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16-Civ-A4 Geotechnical Materials and Analysis · December 2014

Question 6 of 6: CU triaxial strength from CD effective parameters

Nivaar worked solution (AI-drafted; not reviewed by a licensed engineer)

Notes on this paper

Paper format: National Examinations (Engineers Canada / PEO), 98-Civ-A4 Geotechnical Materials and Analysis, December 2014. Closed book, 3 hours, 100 marks. Six questions — answer all. Charts and equations supplied at the back of the paper.

Reference texts: Das & Sobhan, Principles of Geotechnical Engineering (9th ed.), Cengage; Holtz, Kovacs & Sheahan, An Introduction to Geotechnical Engineering (2nd ed.), Pearson; Craig’s Soil Mechanics (Knappett & Craig, 8th ed.), CRC Press.

Check: The label inside Figure 3 prints “$k = 2.0 \times 10^{5}$ m/s”, which is physically impossible (200 km/s). The text of Question 5(b) prints $k = 2.0 \times 10^{-5}$ m/s, so the figure label has lost its minus sign and $2.0 \times 10^{-5}$ m/s is used throughout Question 5.

Question 6: CU triaxial strength from CD effective parameters (Value: 20 marks)

Question text not reproduced: the examination questions are © Engineers and Geoscientists BC. Open the official past paper (linked at the top of this page) to read the question, then follow the worked solution below.

Given. Effective strength parameters (unique to the soil) $c' = 10$ kPa, $\phi' = 28^\circ$. CU stage: total confining stress $\sigma_3 = 100$ kPa; pore-water pressure at failure $u_w = 40$ kPa.

Given data
QuantitySymbolValue
Effective cohesion$c'$10 kPa
Effective friction angle$\phi'$$28^\circ$
Total confining stress$\sigma_3$100 kPa
Pore-water pressure at failure$u_w$40 kPa

Find. The total vertical stress $\sigma_1$ at failure in the CU test.

CU triaxial — effective-stress circle on the CD envelopeσ, σ′ (kPa)ττ = c′ + σ′ tanφ′c′σ₃′σ₁′σ₃σ₁shift = u_w = 40
Figure Q6. The effective-stress circle (green, σ₃′=60 → σ₁′=199.5) is tangent to the unique CD envelope; adding the pore pressure u_w=40 shifts it right to the total-stress circle (blue dashed), giving σ₁=239.5 kPa.

Approach. The effective-stress failure envelope $\tau_f = c' + \sigma'\tan\phi'$ is a property of the soil and is the same whether the test is CD or CU. Work in effective stresses (subtract $u_w$), apply the Mohr–Coulomb principal-stress relation to get $\sigma'_1$, then add $u_w$ back to recover the total stress.

  1. Effective confining stress. $\sigma'_3 = \sigma_3 - u_w = 100 - 40 = 60$ kPa.
  2. Flow value. $N_\phi = \tan^{2}\!\left(45^\circ + \dfrac{\phi'}{2}\right) = \tan^{2}(59^\circ) = 2.770.$
  3. Effective major stress at failure. Using the supplied relation $$\sigma'_1 = \sigma'_3\,\tan^{2}\!\left(45^\circ+\tfrac{\phi'}{2}\right) + 2c'\tan\!\left(45^\circ+\tfrac{\phi'}{2}\right),$$ $$\sigma'_1 = 60(2.770) + 2(10)(1.6643) = 166.19 + 33.29 = 199.48\ \text{kPa}.$$
  4. Back to total stress. Add the pore pressure that acts at failure: $$\boxed{\;\sigma_1 = \sigma'_1 + u_w = 199.48 + 40 = 239.5\ \text{kPa}\;}$$
CU test at failure
QuantityValue
$\sigma'_3 = \sigma_3 - u_w$60 kPa
$N_\phi = \tan^2(59^\circ)$2.770
$\sigma'_1$ (effective)199.5 kPa
$\sigma_1$ (total, applied)239.5 kPa

(i) What the CU test with pore-pressure measurement gives the senior engineer. A consolidated-undrained test in which $u_w$ is measured yields both strength frameworks from one relatively quick test. Plotting total-stress circles gives the undrained (total-stress) parameters $c_{cu},\ \phi_{cu}$ (and, at a single confining pressure, the undrained shear strength $s_u$), which govern end-of-construction / rapid-loading stability. Simultaneously, subtracting the measured $u_w$ gives the effective-stress circles and hence $c',\ \phi'$ — the fundamental long-term parameters — without waiting weeks for a fully drained test. The pore-pressure record also yields Skempton’s pore-pressure parameter $A_f$, which characterises whether the clay is contractive (normally consolidated, positive $u_w$) or dilative (over-consolidated, negative $u_w$) and lets the engineer predict field pore pressures under undrained loading.

(ii) When to run CD versus CU. Use a CD (consolidated-drained) test when the field problem is governed by long-term, drained conditions in which excess pore pressures have fully dissipated — for example the long-term stability of a cut slope or an earth-dam slope in clay years after construction, where $c',\ \phi'$ apply directly. Use a CU (consolidated-undrained with $u_w$) test when loading is rapid relative to drainage, or when both short- and long-term parameters are needed quickly — for example staged embankment construction on a soft clay foundation, or the rapid-drawdown case on the upstream fill zone of a dam, where the CU test supplies the undrained strength for the critical short-term condition and, via $u_w$, the effective parameters for the drained checks. In short: CD for slow permeable/long-term behaviour; CU for fast loading of low-permeability clays and for getting effective parameters economically.

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