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16-Civ-A1 Elementary Structural Analysis · December 2017

Question 1 of 8: Classify each structure: unstable, determinate or indeterminate

Nivaar worked solution (AI-drafted; not reviewed by a licensed engineer)

Notes on this paper

Paper format. National Exams, 16-Civ-A1 Elementary Structural Analysis, December 2017, 3 hours, closed book (approved Sharp or Casio calculator only). A complete paper is six questions: candidates answer all of Q1–Q5 and exactly one of Q6, Q7 or Q8. All eight questions are worked below — Q6, Q7 and Q8 each in full — so the set is a complete study resource. Marks: Q1 [6], Q2–Q5 [18 each], Q6–Q8 [22 each].

Reference texts: R.C. Hibbeler, Structural Analysis (10th ed., Pearson) — determinacy & stability (Ch. 2), method of joints/sections (Ch. 3), shear & moment diagrams (Ch. 4), deflections by virtual work (Ch. 8–9), influence lines (Ch. 6), slope–deflection and moment distribution (Ch. 11–12); A. Kassimali, Structural Analysis (6th ed., Cengage) — compound (Gerber) beams, internal hinges and condition equations, indeterminate frames. Sign convention: sagging bending moment positive (tension on the underside); truss forces tension (T) positive, compression (C) negative.

Reading the exam figures. Every support, member and load below was read directly from the printed figures. The Q4(b) truss carries a stray “3 m” label that is the perpendicular spacing between the two parallel chords (confirmed below), and the Q8 frame carries a stray “4.8 m” dimension that is not a load — it is the offset from the beam down to the lower dimension line (the columns are 4 m, stated on both outer columns).

Question 1 — Classify each structure: unstable, determinate or indeterminate [6]

Question text not reproduced: the examination questions are © Engineers and Geoscientists BC. Open the official past paper (linked at the top of this page) to read the question, then follow the worked solution below.

Approach. For beam/frame assemblies use $D = (3m + r) - (3n + c)$ ($m$ members, $n$ joints, $r$ reaction components, $c$ released condition equations — one per internal hinge in a beam line). For a beam line this reduces to $D = r - (3 + c)$. For a pin-jointed truss use $D = (m + r) - 2n$. Then $D=0$ & stable ⇒ determinate; $D>0$ ⇒ indeterminate to degree $D$; a reaction/member set that cannot resist every equilibrium mode is unstable regardless of the count.

Structure (a) — Statically determinate

whinges
Beam: two rollers + fixed end, two internal hinges

Supports: two rollers ($1+1$) and a fixed end ($3$), so $r=5$. There are two internal hinges (both circle symbols — the “typical hinge” note labels the symbol), giving $c=2$ condition equations. $D=r-(3+c)=5-3-2=\boxed{0}$: determinate. One horizontal restraint (the fixed end) plus five reactions and two hinges leave the beam just-rigid.

Structure (b) — Indeterminate — degree 5

ww
Single-bay frame with an interior beam; pin + fixed bases

Rigid frame: $m=6$ members, $n=6$ joints; supports pin ($2$) + fixed ($3$) ⇒ $r=5$, no internal hinge ($c=0$). $D=3m+r-3n-c=18+5-18-0=\boxed{5}$. Equivalently the closed upper cell is internally $3^{\circ}$ indeterminate and the reactions carry $5-3=2$ external redundants ($3+2=5$).

Structure (c) — Indeterminate — degree 1

w
L-bent (rigid): two rollers under the beam, pin at top of the riser

One rigid bent body; two rollers ($1+1$) under the beam and a pin ($2$) at the top of the right riser give $r=4$, no internal hinge. $D=r-3=4-3=\boxed{1}$. The pin supplies horizontal restraint, so the bent is stable with one redundant.

Structure (d) — Indeterminate — degree 2

ww
Two rigid bents joined by an internal hinge; pin + roller + fixed

Members $m=4$, joints $n=5$; supports pin ($2$) + roller ($1$) + fixed ($3$) ⇒ $r=6$, one internal hinge ⇒ $c=1$. $D=3m+r-3n-c=12+6-15-1=\boxed{2}$.

Structure (e) — Statically determinate

Bowstring truss, pin + roller

Counting all bars (four top chords, two bottom chords, three verticals and four fan diagonals from the two supports down to the lower nodes) gives $m=13$; joints $n=8$; $r=3$. $D=m+r-2n=13+3-16=\boxed{0}$ — determinate, with complete triangulation (no mechanism).

Structure (f) — Indeterminate — degree 1

House-frame truss with an X-braced lower panel, pin + roller

Roof triangle plus a square panel carrying both diagonals: $m=8$ ($2$ rafters, top tie, two sides, bottom chord, two crossing diagonals), $n=5$, $r=3$. $D=m+r-2n=8+3-10=\boxed{1}$ — the second panel diagonal is the internal redundant.

Structure(a)(b)(c)(d)(e)(f)
ClassificationDeterminateIndet. 5°Indet. 1°Indet. 2°DeterminateIndet. 1°
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