23-Chem-B4 Biochemical Engineering · December 2014
Question 2 of 5: Immobilized-Enzyme Packed-Bed Column — Specific Surface Area and Effective Diffusivity
Nivaar worked solution (AI-drafted; not reviewed by a licensed engineer)
Notes on this paper
National Exam 04-Chem-B4, Biochemical Engineering — Dec 2014. 3 hours, Closed-Book Exam
(any non-communicating calculator permitted). Per the exam notes, FIVE (5) questions constitute a
complete paper and all five must be answered; most require a short-essay-format answer.
Find. (a) The specific external surface area α of the packed bed, in cm-1;
(b) the effective substrate diffusivity De inside the 1 mm bead, in m²/s.
Approach. (a) Get the packed-bed volume from column geometry and the total particle
volume from mass/density; a sphere's surface-to-volume ratio 6/dp then converts particle volume
directly to total particle surface area, which is divided by bed volume for α. (b) Rearrange the
observable Thiele modulus $\phi_{obs}=(V_p/S_p)\sqrt{r_{obs}/(D_eS_0)}$ — built from the OBSERVED
(measured) rate rather than an intrinsic rate constant, so it needs no separate kinetic-constant estimate
— for De.
Fig. 2 — immobilized-enzyme packed-bed column: the specific surface area α
converts particle surface area into an area-per-unit-reactor-volume basis.
(a) Packed-bed volume from column geometry.
$$V_{bed}=\frac{\pi}{4}D_{col}^2H=\frac{\pi}{4}(0.20)^2(2.0)=\boxed{0.06283\ \text{m}^3}$$
Total particle volume from the mass/density basis.
$$V_p=\frac{m}{\rho_p}=\frac{18}{1500}=0.01200\ \text{m}^3$$
Total particle surface area via the sphere identity area/volume = 6/dp. For a
sphere, $S_p/V_p=(\pi d_p^2)/(\tfrac{\pi}{6}d_p^3)=6/d_p$, so the TOTAL surface area of all particles follows
directly from their total volume without needing the particle count individually:
$$S_{p,tot}=V_p\times\frac{6}{d_p}=0.01200\times\frac{6}{0.002}=\boxed{36.0\ \text{m}^2}$$
(equivalently, N=Vp/(πdp³/6)≈2.86×106 particles, each of
area πdp²≈1.257×10-5 m².)
Specific surface area α = total particle area / bed volume.
$$\alpha=\frac{S_{p,tot}}{V_{bed}}=\frac{36.0}{0.06283}=572.9\ \text{m}^{-1}
=\boxed{5.73\ \text{cm}^{-1}}$$
(b) Convert the observed rate to SI. 1 µmol·cm-3·min-1
numerically equals 1 mol·m-3·min-1 (the 10-6 mol/µmol and
10-6 m³/cm³ factors cancel), so:
$$r_{obs}=\frac{200}{60}=3.333\ \text{mol}\cdot\text{m}^{-3}\cdot\text{s}^{-1}$$
Characteristic diffusion length of the sphere.
$$\frac{V_p}{S_p}=\frac{R}{3}=\frac{0.5\times10^{-3}}{3}=1.667\times10^{-4}\ \text{m}$$
Rearrange the observable Thiele modulus for De. Squaring
$\phi_{obs}=(V_p/S_p)\sqrt{r_{obs}/(D_eS_0)}$ and solving for De:
$$D_e=\frac{(V_p/S_p)^2\,r_{obs}}{S_0\,\phi_{obs}^2}
=\frac{(1.667\times10^{-4})^2(3.333)}{(100)(4.3)^2}=\boxed{5.01\times10^{-11}\ \text{m}^2/\text{s}}$$
This is a plausible effective diffusivity for a substrate inside a gel-type immobilization matrix (typically
10-10–10-11 m²/s, well below the free-solution value).