11-CS-1 Engineering Economics · May 2016
Nivaar worked solution (AI-drafted; not reviewed by a licensed engineer)
National Exams — May 2016 — 11-CS-1 Engineering Economics. Open book; non-communicating calculator permitted. Any four of the five questions constitute a complete paper; all questions are of equal value. Fully worked solutions to all five questions follow; standard compound-interest factors are used and minor rounding is immaterial.
Question text not reproduced: the examination questions are © Engineers and Geoscientists BC. Open the official past paper (linked at the top of this page) to read the question, then follow the worked solution below.
First the effective annual rates: A $(1+0.0825/366)^{366}-1 = 8.60\%$; B $(1+0.0825/12)^{12}-1 = 8.57\%$; C $(1+0.083/4)^{4}-1 = 8.56\%$. Then $i_{sa}=(1+i_a)^{1/2}-1$:
A saver prefers the highest effective annual rate, so Bank A (8.60%). Interest on $5,000 after 3 years:
There are 6 two-month periods per year, so the nominal annual rate is $1.4\%\times 6 = \boxed{8.4\%}$.
Bank D, simple interest: $F = 5{,}000(1 + 0.09\times 3) = 5{,}000(1.27) = \$6{,}350$, i.e. interest of $1,350. Bank A, compound: $F = \$6{,}404$, i.e. interest of $1,404. Since Bank A yields $54 more over the three years, no—keep Bank A: the compounding of 8.60% beats 9% simple interest. Note the margin is thin and it is horizon-dependent—over one year the 9% simple rate would win ($450 against $430), and the two break even at about 2.1 years; only beyond that does compounding put Bank A ahead.