NivaarExam PrepOfficial exam papers ↗

18-Env-B5 Industrial & Hazardous Waste Management · December 2018

Question 8 of 11: Incinerator Maximum Waste Batch Size

Nivaar worked solution (AI-drafted; not reviewed by a licensed engineer)

Notes on this paper

Reference texts: LaGrega, Buckingham & Evans, Hazardous Waste Management, 2nd ed.; Nemerow & Dasgupta, Industrial and Hazardous Waste Treatment, 2nd ed.; Metcalf & Eddy, Wastewater Engineering: Treatment and Resource Recovery, 5th ed.; Davis & Cornwell, Introduction to Environmental Engineering, 6th ed.; Cooper & Alley, Air Pollution Control: A Design Approach; CCME, Guidelines for the Management of Biomedical Waste in Canada (1992); Ontario Environmental Protection Act, R.S.O. 1990, c. E.19 and O. Reg. 347 (Waste Management – General); Transportation of Dangerous Goods Act, 1992 (Canada) and Regulations; Canadian Environmental Protection Act (CEPA), 1999.

Question 8: Incinerator Maximum Waste Batch Size (10 marks)

Question text not reproduced: the examination questions are © Engineers and Geoscientists BC. Open the official past paper (linked at the top of this page) to read the question, then follow the worked solution below.

Given.

QuantityValue
Design heat-release capacity$2\times10^{7}$ Btu/hr
Normal waste heating value700–1,000 Btu/lb
Rubber waste heating value12,000 Btu/lb
Residence time in incinerator6 min

Find. The maximum size of a rubber-waste batch the incinerator can process without exceeding its design heat-release capacity.

Approach. The incinerator is designed around a fixed heat-RELEASE rate (Btu/hr), not a fixed mass-feed rate — a higher-heating-value waste must be fed at a proportionally LOWER mass rate to stay within that same design capacity. Find the maximum allowable mass feed rate first, then convert to a batch mass using the stated residence time.

  1. Maximum allowable feed rate. Divide the incinerator's design heat-release capacity by the rubber waste's (much higher) heating value: $$\dot{m}_{max}=\frac{Q_{design}}{HV_{rubber}}=\frac{2\times10^{7}\ \text{Btu/hr}}{12{,}000\ \text{Btu/lb}}=\boxed{1{,}666.7\ \text{lb/hr}}$$ This is well below the roughly 20,000–28,600 lb/hr the same $2\times10^7$ Btu/hr capacity would allow at the incinerator's NORMAL 700–1,000 Btu/lb waste — confirming that a high-heating-value waste like rubber must be fed much more slowly, or co-fired/blended with lower-heating-value waste, to avoid over-firing the unit.
  2. Maximum batch size. Convert the residence time to hours and multiply by the maximum feed rate found above — the batch size is the mass of waste present in the incinerator at any one time as it moves through at that feed rate over one residence time: $$t_{res}=6\ \text{min}=0.100\ \text{hr}$$ $$m_{batch}=\dot{m}_{max}\times t_{res}=1{,}666.7\ \text{lb/hr}\times0.100\ \text{hr}=\boxed{166.7\ \text{lb}}$$
Final results
QuantityValue
Maximum allowable feed rate1,666.7 lb/hr
Maximum batch size166.7 lb
Check: the incinerator's heat-release capacity is treated as the binding constraint (standard assumption for this class of problem) — a real installation would also need to check that the resulting lower mass throughput still meets minimum turbulence/mixing and secondary-combustion-chamber residence-time requirements for complete destruction, which are not addressed by this heat-balance calculation alone.