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23-Chem-B5 Pulp and Paper Technology · December 2017

Question 2 of 4: ECF Bleach Plant — DEopDEpD Sequence, Effluent Parameters, Oxygen Delignification, ClO 2 Generation & Heat Recovery

Nivaar worked solution (AI-drafted; not reviewed by a licensed engineer)

Notes on this paper

National Exam 16-Chem-B5, Pulp and Paper Technology — December 2017. 3 hours, OPEN BOOK exam (Casio or Sharp approved calculators only). Per the exam notes, any THREE of the four questions constitute a complete paper (only the first three as they appear in the candidate's answer book are marked), and in Question 2 only the first two of parts (d)–(f) as answered would normally be marked; for completeness this solution answers all FOUR questions in full, including all three optional parts of Question 2. Most parts require an essay-format answer — clarity and organization of the answer are explicitly marked.

Reference texts: Smook (rev. Kocurek), Handbook for Pulp & Paper Technologists, 4th ed.; Biermann, Handbook of Pulp and Paper Technology, 2nd ed.; Perry's Chemical Engineers' Handbook, 9th ed. (generic mass/energy-balance and heat-exchanger methods).

Question 2: ECF Bleach Plant — DEopDEpD Sequence, Effluent Parameters, Oxygen Delignification, ClO2 Generation & Heat Recovery (a)–(c) 10 marks each, (d)–(f) 20 marks each

Question text not reproduced: the examination questions are © Engineers and Geoscientists BC. Open the official past paper (linked at the top of this page) to read the question, then follow the worked solution below.

(a) DEopDEpD bleach sequence

D = chlorine dioxide (ClO2) delignification/brightening stage; E = alkaline extraction stage (NaOH washes out chlorinated/oxidized lignin fragments solubilized by the preceding D stage); the subscripts o and p denote that the extraction stage is reinforced with oxygen (o) and hydrogen peroxide (p) respectively — i.e. "Eop" is a single alkaline-extraction vessel dosed with both O2 and H2O2 to add extra delignifying/brightening power to that stage without a separate tower. Reading the sequence left to right: D0 (first ClO2 stage) → Eop (O2/H2O2-reinforced extraction) → D1 → Ep (peroxide-reinforced extraction) → D2 (final brightening stage) — a standard 5-stage ECF (elemental-chlorine-free) sequence.

Check
As printed, the source labels D1 the "fourth" stage; by the standard 5-token reading of D–Eop–D–Ep–D (D0, Eop, D1, Ep, D2), D1 is conventionally the third stage and D2 is the fifth (last), which is consistent with the source's own "last stage (D2)" label. This is treated as a minor ordinal slip in the source text; the technical content requested — typical conditions of D0, D1 and D2 — is answered using the standard industry stage identities below, independent of the exact position count.
StageTemp.ConsistencypHKappa FactorResidence time
D0 (feed: 25 Kappa)50–60°C10–12% (MC) or 30–35% (HC)2–3 (acidic)0.20–0.2530–60 min
D170–75°C10–12%3.5–4.5≈0.3–0.8 (on the Eop Kappa)120–180 min
D2 (final/brightening)70–75°C10–12%4–5≤0.10 (small trim dose)120–180 min

The chemical dose in every D stage is set from the Kappa Factor relation, $$\%\text{Cl}_2\text{-equivalent charge (on O.D. pulp)}=\text{Kappa Factor}\times\text{Kappa Number entering that stage}$$ so for the D0 stage on this 25-Kappa feed, a KF of 0.20 corresponds to a charge of about $0.20\times25=5.0\%$ Cl2-equivalent, i.e. $5.0\times10/2.63\approx19$ kg ClO2 per O.D. tonne of pulp (dividing by the 2.63 available-chlorine factor). D1/D2 doses are much smaller because the Kappa Number entering them has already been cut by D0 and Eop: typically ≈5–10 kg ClO2/ODMT in D1 (with a little NaOH for pH control) and ≈2–5 kg ClO2/ODMT in D2.

