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16-Civ-B8 Management of Construction · May 2015

Question 3 of 6: Estimating and bidding — trenching machine production and unit cost

Nivaar worked solution (AI-drafted; not reviewed by a licensed engineer)

Notes on this paper

Paper format. National Exams, May 2015 — 98-Civ-B8 Management of Construction (the paper now catalogued as 16-Civ-B8). Three hours, closed book; one of two approved calculator models permitted. Six questions of equal value (20 marks each); the rubric states that any five constitute a complete paper and that only the first five presented in the answer book will be marked. All six are worked here, because this set is a study resource rather than an exam script. The paper is three calculation questions (1, 3, 4) and three discussion questions (2, 5, 6).

Source note. The two side tables on page 2 — the activity/duration/predecessor list in Question 1 and the trenching-machine production table in Question 3 — are given in full in the Given blocks below. The final activity in the Question 1 table is printed as a two-character label that reads QI; it is a closing activity of one day's duration following V and S, and the answer does not depend on how the label is read.

Reference texts.

Question 3: Estimating and bidding — trenching machine production and unit cost (20 marks)

Question text not reproduced: the examination questions are © Engineers and Geoscientists BC. Open the official past paper (linked at the top of this page) to read the question, then follow the worked solution below.

Given. A single trench of uniform section excavated by one ladder-type trencher with a three-person crew — operator, labourer and foreman — the machine's digging speed read from the manufacturer's table for the applicable depth and width band.

Given data for the trench excavation estimate
ItemValue
Trench length2,940 ft
Trench width30 in. (2.5 ft)
Average trench depth7 ft
Materialcommon earth
Table digging speed, depth 6–8 ft and width 30–36 in.25 to 50 ft/hr
Operating efficiency45 productive min per 60-min hour
Trenching machine$87/hr
Machine operator$25/hr
Labourer$20/hr
Foreman$20/hr

Find. The total cost of the trench excavation and the cost per linear foot of trench.

existing ground 30 in. 7 ft average depth common earth Section through the trench; the machine advances 2,940 ft along the line of the trench.
Section through the trench: 30 in. (2.5 ft) wide by 7 ft average depth in common earth. This depth-and-width combination selects the 25–50 ft/hr row of the production table.

Approach. Enter the production table with the trench's depth and width to obtain the ideal digging speed, correct it for operating efficiency to get an achievable production rate, divide the length by that rate to get machine hours, and multiply by the assembled hourly cost of the machine and crew.

  1. Select the correct row of the production table. The trench is 7 ft deep on average and 30 in. wide, which places it in the 6–8 ft depth band and, within that band, in the 30, 32, 36 in. width group. The tabulated digging speed for that combination is 25 to 50 ft/hr. Selecting the row is the step that carries the most estimating judgement, because moving one band up in width or depth would roughly double the assumed production, and every later number scales inversely with it.
  2. Take a representative ideal speed. The table gives a range rather than a value, so in the absence of a stated soil condition the midpoint is the defensible estimate for common earth, which is the average of the materials the range is meant to cover: $$v_{\text{ideal}}=\frac{25+50}{2}=37.5\ \text{ft/hr}$$ The lower end of the range corresponds to tight, stony or wet ground and the upper end to loose, free-digging soil; the sensitivity of the answer to this choice is quantified at the end.
  3. Convert the operating efficiency into a factor. An efficiency stated as 45 productive minutes per hour accounts for the time the machine is not cutting: repositioning, spoil handling, minor adjustments, operator breaks and crew delays. $$E=\frac{45\ \text{min}}{60\ \text{min}}=0.75$$
  4. Compute the achievable production rate. Multiplying the ideal speed by the efficiency factor gives the rate that should be used for estimating: $$P=v_{\text{ideal}}\cdot E=37.5\times0.75=\boxed{28.125\ \text{ft/hr}}$$ This is the number that would be quoted to the superintendent as the daily target — roughly 225 ft in an eight-hour shift.
  5. Convert the quantity of work into machine hours. Dividing the length of trench by the production rate, $$t=\frac{L}{P}=\frac{2{,}940\ \text{ft}}{28.125\ \text{ft/hr}}=104.53\ \text{hr}$$ which at eight hours per shift is a little over thirteen working days for the trenching operation alone.
  6. Assemble the hourly cost of the operation. The machine and the whole crew are charged for every hour the operation is on site, because the labourer and the foreman cannot be released while the trencher is working: $$C_{\text{hr}}=87+25+20+20=\boxed{\$152\ \text{per hour}}$$
  7. Compute the total cost and the unit cost. Multiplying the duration by the hourly cost, $$C_{\text{total}}=t\cdot C_{\text{hr}}=104.53\times152=\boxed{\$15{,}889}$$ and dividing by the length of trench, $$C_{\text{ft}}=\frac{15{,}889}{2{,}940}=\boxed{\$5.40\ \text{per linear foot}}$$ A useful check is that the unit cost can be obtained directly, without the duration, as the hourly cost divided by the production rate: $C_{\text{hr}}/P=152/28.125=\$5.40$ per foot, which agrees.
  8. Cross-check against a volumetric rate. Estimators normally sanity-check a linear price against the volume it moves. The bank volume excavated is $$V=\frac{2{,}940\times2.5\times7}{27}=1{,}906\ \text{bank yd}^3$$ so the operation costs $C_{\text{total}}/V=\$8.34$ per bank cubic yard, which is a plausible order of magnitude for machine trenching in common earth and confirms that no factor-of-twelve unit slip has crept into the width conversion.
  9. Quantify the sensitivity to the tabulated range. Because the table spans a factor of two, the estimate should be reported with its range rather than as a single number:
    Sensitivity of the estimate to the digging speed assumed
    Ideal speedProduction at E = 0.75DurationTotal costCost per linear foot
    25 ft/hr (tight ground)18.75 ft/hr156.8 hr$23,834$8.11
    37.5 ft/hr (mid-range, adopted)28.125 ft/hr104.5 hr$15,889$5.40
    50 ft/hr (free-digging)37.5 ft/hr78.4 hr$11,917$4.05
    A bidder would price the mid-range figure and carry the difference to the low-production case as a contingency, or investigate the ground further before committing.

Check: the estimate assumes (i) the mid-range digging speed of 37.5 ft/hr, since the paper states only "common earth" and gives a two-to-one range; (ii) that the labourer and foreman are charged for the full duration of the trenching operation rather than part-time; and (iii) that the cost asked for is the direct cost of excavation only — no mobilisation, bedding, shoring, dewatering, backfill, compaction, overhead or profit is included, none of which the question supplies data for. Trench boxes or sloping would be mandatory at this depth under WorkSafeBC OHS Regulation Part 20, and their cost would be added in a real bid.

Question 3 — final results
QuantityValue
Table digging speed selected (6–8 ft deep, 30–36 in. wide)25 to 50 ft/hr, midpoint 37.5 ft/hr
Operating efficiency factor0.75
Achievable production rate28.125 ft/hr
Duration of the trenching operation104.5 hr (about 13 eight-hour shifts)
Assembled hourly cost, machine plus crew$152/hr
Total cost of excavation$15,889
Cost per linear foot$5.40/ft
Equivalent volumetric cost$8.34 per bank cubic yard (1,906 bank yd3)