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16-Civ-B3 Geotechnical Design · May 2015

Question 7 of 9: Load Carrying Capacity of a Sixteen-Pile Group in Soft Clay

Nivaar worked solution (AI-drafted; not reviewed by a licensed engineer)

Notes on this paper

Paper format. Professional Engineers Ontario / Engineers Canada National Examinations, May 2015 — 98-Civ-B3 Geotechnical Design. Three hours, OPEN BOOK, any non-communicating calculator. Section A carries five discussion questions of 7 marks each (answer any four); Section B carries four design questions of 24 marks each (answer any three); the examinable total is 4 × 7 + 3 × 24 = 100 marks. All nine questions are worked below, because the set is a study resource rather than a timed attempt.

Reference texts (98-Civ-B3 / 16-Civ-B3 Geotechnical Design).

Sources of design charts and assumed values (page-1 Note 6). Note 6 of this paper requires the candidate to identify the source of every design chart used and of every value assumed in the absence of data. They are named where used and collected here:

  • Q6 — bearing capacity factors $N_c$, $N_q$, $N_{\gamma}$ from Das, Principles of Foundation Engineering, Table 3.3 (Prandtl–Reissner $N_q$, Vesic $N_{\gamma}=2(N_q+1)\tan\phi'$); shape factors after De Beer (1970) and depth factors after Hansen (1970), Das Table 3.4. Assumed: unit weight of water $\gamma_w = 9.81$ kN/m$^3$; general shear failure; the sand extends at least $2B$ below the base.
  • Q7 — adhesion factor $\alpha = 1.0$ for soft clay ($c_u \le 50$ kPa) from NAVFAC DM-7.2 Fig. 1 and Tomlinson & Woodward Table 4.6; $\lambda = 0.24$ at an embedded length of 12 m from Vijayvergiya & Focht (1972) as tabulated by Das, Table 11.7; bearing factor $N_c^{*}=9$ for $L/D \ge 4$ (Skempton). Assumed: pile spacing $s = 3d = 1.5$ m centre to centre, driven closed-end concrete piles, clay $\gamma_{sat} = 17$ kN/m$^3$ with the water table at ground level.
  • Q8 — compression index from the Skempton correlation $C_c = 0.009\,(LL-10)$, Das Principles of Geotechnical Engineering Eq. (11.42); $2{:}1$ stress distribution, Das Eq. (6.31); Boussinesq rectangular influence factor (Das Table 6.6) used as the cross-check.
  • Q9 — Coulomb active pressure coefficient, Das Principles of Foundation Engineering Eq. (8.13) with the wall friction angle prescribed by the question, $\delta = 0.6\phi' = 18^{\circ}$. Assumed: unit weight of reinforced concrete $\gamma_c = 24$ kN/m$^3$ (CSA A23.3 nominal); passive resistance in front of the toe neglected; the backfill surface is horizontal and carries no surcharge.

Question 7: Load Carrying Capacity of a Sixteen-Pile Group in Soft Clay (24 marks)

Question text not reproduced: the examination questions are © Engineers and Geoscientists BC. Open the official past paper (linked at the top of this page) to read the question, then follow the worked solution below.

Given.

QuantitySymbolValue
Number of piles, arrangement$m \times n$$4 \times 4 = 16$
Pile length (embedded)$L$12 m
Pile diameter$d$0.5 m
Average undrained strength of clay$c_u$50 kPa
Pile spacing (assumed)$s$$3d = 1.5$ m
Adhesion factor (assumed, soft clay)$\alpha$1.0
Toe bearing factor$N_c^{*}$9
Clay saturated unit weight (assumed)$\gamma_{sat}$17 kN/m$^3$

Find. The ultimate load carrying capacity of the 16-pile group, taking the smaller of the sum of the individual pile capacities and the capacity of the group acting as a single block, and the corresponding allowable load at a factor of safety of 3.

Plan of cap s = 1.5 m Bg = Lg = 3s + d = 5.0 m Section L = 12 m Soft clay, cu = 50 kPa, undrained pile cap
Sixteen-pile group: plan of the cap at $s = 3d$ centres (left) and section through one row (right). Only four of the sixteen piles appear in the section.

Approach. Compute the ultimate capacity of a single pile by the $\alpha$ (total-stress) method, multiply by 16 for the sum of the individual capacities, compute the capacity of the group acting as a single block of plan $B_g \times L_g$ and depth $L$, and take the smaller of the two as the group capacity; then check the shaft resistance against the independent $\lambda$-method.

