Given. Population $= 50{,}000$; compacted refuse depth $= 4\ \text{m}$ (cover material excluded, as stated).
Find. The annual land area (excluding buffer zone) required to place one year's compacted refuse at this depth.
Approach. Estimate the annual mass of waste generated from an assumed per-capita generation rate, convert to compacted volume using an assumed compacted density, then divide by the stated refuse depth to get area.
Check: neither a generation rate nor a compacted density is given in this question. A per-capita generation rate of 2.0 kg/cap/day is assumed (a typical North American municipal design value, Tchobanoglous). The compacted density is taken as 600 kg/m³, reused from this same paper's own Q15 data ("density of well compacted landfill = 600 kg/m³") for internal consistency rather than inventing a separate figure.
Annual mass of waste generated.
$$m = 50{,}000 \times 2.0\ \text{kg/cap/d} \times 365\ \text{d/yr} = 36{,}500{,}000\ \text{kg/yr} = 36{,}500\ \text{t/yr}$$