(b) Effluent parameters: BOD, AOX, Toxicity, TSS

BOD (biochemical oxygen demand) is measured by the standard 5-day BOD5 test: a diluted, microbially-seeded sample is incubated in the dark at 20°C, and BOD is the drop in dissolved oxygen over 5 days (mg O2/L). AOX (adsorbable organic halogens) is measured by adsorbing the organic content of a sample onto activated carbon, then combusting the carbon and measuring the total halide released (predominantly chloride) by microcoulometric titration, reported as mg Cl/L. Toxicity is measured by standardized bioassays — acute 96-hour LC50 tests (e.g. rainbow trout, Daphnia) and chronic (sub-lethal, growth/reproduction) tests on whole final effluent, per regulatory protocols (e.g. Environment Canada EPS methods). TSS (total suspended solids) is measured gravimetrically: a known volume is filtered through a pre-weighed glass-fibre filter, the residue dried at 103–105°C and weighed, TSS reported in mg/L.

A kraft bleach plant is historically the mill's largest contributor to all four parameters: chlorinated and oxidized lignin/carbohydrate fragments solubilized in the D and E filtrates add BOD (biodegradable organics) and, where any elemental chlorine or hypochlorite is used, AOX and chlorinated-phenolic toxicity; fibre fines lost in washing add TSS. Modern ECF sequences (ClO2 only, no Cl2/hypochlorite) cut AOX and toxicity dramatically relative to older chlorine-bleaching technology, though BOD and TSS loads remain significant simply from the volume of organics solubilized.

Before discharge, combined mill effluent (bleach plant plus other mill streams) is routed through primary clarification (settling/DAF to remove TSS and fibre), then secondary biological treatment — typically an aerated stabilization basin or activated-sludge system — where microorganisms consume the biodegradable organic load (reducing BOD by roughly 90%+ and further degrading a portion of the AOX and toxic compounds), before final discharge under a regulatory permit that sets BOD, TSS, AOX, toxicity, pH and temperature limits.

(c) Oxygen delignification technologies

Two reactor configurations are in commercial use, distinguished by pulp consistency: (1) medium-consistency (MC) O2 delignification, at 10–14% consistency, where the pumpable pulp slurry is passed through a dedicated high-shear MC mixer that mechanically disperses gaseous O2 into fine bubbles throughout the fibre suspension before the mixture enters an upflow/downflow pressurized tower reactor (85–100°C, 600–700 kPa O2 partial pressure, NaOH charge); and (2) high-consistency (HC) O2 delignification, at 25–30% consistency, where pulp is first fluffed (defibrated to a low-density, high-surface-area mass) and O2 gas plus steam are then blown directly into the fluffed pulp in a reactor vessel — mixing/diffusion here relies on the pulp's own high porosity and large exposed fibre surface area rather than mechanical shear. Both processes achieve broadly comparable delignification, typically 35–50% Kappa reduction; the practical ceiling (rather than any equipment limitation) is set by cellulose/carbohydrate degradation — beyond about 50% delignification, O2 radical attack increasingly targets cellulose rather than residual lignin, causing unacceptable pulp-strength (viscosity) loss, so mills deliberately stop short of that point and let the bleach plant proper (D/E stages) complete delignification to final brightness.

(d) Chlorine dioxide generation (SVP/HP-type generator)

1) Reducing agent: hydrogen peroxide (H2O2) is the reducing agent — it reduces chlorate (Cl(V)) to chlorine dioxide (Cl(IV)) under the strongly acidic conditions maintained by sulphuric acid, while itself being oxidized to O2 (visible as the O2 product in the stated net reaction).

2) Typical generator concentrations: NaClO3 maintained near 600–700 g/L; H2SO4 maintained very strong, roughly 700–900 g/L (generator liquor operates below pH≈1, essential for reasonable ClO2 generation rate and selectivity); Na2SO4 by-product is kept near its solubility limit in the strongly acidic, high-ionic-strength liquor so that it continuously crystallizes out as it forms.

3) Typical feed strengths: NaClO3 solution fed at roughly 600–700 g/L; H2SO4 fed as concentrated (93–98%) acid; H2O2 fed as a 35–50% aqueous solution (50% in this problem).

4) By-product separation: because Na2SO4 has low solubility in the strongly acidic, high-salinity generator liquor, it precipitates continuously as fine crystals ("saltcake") and is removed from the recirculating generator liquor by a vacuum filter or centrifuge.

