23-Chem-A6 Process Dynamics and Control · May 2014
Question 7 of 8: CSTR with a Second-Order Reaction — Model and Transfer Function
Nivaar worked solution (AI-drafted; not reviewed by a licensed engineer)
Notes on this paper
National Exams / EGBC — May 2014 — 04-Chem-A6 Process Dynamics & Control. Three-hour open-book examination; any non-communicating calculator is permitted. Eight problems are printed and any five constitute a complete paper (each worth 20%); all eight are solved below for completeness. The parts are quantitative throughout — tank and reactor modelling, transfer functions, step/impulse responses, IMC design, Nyquist and Bode stability — and every requested plot (IMC response, Nyquist locus, thermocouple response, Bode diagram) is drawn as a real figure.
Reference texts: D. E. Seborg, T. F. Edgar, D. A. Mellichamp & F. J. Doyle III, Process Dynamics and Control (4th ed., Wiley) — Laplace-domain modelling, transfer functions, feedback stability, frequency response and IMC design; G. Stephanopoulos, Chemical Process Control: An Introduction to Theory and Practice (Prentice Hall) — Nyquist criterion, Bode stability and dead-time systems; D. R. Coughanowr & S. E. LeBlanc, Process Systems Analysis and Control (3rd ed., McGraw-Hill) — first- and second-order tank dynamics, step/impulse response and linearisation of non-linear balances. Standard control conventions (deviation variables; unity valve/sensor gains unless stated) are used throughout.
Problem 7: CSTR with a Second-Order Reaction — Model and Transfer Function (20%)
Given. Isothermal constant-volume CSTR; constant $\rho$ (so the volumetric flow $q=F/\rho$ is constant); second-order kinetics $r_A=k_1 C_A^2$.
Find. (a) the dynamic model and steady-state $C_{As}$; (b) $\delta C_A/\delta C_{A_o}$.
Problem 7: well-mixed isothermal CSTR of constant volume $V$; feed $q,\,C_{A_o}$, effluent $q,\,C_A$, with second-order consumption $r_A=k_1 C_A^2$ throughout the vessel.
Approach. Write an unsteady component-$A$ balance over the well-mixed volume, set the derivative to zero for the steady state, then linearise the non-linear reaction term about $C_{As}$ and Laplace-transform to obtain a first-order transfer function.
(a) Dynamic model. Component-$A$ balance on the constant volume $V$ (in $=$ out $+$ consumed $+$ accumulated), with volumetric flow $q=F/\rho$: $$\boxed{V\dfrac{dC_A}{dt}=q\,(C_{A_o}-C_A)-V k_1 C_A^{2}}.$$ The out-flow term uses the well-mixed effluent concentration $C_A$; the reaction removes $k_1C_A^2$ per unit volume.
Steady state. Set $dC_A/dt=0$: $q(C_{A_o,s}-C_{As})-Vk_1C_{As}^2=0$, i.e. $Vk_1C_{As}^2+qC_{As}-qC_{A_o,s}=0$. Solving the quadratic (positive root): $$\boxed{C_{As}=\dfrac{-q+\sqrt{q^{2}+4Vk_1 q\,C_{A_o,s}}}{2Vk_1}}.$$
Linearise the reaction term. Expanding $k_1C_A^2$ about $C_{As}$: $k_1C_A^2\approx k_1C_{As}^2+2k_1C_{As}\,(C_A-C_{As})$. In deviation variables $C_A'=C_A-C_{As}$, $C_{A_o}'=C_{A_o}-C_{A_o,s}$ the balance becomes $$V\dfrac{dC_A'}{dt}=q\,(C_{A_o}'-C_A')-2Vk_1C_{As}\,C_A'.$$
Collect into first-order form. $V\dot C_A'+(q+2Vk_1C_{As})C_A'=q\,C_{A_o}'$. Dividing by $(q+2Vk_1C_{As})$ gives $\tau\dot C_A'+C_A'=K C_{A_o}'$ with $$\tau=\dfrac{V}{q+2Vk_1C_{As}},\qquad K=\dfrac{q}{q+2Vk_1C_{As}}.$$
(b) Transfer function. Laplace-transforming, $$\boxed{\dfrac{\delta C_A(s)}{\delta C_{A_o}(s)}=\dfrac{K}{\tau s+1}=\dfrac{q}{V s+\big(q+2Vk_1C_{As}\big)}}.$$ It is a first-order lag; the gain $K=q/(q+2Vk_1C_{As})<1$ because the reaction consumes part of any inlet-concentration change, and the reaction shortens $\tau$ below the pure residence time $V/q$.
“Mass flowrate $F$” with constant density is converted to a constant volumetric flow $q=F/\rho$ for the concentration (mol per volume) balance. If one prefers to keep $F$ throughout, replace every $q$ above by $F/\rho$; the structure and conclusions are unchanged.