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16-Civ-B9 The Finite Element Method: December 2018

Nivaar worked solution (AI-drafted; not reviewed by a licensed engineer)

  1. Question 1 Reactions by virtual work, and why the element must contain the rigid body modes (Problem 1)
  2. Question 2 Two-span beam with a seating gap at the middle support (Problem 2)
  3. Question 3 Shape functions, a stiffness coefficient and consistent nodal loads for the four-node rectangle (Problem 3)

Start with Question 1 →

Paper format. National Exams, December 2018 — 16-Civ-B9 The Finite Element Method. Three hours; four pages; three problems of equal weight, all to be attempted. Closed book, one aid sheet written on both sides, approved Casio or Sharp calculator. Candidates are asked to state any interpretive assumptions with the answer paper, which matters here because Problem 2 is a contact problem whose answer depends on one such check.

Reference texts for this subject.

Check — misprint on page 3 of the paper. The examination prints the first Hermite shape function as $N_1(s) = \dfrac{2s^3}{L^3} - \dfrac{2s^2}{L^2} + 1$. That expression gives $N_1(L) = 1$ instead of $0$ and makes $N_1 + N_3 = 2$ at the far node, so it cannot be a beam shape function. The middle coefficient must be $3$: $N_1(s) = \dfrac{2s^3}{L^3} - \dfrac{3s^2}{L^2} + 1$, which is consistent with the $N_3(s)$ printed immediately below it and with the $[K]$ matrix given on the same page. The corrected form is used throughout. Nothing in the numerical answer depends on it, because the element stiffness matrix is supplied directly.