5) Typical use: the by-product sodium sulphate (saltcake) is fed directly to the kraft recovery boiler as makeup sodium and sulphur — it is reduced to Na2S in the furnace exactly like the mill's normal Na2SO4→Na2S recovery chemistry — recycling it back into the kraft chemical cycle to replace sodium/sulphur losses rather than discarding it.

6) Calculation — see below.

Given.

QuantityValue
ClO2 plant production42 t/day
Plant (chemical) efficiency92.5%
ClO2 solution flow2000 L/min
Absorption water temperature6°C

Find. ClO2 solution concentration; 50% H2O2 flowrate (kg/min); 6.2 M NaClO3 solution flowrate (L/min).

Approach. The 42 t/day rating is the ClO2 the plant makes; dividing by the 2000 L/min absorber flow gives the concentration. "92.5% efficient" is the generator's chemical efficiency — the fraction of chlorate fed that ends up as ClO2 (the rest is lost to side reactions) — so the chlorate feed is the stoichiometric 1:1 (2 NaClO3 → 2 ClO2) requirement divided by 0.925, and the peroxide follows the reaction's 2 NaClO3 : 1 H2O2 ratio on the chlorate actually consumed.

Check
Reading "42 t/day plant (92.5% efficient)" as a nameplate capacity run at 92.5% of rating (38.85 t/day) would instead give 13.49 g/L, 13.61 kg/min H2O2 and 64.5 L/min chlorate. That reading applies the efficiency to the output while feeding exactly stoichiometric reagents, which is not what generator efficiency means, so the chemical- efficiency reading is used here.
  1. ClO2 production and solution concentration. $$\dot m_{ClO_2}=\frac{42{,}000}{1440}=29.17\ \text{kg/min}\qquad C_{ClO_2}=\frac{29.17\times1000}{2000}=\boxed{14.58\ \text{g/L}}$$
  2. NaClO3 solution flowrate. M(ClO2)=67.45, M(NaClO3)=106.45: $$n_{ClO_2}=\frac{29{,}167}{67.45}=432.4\ \text{mol/min}\ \Rightarrow\ n_{NaClO_3}=\frac{432.4}{0.925}=467.5\ \text{mol/min}$$ $$\dot V_{NaClO_3}=\frac{467.5}{6.2}=\boxed{75.4\ \text{L/min}}\qquad(\dot m=467.5\times106.45/1000=49.8\ \text{kg/min})$$
  3. H2O2 flowrate. M(H2O2)=34.016; 1 mol H2O2 per 2 mol NaClO3: $$n_{H_2O_2}=467.5/2=233.7\ \text{mol/min}\ \Rightarrow\ \dot m_{H_2O_2,100\%}=233.7\times34.016/1000=7.95\ \text{kg/min}\ \Rightarrow\ \dot m_{50\%\ soln}=7.95/0.50=\boxed{15.90\ \text{kg/min}}$$ (The bare stoichiometric minimum, on the ClO2 made, would be 14.71 kg/min.)
QuantityValue
ClO2 solution concentration14.58 g/L
50% H2O2 feed15.90 kg/min
6.2 M NaClO3 feed75.4 L/min (49.8 kg/min)

(e) Oxygen delignification & D0 stage sizing

Given.

QuantityValue
Bleached pulp production1500 ADMT/day (softwood)
Digester yield45% (on O.D. wood)
Kappa Number entering O2 delig.27.5
O2 delignification42%
D0 Kappa Factor0.195
ClO2 solution strength10.5 g/L
Chip moisture44% (total mass)
Reject rate3.25 ADMT/day
Bleaching yield loss5%

Find. (1) ClO2 solution flow to D0 (L/min); (2) wet wood supply required (t/day); (3) purpose/equipment for washing before and after O2 delignification.

Approach. The D0 Kappa Factor applies to the Kappa Number the pulp carries INTO D0, i.e. after the 42% O2-stage delignification has already reduced the 27.5 digester Kappa. Convert the resulting Cl2-equivalent dose to actual ClO2 mass via the 2.63 available-chlorine factor, and scale by the O.D. production rate. For the wood supply, work BACKWARD from the 1500 ADMT/d bleached product through the stated bleaching yield loss and reject rate to the brown stock (digester) O.D. pulp output, then through the digester yield and chip moisture to wet wood.

