — profitability measures (rate of return, incremental analysis), straight-line depreciation, after-tax cash flow, and the anatomy of a process/economic study; R. Turton, R. C. Bailie, W. B. Whiting & J. A. Shaeiwitz, Analysis, Synthesis, and Design of Chemical Processes (4th ed., Prentice Hall) — the process flow diagram and its information content, equipment/economics; G. Towler & R. Sinnott, Chemical Engineering Design (Coulson & Richardson Vol. 6, 2nd ed.) — utilities, offsites and storage; O. Levenspiel, Chemical Reaction Engineering (3rd ed.) and H. S. Fogler, Elements of Chemical Reaction Engineering — reactor scale-up. Engineering-economy factors follow the standard notation $(A/P,i,n)$ and $(P/A,i,n)$; as the question specifies straight-line depreciation, that method is used throughout (rather than the Canadian CCA declining-balance system).
Question text not reproduced: the examination questions are © Engineers and Geoscientists BC. Open the official past paper (linked at the top of this page) to read the question, then follow the worked solution below.
Given. Two mutually exclusive projects, 20-year life, straight-line depreciation to zero salvage (100% depreciable), income-tax rate $t=0.52$, before-tax MARR $=12.5\%$. Financial data:
| Quantity | Inorganic Chemicals Plant | Textile Fibers Expansion |
|---|---|---|
| Projected revenue $R$ | $\$33{,}700{,}000$ | $\$30{,}900{,}000$ |
| Total capital investment $P$ | $\$52{,}500{,}000$ | $\$57{,}300{,}000$ |
| Total annual cost $C$ | $\$25{,}100{,}000$ | $\$21{,}500{,}000$ |
| Straight-line depreciation $D=P/20$ | $\$2{,}625{,}000$/yr | $\$2{,}865{,}000$/yr |
Find. The after-tax internal rate of return of each project and of the incremental investment, and hence which project the firm should fund.
Approach. Convert each project to a level after-tax annual cash flow, find each project’s IRR, then — because the projects are mutually exclusive and unequal in size — test the incremental investment against the (after-tax) MARR to decide which to fund.
| Quantity | Inorganic | Textile | Increment |
|---|---|---|---|
| After-tax annual cash flow | $\$5{,}493{,}000$ | $\$6{,}001{,}800$ | $\$508{,}800$ |
| After-tax IRR | 8.36% | 8.38% | 8.54% |
| vs. 6% after-tax MARR | accept | accept | increment justified |
Recommendation: fund the Textile Fibers Plant Expansion — its additional investment earns a return above the firm’s hurdle rate.
Check: the before-tax MARR is converted to an after-tax basis with the common textbook approximation $i_{at}=i_{bt}(1-t)=6\%$, which is consistent with the 6% after-tax hurdle rate used in Q4 of the same paper. If an examiner instead intends the 12.5% to be applied directly to the after-tax cash flows, neither project clears the hurdle; the ranking (Textile > Inorganic by incremental IRR) is unchanged regardless of the basis chosen.