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23-CS-2 Engineering in Society · May 2013

Question 6 of 7: Industrial Noise — Effects, Audiology, and Noise Dose

Nivaar worked solution (AI-drafted; not reviewed by a licensed engineer)

Notes on this paper

National Exams — May 2013 — 11-CS-2 Engineering in Society: Health and Safety. Closed book; approved calculator permitted. Any five of the seven questions constitute a complete paper; all questions are of equal value. Answers are written in point form but fully, as instructed. Complete answers to all seven questions follow.

Question 6: Industrial Noise — Effects, Audiology, and Noise Dose (20 marks: 6/6/8)

Question text not reproduced: the examination questions are © Engineers and Geoscientists BC. Open the official past paper (linked at the top of this page) to read the question, then follow the worked solution below.

(i) Detrimental Effects of Noise (other than hearing loss)

(ii) Audiology and Audiogram

(iii) Daily Noise Dose Calculation

The combined dose is the sum of the fractions of each exposure to its permissible duration: $D = \sum \dfrac{C_i}{T_i}$.

$$D = \frac{4}{16} + \frac{2}{8} + \frac{1}{4} + \frac{1}{2} = 0.25 + 0.25 + 0.25 + 0.50 = 1.25$$
$$D = \boxed{1.25 = 125\%}$$

The durations the question supplies are the 5 dB exchange rule anchored at 85 dBA = 8 h ($T = 8/2^{(L-85)/5}$ gives 16, 8, 4 and 2 hr at 80, 85, 90 and 95 dBA). The equivalent 8-hour time-weighted average must therefore be read off the same 85 dBA anchor:

$$TWA = 85 + 16.61\log_{10}(D) = 85 + 16.61\log_{10}(1.25) = 85 + 1.61 \approx 86.6\ \text{dBA}$$

Cross-check on OSHA’s own Table G-16a, whose reference durations ($T = 8/2^{(L-90)/5}$: 32, 16, 8 and 4 hr) are exactly double the ones printed here: the same exposure scores $D = \tfrac{4}{32}+\tfrac{2}{16}+\tfrac{1}{8}+\tfrac{1}{4} = 0.625$ and $TWA = 90 + 16.61\log_{10}(0.625) = 86.6$ dBA — the same level, as it must be. The dose is criterion-dependent; the TWA it encodes is not.

LevelExposure $C_i$Permissible $T_i$$C_i/T_i$
80 dBA4 hr16 hr0.25
85 dBA2 hr8 hr0.25
90 dBA1 hr4 hr0.25
95 dBA1 hr2 hr0.50
Total dose D1.25

Is it acceptable? No. Since $D = 1.25 > 1.0$ (125% > 100%), the daily exposure exceeds the permissible limit—it is NOT acceptable (equivalent TWA ≈ 86.6 dBA > the 85 dBA criterion on which the supplied table is based).

What should be done (in hierarchy order):

Canadian context. The durations the question labels “OSHA” keep OSHA’s 5 dB exchange rate but are anchored at 85 dBA = 8 h, not at OSHA’s own 90 dBA — each printed value is half the corresponding Table G-16a duration. Most Canadian jurisdictions set an 85 dBA Lex(8h) limit with a 3 dB exchange rate (per CSA Z107.56 and provincial OH&S regulations; Québec still uses 90 dBA / 5 dB), so the limit agrees with the supplied table but the exchange rate does not. Under a 3 dB rule every +3 dBA halves the allowed time (25.4, 8, 2.52 and 0.79 hr at 80, 85, 90 and 95 dBA), giving $D = 2.06$ and $L_{ex(8h)} = 85 + 10\log_{10}(2.06) = 88.1$ dBA — this same exposure accumulates dose even faster and is still unacceptable, so the Canadian assessment is the more protective one. Above, the dose is computed with the table exactly as the question gives it.