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18-Env-B4 Site Assessment and Remediation · May 2014

Question 6 of 8: Section B — Two of Three Questions

Nivaar worked solution (AI-drafted; not reviewed by a licensed engineer)

Notes on this paper

National Exams — May 2014 — 04-Env-B4 / Site Assessment and Remediation. 3 hours duration; open-book exam (any non-communicating calculator permitted). The paper is split into Section A (five questions, candidates asked to answer three) and Section B (three questions, candidates asked to answer two), each question worth 20 marks. All eight questions are solved below for completeness.

Reference texts. Suthersan & Payne, Remediation Engineering: Design Concepts (CRC Press); Gavaskar, Gupta, Sass, Janosy & O'Sullivan, Design Guidance for Application of Permeable Reactive Barriers for Groundwater Remediation (Battelle/EPA, 2000); ASTM E1527 Standard Practice for Phase I Environmental Site Assessments and ASTM E1903 Standard Practice for Phase II ESA; Mercer & Cohen (1990), “A review of immiscible fluids in the subsurface,” Journal of Contaminant Hydrology; Freeze & Cherry, Groundwater; Davis & Cornwell, Introduction to Environmental Engineering (6th ed.); Ontario Reg. 153/04 under the Environmental Protection Act (Record of Site Condition regime); BC Environmental Management Act — Contaminated Sites Regulation.

Section A — Three of Five Questions

Section B — Two of Three Questions

Question B-1: Fe⁰ Permeable Reactive Barrier Sizing for a PCE Plume (20 marks)

Question text not reproduced: the examination questions are © Engineers and Geoscientists BC. Open the official past paper (linked at the top of this page) to read the question, then follow the worked solution below.

A zero-valent iron (Fe⁰) permeable reactive barrier (PRB) is installed as a wall of granular iron across the width and depth of the contaminant plume, oriented perpendicular to groundwater flow, so that the plume passes through it under its own natural gradient with no pumping (a purely passive, in-situ treatment train). PCE reacts abiotically at the iron surface: the iron corrodes ($\text{Fe}^0 \rightarrow \text{Fe}^{2+} + 2e^-$), and the released electrons reductively dechlorinate PCE, stripping chlorine atoms stepwise (or, more favourably, via beta-elimination that bypasses the more toxic intermediates) to non-chlorinated end products such as ethene and ethane. Because the reaction occurs at the iron surface, its rate is normalized to the surface area of iron presented to the water — the surface-area rate constant $k_{sa}$ supplied in this question — rather than to the iron's mass or the barrier's bulk volume directly.

regional groundwater flow PCE source (dry cleaner) PCE plume C₀ = 95 mg/L treated GW Cₜ = 5 µg/L MW-1 (source zone) MW-2 (compliance point) Fe⁰ PRB (granular iron wall, A = 80 m²)
Plan-view sketch: the PCE plume from the dry-cleaner source passes through a continuous Fe⁰ permeable reactive barrier installed across the full plume cross-section; abiotic reductive dechlorination on the iron surface reduces the concentration from 95 mg/L to below the 5 µg/L target by the downgradient compliance well.

Given. $C_0 = 95$ mg/L, $C_t = 5\ \mu\text{g/L} = 0.005$ mg/L, plume cross-section $A = 80$ m², groundwater (seepage) velocity $v = 0.12$ m/d, aquifer porosity $n = 0.35$, iron specific surface area $a_s = 1.0$ m²/g, $k_{sa} = 2.1\times10^{-3}$ L/(m²·h) with only 35% activity at the 10°C site temperature, safety factor SF = 3.

Find. The total mass of granular Fe⁰ (metric tons) required in the barrier.

Approach. Model the barrier as a plug-flow packed bed: water carrying PCE flows through a fixed mass of iron, and PCE degrades as a pseudo-first-order surface reaction. Integrating the mass balance along the flow path gives the classic packed-bed design equation $W = Q\ln(C_0/C_t)/(k_{sa}a_s)$ — the total iron mass needed depends only on the water flux, the required log-removal, and the rate parameters, not on the barrier's thickness (mass and thickness trade off against each other for a fixed iron packing density).

  1. Temperature-corrected rate constant. $k_{sa,10^\circ C} = 0.35 \times 2.1\times10^{-3} = \boxed{7.35\times10^{-4}}\ \text{L/(m}^2\cdot\text{h)} = 1.764\times10^{-2}\ \text{L/(m}^2\cdot\text{d)}$.
  2. Volumetric flow through the barrier. The given 0.12 m/d is the average linear (seepage) groundwater velocity; converting to the Darcy flux (specific discharge) that actually carries the water volume through the full cross-section uses the aquifer porosity: $v_{Darcy} = n\,v = 0.35 \times 0.12 = 0.042$ m/d. The volumetric flow is then $Q = v_{Darcy}A = 0.042 \times 80 = \boxed{3.36}\ \text{m}^3/\text{d} = 3360\ \text{L/d}$.
  3. Required log-removal. $\ln(C_0/C_t) = \ln(95/0.005) = \boxed{9.85}$.
  4. Iron mass, no safety factor. $W = \dfrac{Q\ln(C_0/C_t)}{k_{sa,10^\circ C}\,a_s} = \dfrac{3360 \times 9.85}{1.764\times10^{-2}\times1.0} = 1{,}876{,}600\ \text{g} = 1.877$ metric tons.
  5. Apply the safety factor. $W_{design} = 3 \times 1.877 = \boxed{5.63}\ \text{metric tons of Fe}^0$.
Final Results
QuantityValue
$k_{sa}$ at 10°C$7.35\times10^{-4}$ L/(m²·h)
Darcy flux through barrier0.042 m/d (Q = 3.36 m³/d)
Required log-removal, ln(C₀/Cᷯ)9.85
Fe⁰ mass, no safety factor1.877 t
Fe⁰ mass, design (SF = 3)5.63 metric tons
Check: “groundwater velocity of 0.12 m/d” is read here as the average linear (seepage) velocity, converted to a Darcy flux via the given aquifer porosity to obtain the true volumetric flow through the barrier — the standard convention when a porosity value is supplied alongside a stated groundwater velocity. If instead 0.12 m/d were intended as the Darcy flux directly (no porosity correction), Q rises to 9.6 m³/d and the design Fe⁰ mass scales up to ≈16.1 metric tons; either reading uses every given number, so the assumption is stated explicitly rather than silently resolved.