  1. Geometry of a single pile and of the group. The cross-sectional area at the toe is $A_p = \pi d^2/4 = \pi(0.5)^2/4 = 0.19635$ m$^2$ and the perimeter is $p = \pi d = \pi(0.5) = 1.5708$ m. Adopting the standard minimum spacing $s = 3d = 1.5$ m (closer spacing causes driving interference and heave in soft clay; wider spacing wastes cap concrete), a $4\times4$ group with the cap projecting $d/2$ beyond the outer piles has plan dimensions $B_g = L_g = 3s + d = 3(1.5)+0.5 = 5.0$ m.
  2. End bearing of a single pile. In a saturated clay loaded undrained the toe resistance is $Q_p = A_p N_c^{*} c_u$ with $N_c^{*}=9$ for an embedment ratio $L/d = 24 \gg 4$ (Skempton): $$Q_p = 0.19635 \times 9 \times 50 = 88.4\ \text{kN}$$ The toe contributes less than one tenth of the capacity, as expected for a long friction pile in soft clay.
  3. Shaft resistance of a single pile by the alpha method. For a soft clay with $c_u \le 50$ kPa the adhesion factor is taken as $\alpha = 1.0$ (NAVFAC DM-7.2 adhesion chart for driven concrete piles; Tomlinson & Woodward Table 4.6). Then $$Q_s = \alpha\,c_u\,p\,L = 1.0 \times 50 \times 1.5708 \times 12 = 942.5\ \text{kN}$$ and the ultimate capacity of the single pile is $$\boxed{Q_{u(\text{single})} = 88.4 + 942.5 = 1030.8\ \text{kN}}$$
  4. Sum of the individual pile capacities. Taken as sixteen independent piles, $$\sum Q_u = 16 \times 1030.8 = 16{,}493\ \text{kN}$$ This is the upper bound: it presumes that each pile can mobilise its full shaft and toe resistance without interfering with its neighbours.
  5. Capacity of the group acting as a block. The competing failure mode is that the whole $5.0 \times 5.0 \times 12$ m block of clay and piles punches down as one body, shearing on its perimeter at the full undrained strength of the clay (soil against soil) and bearing at its base: $$Q_{g(\text{block})} = 2(B_g+L_g)\,c_u L + 9\,c_u\,B_g L_g$$ Substituting, the perimeter term is $2(5.0+5.0)(50)(12) = 12{,}000$ kN and the base term is $9(50)(5.0)(5.0) = 11{,}250$ kN, so $Q_{g(\text{block})} = 23{,}250$ kN.
  6. Governing group capacity and group efficiency. The design value is the smaller of the two, $$Q_{g(u)} = \min\{16{,}493;\ 23{,}250\} = 16{,}493\ \text{kN}$$ so the individual-pile mode governs and the group efficiency is $\eta = 16{,}493/16{,}493 = 1.0$. At the customary factor of safety of 3 on ultimate capacity, $$\boxed{Q_{g(\text{all})} = \frac{16{,}493}{3} = 5{,}500\ \text{kN}\ \ (\approx 5.5\ \text{MN})}$$ which is about 344 kN of working load per pile.
  7. Independent check on the shaft resistance by the lambda method. Because $\alpha = 1.0$ is the most generous defensible value, the answer should be bracketed. With the water table at ground level and $\gamma_{sat} = 17$ kN/m$^3$, the mean effective vertical stress over the shaft is $\bar\sigma'_v = (17-9.81)(12)/2 = 43.1$ kPa. Vijayvergiya and Focht give $\lambda = 0.24$ at an embedded length of 12 m, so $$f_{av} = \lambda(\bar\sigma'_v + 2\bar c_u) = 0.24\,(43.1 + 100) = 34.4\ \text{kPa}$$ giving $Q_s = 34.4(1.5708)(12) = 647.6$ kN, a single-pile capacity of 735.9 kN, a group ultimate of 11,775 kN and an allowable load of 3,925 kN. The two methods bracket the answer between roughly 3.9 MN and 5.5 MN, which is the honest precision of a capacity predicted from $c_u$ alone.
  8. Empirical efficiency formulae, and why they are not used here. The Converse–Labarre expression $\eta = 1 - \theta[(n-1)m+(m-1)n]/(90mn)$ with $\theta = \tan^{-1}(d/s) = 18.44^{\circ}$ returns $\eta = 0.693$ and hence 11,426 kN. Formulae of this kind were calibrated on driven piles in sand and have no theoretical basis in clay; current practice (Das §11.19, CFEM Ch. 18) is the block-versus-sum comparison used in step 6, and the Converse–Labarre value is quoted here only to show that it happens to fall inside the bracket established by the two strength methods.
QuantityValue
Toe area $A_p$ / perimeter $p$0.19635 m$^2$ / 1.5708 m
End bearing per pile, $Q_p$88.4 kN
Shaft resistance per pile ($\alpha = 1.0$), $Q_s$942.5 kN
Ultimate capacity, single pile1030.8 kN
Sum of 16 individual piles16,493 kN
Group as a block ($5.0 \times 5.0 \times 12$ m)23,250 kN
Governing ultimate group capacity16,493 kN
Group efficiency, $\eta$1.00 (individual mode governs)
Allowable group load at FS = 35,500 kN
Lambda-method bracket (ultimate / allowable)11,775 kN / 3,925 kN

Other criteria to be considered in the design of this pile group. Capacity is only the first of several limit states, and for a friction group in soft clay it is rarely the one that governs: