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16-Civ-A4 Geotechnical Materials and Analysis · May 2016

Question 2 of 6: The three limit lateral earth pressures

Nivaar worked solution (AI-drafted; not reviewed by a licensed engineer)

Notes on this paper

National Examination 98-Civ-A4 Geotechnical Materials and Analysis — May 2016. Closed book; 3 hours; total 100 marks; answer ALL six questions. Influence charts (m–n and Newmark) and a formula sheet are supplied with the paper.

Reference texts: B.M. Das & K. Sobhan, Principles of Geotechnical Engineering, 9th ed. (Cengage); R.F. Craig, Craig's Soil Mechanics, 8th ed. (Spon Press); Holtz, Kovacs & Sheahan, An Introduction to Geotechnical Engineering, 2nd ed. (Pearson).

Question 2: The three limit lateral earth pressures (10 marks)

Question text not reproduced: the examination questions are © Engineers and Geoscientists BC. Open the official past paper (linked at the top of this page) to read the question, then follow the worked solution below.

The lateral pressure a soil exerts on a wall depends on how much the wall moves relative to the backfill. Three limiting states are defined, each with a coefficient $K$ relating the horizontal effective stress to the vertical effective stress, $\sigma_h' = K\,\sigma_v'$.

At-rest ($K_0$). The wall does not move, so the backfill retains the lateral stress it had in the ground. For a normally consolidated soil Jaky's relation gives $K_0 = 1-\sin\phi'$ (for OC soil $K_0 = (1-\sin\phi')\,\mathrm{OCR}^{\sin\phi'}$). Because the soil is not at failure, the Mohr circle drawn between $\sigma_h'=K_0\sigma_v'$ and $\sigma_v'$ lies entirely inside the Mohr–Coulomb failure envelope.

Active ($K_a$). The wall moves away from the backfill; the soil expands laterally and the horizontal stress drops until the soil fails. The horizontal stress reaches its minimum,

$$K_a = \tan^2\!\left(45^\circ-\tfrac{\phi'}{2}\right)=\frac{1-\sin\phi'}{1+\sin\phi'}.$$

Here $\sigma_v'$ is the major principal stress $\sigma_1$ and $\sigma_h'=K_a\sigma_v'$ is the minor $\sigma_3$; the Mohr circle is small and just touches (is tangent to) the failure envelope.

Passive ($K_p$). The wall is pushed into the backfill; the soil is compressed laterally and the horizontal stress rises to its maximum,

$$K_p = \tan^2\!\left(45^\circ+\tfrac{\phi'}{2}\right)=\frac{1+\sin\phi'}{1-\sin\phi'}=\frac{1}{K_a}.$$

Now the roles reverse: $\sigma_h'=K_p\sigma_v'$ is the major principal stress and $\sigma_v'$ is the minor. The Mohr circle is the largest of the three and is again tangent to the failure envelope. Only a small wall movement mobilises the full active state, whereas a much larger movement is needed to develop the passive state.

σ'τ (shear)envelope τ = σ' tanφ' (φ' = 30°)Kₐσ'vK₀σ'vσ'vKₚσ'v● active: small circle, tangent ● at‑rest: inside envelope ● passive: large circle, tangent
Mohr circles for the three limit states, all sharing the vertical effective stress $\sigma_v'$: the small active circle (tangent), the interior at-rest circle (not at failure), and the large passive circle (tangent). Active and passive circles touch the Mohr–Coulomb envelope.
Question 2 — limit earth-pressure coefficients
StateWall movementCoefficientMohr circle
At-restnone$K_0=1-\sin\phi'$interior (no failure)
Activeaway from soil$K_a=\tan^2(45^\circ-\phi'/2)$small, tangent
Passiveinto soil$K_p=\tan^2(45^\circ+\phi'/2)$large, tangent