23-CS-1 Engineering Economics · May 2017
Nivaar worked solution (AI-drafted; not reviewed by a licensed engineer)
National Exams — May 2017 — 11-CS-1 Engineering Economics. Open book; non-communicating calculator permitted. Any four of the five questions constitute a complete paper; all questions are of equal value. Fully worked solutions to all five questions follow; standard compound-interest factors are used and minor rounding is immaterial.
Question text not reproduced: the examination questions are © Engineers and Geoscientists BC. Open the official past paper (linked at the top of this page) to read the question, then follow the worked solution below.
For a nominal rate $r$ compounded $m$ times a year the period rate is $r/m$ and the effective annual rate is $i_a=(1+r/m)^{m}-1$. Using the paper's hint, $m=366$ days for A, $52$ weeks for B and $12$ months for C:
The spread between the three nominal rates (0.50 percentage points) is larger than the extra compounding gains, so the ranking by effective rate follows the ranking by nominal rate here.
A quarter contains $366/4 = 91.5$ days, $52/4 = 13$ weeks or $12/4 = 3$ months, so compound each company's own period rate over one quarter — equivalently, take $i_q=(1+i_a)^{1/4}-1$ from part (a), which gives the same figures:
Check: $(1.0253116)^4-1 = 0.10516$, which reproduces Company A's effective annual rate, as it must.
These are loan rates, so the entrepreneurs want the lowest effective cost—Company A (10.52%), whose lower nominal 10% compounded daily still beats the higher nominal rates compounded less often.
Break-even means Company A's effective annual rate equals Company B's, $10.7826\%$. Solve for the nominal daily rate $r$ by taking the $366$th root:
So Company A could raise its quoted rate from 10.00% to about 10.24% before the entrepreneurs would become indifferent between A and B — a 0.24-point margin, which is the practical value of A's more frequent compounding being offset by its lower nominal rate.