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18-Env-B9 Environmental Chemistry and Microbiology · May 2013

Question 7 of 25: Suspended Solids and Percent Volatile Matter

Nivaar worked solution (AI-drafted; not reviewed by a licensed engineer)

Notes on this paper

National Exams — May 2013 — 04-Env-B9, Environmental Chemistry/Microbiology. 3 hours duration; closed-book exam (approved Casio or Sharp calculator only). The paper has two sections — Section 1: Chemistry (11 questions, 50 marks) and Section 2: Microbiology (14 questions, 50 marks) — twenty-five questions constitute the complete exam and all are answered below. Total examination mark 100.

Reference texts. Davis & Cornwell, Introduction to Environmental Engineering (6th ed.) (water chemistry, disinfection, water/wastewater microbiology, indicator organisms); Metcalf & Eddy (Tchobanoglous, Stensel, Tsuchihashi & Burton), Wastewater Engineering: Treatment and Resource Recovery (5th ed.) (chemical unit processes, chemical phosphorus precipitation, biomass stoichiometry, activated-sludge microbiology); Guidelines for Canadian Drinking Water Quality (Health Canada); MWH's Water Treatment: Principles and Design (3rd ed.) (chlorine disinfection, contact-tank sizing).

Section 1: Chemistry (11 questions, 50 marks)

Question 7: Suspended Solids and Percent Volatile Matter (4 marks)

Question text not reproduced: the examination questions are © Engineers and Geoscientists BC. Open the official past paper (linked at the top of this page) to read the question, then follow the worked solution below.

Given data
QuantityValue
Sample volume25 mL
Tare mass, filter (dry)1.5325 g
Tare mass, filter + dried solids (105°C)1.5415 g
Tare mass, filter + ash (after ignition, 550°C)1.5378 g

Given. Standard Methods 2540D/E gravimetric procedure: mass gained on the filter after drying is total suspended solids (TSS); mass lost on subsequent ignition at 550°C is the volatile fraction of that TSS.

Find. (7.1) TSS concentration, mg/L; (7.2) percent of the TSS that is volatile.

Approach. Take the mass difference for drying to get TSS mass, normalize by sample volume for concentration; take the mass difference between dried and ignited filter to get the volatile (ash-loss) mass, and express as a percentage of the TSS mass.

  1. Suspended solids mass and concentration. $$m_{SS} = 1.5415-1.5325 = 0.0090\ \text{g per } 25\ \text{mL}$$ $$\text{TSS} = \frac{0.0090\ \text{g}}{0.025\ \text{L}} = 0.360\ \text{g/L} = \boxed{360\ \text{mg/L}}$$
  2. Volatile (organic) mass. Ash mass retained after ignition $=1.5378-1.5325=0.0053$ g, so the mass burned off (volatile solids) is $$m_{VS} = m_{SS}-m_{ash} = 0.0090-0.0053 = 0.0037\ \text{g}$$
  3. Percent volatile matter. $$\%VS = \frac{m_{VS}}{m_{SS}}\times100 = \frac{0.0037}{0.0090}\times100 = \boxed{41.1\%}$$
Solids analysis — final results
QuantityValue
Total suspended solids360 mg/L
Volatile fraction of TSS41.1%