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16-Civ-A6 Highway Design, Construction, and Maintenance · December 2014

Question 5 of 7: Singly-Constrained Gravity Model

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Notes on this paper

National Examination — 98-Civ-A6 Transportation Planning & Engineering, December 2014. Closed book (one two-sided aid sheet), 3 hours. Seven questions of equal value (20 marks); any five constitute a complete paper. All seven are solved here as a study resource.

Reference texts (subject):


Question 5: Singly-Constrained Gravity Model (20 marks)

Question text not reproduced: the examination questions are © Engineers and Geoscientists BC. Open the official past paper (linked at the top of this page) to read the question, then follow the worked solution below.

Given. Origin production $P_1$, destination attractions $A_j$, interzonal times $t_{1j}$, and friction $F_{1j}=1/t_{1j}$ (inverse proportionality).

Given data
Destination zone $j$2345
Travel time $t_{1j}$ (min)255075100
Attraction $A_j$ — case (a)75300115675
Attraction $A_j$ — case (b)150340150900

Find. The distributed trips $T_{1j}$ for the base case (a), the future case (b), and the zone of largest increase (c). Base production $P_1=1500$; future $P_1=1875$.

Approach. Singly-constrained gravity model: weight each destination by $A_j/t_{1j}$, normalize so the shares reproduce the origin production, and multiply by $P_1$.

  1. Model form. With $F_{1j}=1/t_{1j}$, $$T_{1j}=P_1\,\frac{A_j/t_{1j}}{\displaystyle\sum_{k}A_k/t_{1k}}.$$
  2. (a) Weights and denominator. $A_j/t_{1j}=\{75/25,\;300/50,\;115/75,\;675/100\}=\{3.000,\;6.000,\;1.533,\;6.750\}$, summing to $17.283$.
  3. (a) Distribute $P_1=1500$. $T_{1j}=1500\times(\text{weight})/17.283$ gives $$T_{12}=260.4,\quad T_{13}=520.7,\quad T_{14}=133.1,\quad T_{15}=585.8,$$ which sum to $\boxed{1500}$ (production conserved).
  4. (b) Future weights. $A_j/t_{1j}=\{150/25,\;340/50,\;150/75,\;900/100\}=\{6.000,\;6.800,\;2.000,\;9.000\}$, summing to $23.800$.
  5. (b) Distribute $P_1=1875$. $T_{1j}=1875\times(\text{weight})/23.800$ gives $$T_{12}=472.7,\quad T_{13}=535.7,\quad T_{14}=157.6,\quad T_{15}=709.0,$$ summing to $\boxed{1875}$.
  6. (c) Largest increase. The changes are $+212.3$ (zone 2), $+15.0$ (zone 3), $+24.5$ (zone 4) and $+123.2$ (zone 5). The largest increase is to zone 2: although zone 5 gains the most attraction in absolute terms, zone 2's attraction doubled (75→150, the largest relative jump) while its short 25-minute travel time gives it the strongest friction weight, so the extra production is funnelled disproportionately toward it.
Question 5 — trips from zone 1
Destination(a) Base(b) FutureIncrease
Zone 2260.4472.7+212.3
Zone 3520.7535.7+15.0
Zone 4133.1157.6+24.5
Zone 5585.8709.0+123.2
Total15001875+375