Question 1 of 5: Falling-Head Permeameter, Storage Properties and Soil Phase Relations
Nivaar worked solution (AI-drafted; not reviewed by a licensed engineer)
Notes on this paper
National Exams — May 2017 — 04-Geol-A2 Hydrogeology. Three-hour, open-book exam; any non-communicating calculator permitted. Five questions constitute a complete paper and all five are of equal value; most call for an essay-format answer with clarity and organization counted. Unless stated otherwise, water density is taken as 998 kg/m³, water viscosity as 0.001 kg/m-sec at 20°C, and g as 9.81 m/s².
Reference texts: Freeze & Cherry, Groundwater (Prentice-Hall, 1979) — Darcy's law, specific storage/storativity, the Theis and Thiem well equations, leaky-aquifer (Hantush-Jacob) theory, image-well boundary methods, density-dependent flow, and the Dupuit-Forchheimer approximation with areal recharge; Todd & Mays, Groundwater Hydrology — slug-test (Hvorslev) analysis and unconfined dam-seepage solutions; EGBC Geoscience Professional Practice Guidelines for assumption-disclosure conventions on open-book calculations.
Given. (a) Falling-head tube diameter 1.8 cm, sample-tube diameter 12.0 cm, flow length $L=15$ cm, head falls from $h_0=6.0$ cm to $h_1=0.50$ cm over $t=550$ min at a constant test temperature of 15°C. (b) Confined aquifer specific storage $S_s=5.33\times10^{-3}\ \text{m}^{-1}$, porosity $n=0.3$, water compressibility $\beta_w=4.6\times10^{-10}\ \text{m}^2/\text{N}$. (c) Aquifer thickness $b=30$ m, piezometric decline $\Delta h=2.5$ m over a circular area of radius $r=220$ m.
Symbol
Value
$V_t$ (total volume, part d)
11.8 cm³
$M_t$ (moist mass, part d)
23.1 g
$M_s$ (dry mass, part d)
21.1 g
$\rho_s$ (grain density, part d)
2.65 g/cm³
Find. (a) hydraulic conductivity $K$ and intrinsic permeability $k$ of the soil, and its likely classification. (b) skeletal (matrix) compressibility $\alpha$. (c) volume of water released as the piezometric surface declines. (d) porosity, bulk density, void ratio and moisture content of the moist sample.
Approach. Part (a) uses the standard falling-head permeameter equation to get $K$ directly from the geometry and head ratio (no fluid properties needed), then converts to intrinsic permeability with the fluid properties at the 15°C test temperature (not the paper's 20°C default, since a temperature is explicitly stated). Part (b) inverts $S_s=\rho_wg(\alpha+n\beta_w)$ for the skeletal term $\alpha$. Part (c) uses $S_s$ (as a storativity per unit thickness) to convert the piezometric decline over the given area directly into a released volume. Part (d) is a standard four-measurement soil phase-relation reduction.
Part (a) — hydraulic conductivity from the falling-head test. With standpipe area $a=\pi(1.8/2)^2=2.545\ \text{cm}^2$ and sample area $A=\pi(12.0/2)^2=113.10\ \text{cm}^2$, $t=550\times60=33{,}000$ s:
$$K=\frac{aL}{At}\ln\!\left(\frac{h_0}{h_1}\right)=\frac{(2.545)(15)}{(113.10)(33{,}000)}\ln\!\left(\frac{6.0}{0.50}\right)=\boxed{2.54\times10^{-5}\ \text{cm/s}\ (2.54\times10^{-7}\ \text{m/s})}.$$
Intrinsic permeability at the test temperature. $K$ is a hydraulic conductivity measured with water at 15°C, so converting to the fluid-independent intrinsic permeability $k=K\mu/(\rho g)$ needs water's properties AT 15°C ($\mu_{15}=1.139\times10^{-3}\ \text{kg/m-s}$, $\rho_{15}=999.1\ \text{kg/m}^3$), not the paper's 20°C default:
$$k=\frac{(2.54\times10^{-7})(1.139\times10^{-3})}{(999.1)(9.81)}=\boxed{2.95\times10^{-14}\ \text{m}^2}.$$
At $K\approx2.5\times10^{-7}\ \text{m/s}$ the material sits squarely in Freeze & Cherry's silt / silty-sand range ($10^{-9}$–$10^{-6}\ \text{m/s}$), well below clean-sand values — the soil tested behaves hydraulically as a silt, not a sand.
Part (b) — skeletal compressibility from specific storage. Specific storage combines the matrix (skeleton) and pore-water compressibilities, $S_s=\rho_wg(\alpha+n\beta_w)$, so:
$$\alpha=\frac{S_s}{\rho_wg}-n\beta_w=\frac{5.33\times10^{-3}}{(998)(9.81)}-(0.3)(4.6\times10^{-10})=\boxed{5.44\times10^{-7}\ \text{m}^2/\text{N}}.$$
The skeleton is roughly 1,200 times more compressible than the water itself — consistent with $S_s$ of a confined aquifer being dominated by grain-skeleton rearrangement, not pore-fluid compression.
Part (c) — volume released over the piezometric decline. Multiplying $S_s$ by the aquifer thickness gives the (dimensionless) storativity, $S=S_sb=(5.33\times10^{-3})(30)=0.1599$; the released volume is then $S$ times the affected area times the head decline:
$$V=S\cdot(\pi r^2)\cdot\Delta h=(0.1599)\left[\pi(220)^2\right](2.5)=\boxed{6.08\times10^4\ \text{m}^3\ (60{,}783\ \text{m}^3)}.$$
Part (d) — solids and void volume. The oven-dried solids occupy $V_s=M_s/\rho_s=21.1/2.65=7.962\ \text{cm}^3$, leaving $V_v=V_t-V_s=11.8-7.962=3.838\ \text{cm}^3$ as void space.
Porosity, void ratio, bulk density.
$$\begin{aligned} n &=\frac{V_v}{V_t}=\frac{3.838}{11.8}=\boxed{0.325\ (32.5\%)} \\ e &=\frac{V_v}{V_s}=\frac{3.838}{7.962}=\boxed{0.482} \\ \rho_{\text{bulk}} &=\frac{M_t}{V_t}=\frac{23.1}{11.8}=\boxed{1.96\ \text{g/cm}^3}\ \text{(moist; dry bulk density }\rho_d=M_s/V_t=1.79\ \text{g/cm}^3\text{)} \end{aligned}$$
Moisture content. The pore water mass is $M_w=M_t-M_s=23.1-21.1=2.0$ g:
$$w=\frac{M_w}{M_s}=\frac{2.0}{21.1}=\boxed{0.0948\ (9.48\%)}.$$
With porosity 32.5% and only a 9.48% moisture content by mass, the sample is far from saturated (degree of saturation $S=V_w/V_v=2.0/3.838\approx52\%$), consistent with being described only as "moist."