  1. Kappa Number entering D0. $$\kappa_{D_0,in}=27.5\times(1-0.42)=\boxed{15.95}$$
  2. ClO2 dose and D0 solution flow. Cl2-equivalent charge $=\text{KF}\times\kappa=0.195\times15.95=3.110\%=31.10\ \text{kg Cl}_2\text{-eq/tonne}$; dividing by the 2.63 available-chlorine factor for ClO2: $$\text{ClO}_2\ \text{dose}=31.10/2.63=11.83\ \text{kg/ODMT}$$ O.D. production $=1500\times0.90=1350\ \text{ODMT/day}$ (90% AD convention), so $$\dot m_{ClO_2}=11.83\times1350=15{,}965\ \text{kg/day}=11.09\ \text{kg/min}$$ $$\dot V_{D_0}=\frac{11.09\times1000}{10.5}=\boxed{1056\ \text{L/min}}$$
  3. Wood supply (working backward from final production). Pulp entering the bleach plant, before the stated 5% bleaching yield loss: $$1500/(1-0.05)=1578.9\ \text{ADMT/d}$$ Adding the 3.25 ADMT/d reject rate (brown stock produced, including the material later screened out as rejects): $$1578.9+3.25=1582.2\ \text{ADMT/d}=1582.2\times0.90=1424.0\ \text{O.D. t/d brown stock}$$ Dividing by the 45% digester yield gives O.D. wood, then dividing by (1−chip moisture) gives wet wood: $$\text{O.D. wood}=1424.0/0.45=3164\ \text{t/d}\qquad \text{Wet wood}=3164/(1-0.44)=\boxed{5651\ \text{wet t/day}}$$
QuantityValue
Kappa Number entering D015.95
ClO2 solution flow to D01056 L/min
Wet wood supply required5651 t/day

(3) Washing before and after O2 delignification. Washing BEFORE the stage removes the dissolved lignin, spent cooking chemical and inorganic carryover from the digester/brown-stock system, protecting the O2 stage's own chemical (NaOH) economy from being consumed by residual digester alkali demand. Washing AFTER the stage removes the additional lignin and organics solubilized during O2 delignification itself, keeping that lignin-rich filtrate on the brown-stock (kraft recovery) side of the mill rather than allowing it to carry forward into the bleach plant proper, where it would otherwise inflate D/E-stage chemical consumption and effluent (BOD/AOX) load. Typical washing equipment is rotary vacuum drum washers, pressure diffusion washers, or (increasingly, for better displacement efficiency at lower dilution) wash presses; the removed component is dissolved organic solids (lignin fragments plus residual cooking/O2-stage chemicals), and the recovered filtrate is returned to the brown-stock washing/evaporator system for chemical recovery in the recovery boiler rather than sent to effluent treatment.

(f) ClO2 preheat heat exchanger & D1-stage steam savings

1) Filtrate/water sources: the most practical source is hot washer filtrate already generated on-site — typically E-stage (extraction) filtrate, as used in this problem, since it is discharged at a useful temperature (70–80°C) and would otherwise be partly wasted to sewer; D2-stage filtrate or general mill hot process water are secondary options.

2) Design criteria: size the exchanger for the design heat duty at the required flow/ΔT; select heat-transfer area/approach temperature to balance capital cost against recovered energy; ensure the ClO2 side never exceeds a safe temperature (ClO2 solution should stay well below the temperature at which dissolved ClO2 gas evolution/decomposition becomes a hazard, which is exactly why the target outlet here is a modest 43°C rather than higher); design for fouling resistance (filtrate carries fines and scale-forming ions) with adequate cleaning access; and use corrosion-resistant construction (see metallurgy, below).

3) Safety parameters: ClO2 is a toxic, thermally unstable gas that can decompose explosively if concentrated and/or heated beyond safe limits, so the exchanger and associated piping must be designed and interlocked to prevent local hot-spots, vapour pocket formation, or loss of dilution water flow; adequate ventilation, ClO2 gas detection, and pressure-relief provisions are required in the exchanger's immediate area.

4) Metallurgy: yes — both process streams (ClO2 solution and chlorinated E-stage filtrate) are highly corrosive (acidic, chloride/chlorine-dioxide-bearing); ordinary carbon steel or standard 300-series stainless steel will pit and corrode rapidly in this service, so the exchanger must be built from a corrosion-resistant material such as titanium or a high-nickel/chromium alloy suited to ClO2/chloride duty.

