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11-CS-1 Engineering Economics · May 2014

Question 2 of 5: Air Compressor — Economic Life

Nivaar worked solution (AI-drafted; not reviewed by a licensed engineer)

Notes on this paper

National Exams — May 2014 — 11-CS-1 Engineering Economics. Open book; non-communicating calculator permitted. Any four of the five questions constitute a complete paper; all questions are of equal value. Fully worked solutions to all five questions follow; standard compound-interest factors are used and minor rounding is immaterial.

Question 2: Air Compressor — Economic Life (25 marks)

Question text not reproduced: the examination questions are © Engineers and Geoscientists BC. Open the official past paper (linked at the top of this page) to read the question, then follow the worked solution below.

(a) Sunk Costs

A sunk cost is a cost already incurred that cannot be recovered by any future decision. In a replacement analysis, sunk costs are irrelevant—the original purchase price of an existing asset does not affect the keep-or-replace decision; only future costs and the asset's current market value matter. Including sunk costs leads to the error of "throwing good money after bad."

(b) Equivalent Annual Cost for n = 1–4 Years

Initial cost $P=\$5{,}200$ (compressor + running-in); salvage $S_n = 5{,}000(0.85)^{n}$; $EAC(n) = P(A/P,10\%,n) - S_n(A/F,10\%,n) + [500 + 220(A/G,10\%,n)]$:

n (yr)Salvage $S_n$Capital costO&M equiv.EAC(n)
1$4,250$1,470$500$1,970
2$3,613$1,276$605$1,881
3$3,071$1,163$706$1,869
4$2,610$1,078$804$1,882

Two modelling points are worth stating explicitly, as the exam's own instructions invite. First, the $200 running-in cost is incurred immediately and is not recoverable, so it is added to the first cost ($P = \$5{,}200$) but is not part of the declining-balance base — salvage is estimated on the $5,000 purchase price alone. Second, the $220 escalation is a uniform arithmetic gradient, so it is converted with $(A/G,10\%,n)$ rather than the geometric factor; note that $(A/G,10\%,1)=0$, which is why year 1's O&M equivalent is exactly the base $500.

(c) Optimal Replacement Interval

The EAC is minimized at n = 3 years (EAC ≈ $1,869), so with constant costs and interest the compressor should be replaced every 3 years—its economic life.

(d) Depreciation Rate for $500 Book Value in 4 Years

$$5{,}000(1-d)^{4} = 500 \;\Rightarrow\; (1-d)^{4} = 0.10 \;\Rightarrow\; 1-d = 0.10^{1/4}=0.5623 \;\Rightarrow\; d \approx \boxed{43.8\%}$$