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23-Chem-B4 Biochemical Engineering · May 2017

Question 1 of 5: Fed-Batch Culture — Definition, Advantages & First-Principles Proof that μ=D at Quasi-Steady-State

Nivaar worked solution (AI-drafted; not reviewed by a licensed engineer)

Notes on this paper

National Exam 16-Chem-B4, Biochemical Engineering — May 2017. 3 hours, Closed-Book Exam (any non-communicating Casio or Sharp calculator permitted). Per the exam notes, FIVE (5) questions constitute a complete paper and all five must be answered; most require a short-essay-format answer, and clarity/organization of the answer are explicitly marked.

Reference texts: Shuler & Kargi, Bioprocess Engineering: Basic Concepts, 2nd ed.; Bailey & Ollis, Biochemical Engineering Fundamentals, 2nd ed.; Madigan et al., Brock Biology of Microorganisms, 13th ed.

Question 1: Fed-Batch Culture — Definition, Advantages & First-Principles Proof that μ=D at Quasi-Steady-State (20 marks)

Question text not reproduced: the examination questions are © Engineers and Geoscientists BC. Open the official past paper (linked at the top of this page) to read the question, then follow the worked solution below.

Definition. Fed-batch culture is a mode of bioreactor operation in which one or more growth-limiting nutrients (the feed, at flow rate F and concentration SF) are added to the vessel continuously or intermittently after an initial batch phase, while nothing is withdrawn — the working volume V(t) therefore increases monotonically with time until the vessel is full or the run is terminated (unlike a chemostat, which has a matching outflow Fout=F that holds V constant). It sits between simple batch culture (fixed V, all nutrient charged at t=0) and true continuous culture (fixed V, F in = F out) as a third distinct mode of operation.

V(0) = V₀V(t) ↑ (t > 0)F, Sᶠ (feed)no outflowX(t), S(t), V(t)well-mixed
Fig. 1 — fed-batch bioreactor: continuous feed F in, zero outflow, so the working volume V(t) climbs monotonically from V₀ while the vessel remains well mixed.

Advantages. Feeding the limiting substrate slowly rather than charging it all at t=0 gives the operator direct control over the substrate concentration S(t) inside the vessel, which unlocks several industrially important benefits:

Approach to the proof. Because a fed-batch bioreactor has an inflow but no outflow, unsteady total mass balances on volume and on biomass are written first (exact, no assumption), then the quasi-steady-state (QSS) condition is applied to the resulting rate equation.

  1. Unsteady volume balance. With feed flow rate F in and nothing removed, $$\frac{dV}{dt}=F$$ Define the instantaneous dilution rate exactly as in a chemostat, D≡F/V, so $$\frac{dV}{dt}=DV$$
  2. Unsteady total-biomass balance. No cells enter in the feed and none leave, so the only change in total biomass XV is growth at the specific rate μ: $$\frac{d(XV)}{dt}=\mu XV$$
  3. Expand the product rule and substitute D. Differentiating XV by parts, $$\frac{d(XV)}{dt}=X\frac{dV}{dt}+V\frac{dX}{dt}=XDV+V\frac{dX}{dt}$$ Setting this equal to μXV from Step 2 and dividing through by V (V≠0) gives an exact identity, true at every instant regardless of how F(t) is programmed: $$\boxed{\frac{dX}{dt}=X(\mu-D)}$$
  4. Apply the quasi-steady-state assumption. In a properly operated fed-batch run the feed is manipulated (classically, exponentially: F(t)=DsetV(t)) so that the limiting substrate concentration S is brought to, and held at, an essentially constant low level after the initial transient. Because Monod kinetics makes μ a function of S alone (μ=μmaxS/(Ks+S)), holding S constant holds μ constant too, and the biomass concentration X settles to an essentially time-invariant value: $$\frac{dX}{dt}\approx 0 \quad\text{(QSS)}$$
  5. Combine Steps 3 and 4. Substituting dX/dt=0 into the exact identity X(μ−D)=dX/dt and noting X≠0, $$0=X(\mu-D)\;\Rightarrow\;\boxed{\mu=D}$$ This is the operating principle behind exponential fed-batch feeding: to run the culture at a chosen growth-rate set-point μset, program the feed as F(t)=μset⋅V(t), which by construction keeps D=F/V=μset at every instant, so the QSS condition μ=D is satisfied by design rather than by coincidence.
ResultStatement
Exact (no QSS) identitydX/dt = X(μ − D), D≡F/V
QSS conditiondX/dt ≈ 0 (X essentially constant once feed tracks growth)
Proof resultμ = D at quasi-steady state
Design consequenceProgram F(t) = μset·V(t) to hold μ at a chosen set-point
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