Given.

QuantityValue
Incoming E1 Kappa Number6.0
D1 Kappa Factor0.76
Bleach plant production (iii)800 ADMT/day
D1 operating consistency11% AD
ClO2 solution strength10.5 g/L
Stock temp. from preceding extraction60°C
D1 mixer target temp.75°C
ClO2 in / out of HX4°C / 43°C
E1 filtrate in76°C

Find. (vi) ClO2 solution flow to D1; (vii) E1 filtrate flow; (viii) E1 filtrate temperature out; (ix) steam savings.

Approach. Size the D1 ClO2 dose exactly as in part (e), using KF=0.76 on the 6.0 incoming Kappa Number. The E1 filtrate doubles as the D1 mixer's own dilution water (needed to bring the O.D. pulp to the stated 11% AD operating consistency) — its flow is therefore fixed by that mass balance, not a free design choice — and it is this same filtrate stream that is routed through the ClO2 preheat exchanger before being added to the mixer. An energy balance on the exchanger (heat lost by filtrate = heat gained by ClO2 solution, Cp≈4.18 kJ/kg·°C for both dilute streams) then gives the filtrate's outlet temperature, and the heat duty recovered is exactly the steam load that would otherwise have been needed to warm the ClO2 stream from 4°C to 43°C by direct steam injection — converted to an equivalent steam mass using the latent heat of the mill's low-pressure steam supply.

Check
Two engineering assumptions are made, consistent with the exam's own Note 1: (i) the ClO2 solution and E1 filtrate are both treated as dilute aqueous streams with ρ≈1.0 kg/L and Cp≈4.18 kJ/kg·°C; (ii) the steam displaced is valued at its latent heat of vaporization, taken as 2257 kJ/kg (saturated steam ≈100°C, a typical low-pressure mixer injection condition) — not otherwise stated in the source.
  1. (vi) D1 ClO2 dose and solution flow. $$\%\text{Cl}_2\text{-eq}=0.76\times6.0=4.56\%=45.6\ \text{kg/t}\ \Rightarrow\ \text{ClO}_2=45.6/2.63=17.34\ \text{kg/ODMT}$$ O.D. production $=800\times0.90=720\ \text{ODMT/day}=500.0\ \text{kg O.D. pulp/min}$: $$\dot m_{ClO_2}=17.34\times720/1440=8.669\ \text{kg/min}\ \Rightarrow\ \dot V_{D_1}=\frac{8.669\times1000}{10.5}=\boxed{825.6\ \text{L/min}}$$
  2. (vii) E1 filtrate flow (= D1 dilution water at 11% AD). Total The consistency is stated on an air-dry basis, so it is applied to the air-dry pulp flow, $800\ \text{ADMT/day}=555.6\ \text{kg AD pulp/min}$. Total stock flow at 11% AD $=555.6/0.11=5050.5\ \text{kg/min}$, and the water (filtrate) portion is the difference: $$\dot m_{filtrate}=5050.5-555.6=\boxed{4495\ \text{kg/min}}\ (\approx\text{L/min})$$
  3. HX heat duty. With the ClO2 solution mass flow ≈825.6 kg/min (ρ≈1.0): $$Q=825.6\times4.18\times(43-4)=\boxed{134{,}600\ \text{kJ/min}}$$
  4. (viii) E1 filtrate outlet temperature. Energy balance on the exchanger, filtrate loses what the ClO2 solution gains: $$\Delta T_{filtrate}=\frac{Q}{\dot m_{filtrate}\times Cp}=\frac{134{,}600}{4495\times4.18}=7.16\,{}^{\circ}\text{C}$$ $$T_{filtrate,out}=76-7.16=\boxed{68.8\,{}^{\circ}\text{C}}$$
  5. (ix) Steam savings. The HX duty is heat that steam no longer has to supply directly at the D1 mixer; converting to an equivalent mass of steam at hfg=2257 kJ/kg: $$\dot m_{steam,saved}=\frac{134{,}600}{2257}=\boxed{59.6\ \text{kg/min}}$$
QuantityValue
(vi) ClO2 solution flow to D1825.6 L/min
(vii) E1 filtrate flow required4495 kg/min
(viii) E1 filtrate outlet temperature68.8°C
(ix) Steam savings59.6 kg/min