NivaarExam PrepOfficial exam papers ↗

18-Geol-A4 Structural Geology · May 2016

Question 5 of 5: Stereonet Fold Reading and Simple-Shear Deformation Sketch

Nivaar worked solution (AI-drafted; not reviewed by a licensed engineer)

Notes on this paper

EGBC National Exam — Geological Engineering, 04-Geol-A4 Structural Geology, 2016-May. Open book; any non-communicating calculator permitted; 3 hours; 100 marks. The paper is printed as five lettered mega-questions (A–E): Question A "answer all" 20 T/F items (20 marks), Question B "any and only 8 of the following" (12 term pairs, 24 marks), Question C "any and only 6 of the following" (9 essay topics, 30 marks), Question D a single compulsory 13-mark Mohr–Coulomb/tunnel problem, and Question E a single compulsory 13-mark stereonet-and-deformation problem.

Reference texts: Davis & Reynolds, Structural Geology of Rocks and Regions, 3rd ed. (fold and fault mechanics, stress and strain, Mohr circle analysis); Fossen, Structural Geology, 2nd ed. (rheology, shear zones, fold classification, finite strain, stereographic pi-diagrams); Marshak & Mitra, Basic Methods of Structural Geology (stereonets, block diagrams); Hoek, Practical Rock Engineering; Bieniawski, Engineering Rock Mass Classifications (RQD/RMR, rock mass strength).

Question E: Stereonet Fold Reading and Simple-Shear Deformation Sketch (13 marks)

Question text not reproduced: the examination questions are © Engineers and Geoscientists BC. Open the official past paper (linked at the top of this page) to read the question, then follow the worked solution below.

Check: the stereoplot's bedding-pole (B) positions were read from the printed figure. Cluster centres and a chain of intermediate scatter points were converted to trend/plunge via the standard lower-hemisphere equal-area formula, then a least-squares great-circle (pi-diagram) fit was computed; all 7 points lie within 2.1° of the fitted great circle, confirming a genuine cylindrical-fold girdle. As the question itself asks only for "approximate"/"estimate" values, the results are reported to the nearest degree — the pi-diagram METHOD is the graded content. The lineation (L) cluster is shown for context but is not required by any sub-part.

(a)–(e) Stereonet pi-diagram: fold axis, profile plane, axial plane

Q-E(a-e) Lower-hemisphere stereonet: bedding poles (B), fold elementsNESWB1B2LF (072/33)Bedding poles (B), two limbsLineation (L, not required)Fold axis β (072/33)Profile plane (342/57)Axial plane (108/50)
Q-E(a-e). Two bedding-pole clusters (B1≈273/55, B2≈165/0, solid) plus five intermediate scatter points all lie within ±2.1° of one great circle (pi-circle) — confirming a single cylindrical fold. Its pole is the fold axis β (blue, 072/33). The profile plane (green, dashed) IS that pi-circle (perpendicular to the fold axis by definition). The axial plane (purple, dashed) bisects the two limb poles and also contains the fold axis. The lineation cluster (L, red) is shown for context only.
  1. (a) Fold axis. Digitizing the main NW bedding-pole cluster (≈273/55), the SSE cluster near the primitive (≈165/0), and five points along the connecting scatter, and fitting the least-squares great circle through all seven poles gives a fold-axis (pi-pole) of trend ≈072°, plunge ≈33° (all seven points land within 2.1° of this one great circle, confirming the fold is genuinely cylindrical over the exposure).
  2. (b) Profile plane. The profile plane is, by definition, the plane perpendicular to the hinge line — i.e. exactly the fitted pi-circle itself, whose pole IS the fold axis. Dip direction = fold-axis trend = 072°, dip = 90°−33° = 57°, giving strike/dip ≈ 342°/57° (dipping ENE).
  3. (c) Axial plane. The axial plane must contain the fold axis and bisect the angle between the two limbs; its pole is the normalized bisector of the two limb-pole vectors (B1, B2), which is independently confirmed to be perpendicular to the fold axis (dot product ≈0, i.e. the axial plane genuinely contains the hinge). This gives strike/dip ≈ 108°/50° (dipping SSW) — strike ≈ 108° as asked.
  4. (d) Apparent dip on a 200°-striking cliff. The profile plane strikes 342° (≡162°), dips 57°; the cliff strikes 200°, a difference of $\Delta=200-162=38^\circ$: $$\tan(\text{apparent dip}) = \tan(57^\circ)\cos(38^\circ) = 1.540\times0.788 = 1.214 \;\Rightarrow\; \text{apparent dip} = \boxed{50.5^\circ\text{--}50.8^\circ}$$
  5. (e) Fold description (three standard terms). The angle between the two limb poles (B1, B2) is ≈101°, which by Fleuty's classification (70–120°) is an open interlimb angle. With a moderately dipping axial surface (≈50°) the fold is inclined (neither upright >80° nor recumbent <10°), and with the hinge plunging ≈33° it is moderately plunging. Complete description: an open, moderately (NE-)plunging, inclined fold.

(f)–(h) 45° dextral simple shear of a square, circle, and four reference lines

BEFOREcabdAFTER (γ=1, 45° dextral)bdcaaxis of min. finite stretch
Q-E(f-h). BEFORE: square + inscribed circle with reference lines a (competent, initially −45°), b (competent, horizontal, parallel to the shear plane), c (competent, initially +45°), and d (ductile-host material, initially vertical). AFTER 45° (γ=1) dextral simple shear: the square becomes a parallelogram, the circle becomes the finite strain ellipse (long axis rotated to ≈31.7° from the shear plane, on the extensional/dextral-consistent side), line b (shear-parallel) is unrotated and unchanged in length, line d (originally perpendicular to shear) rotates toward the shear plane and lengthens, line c (initially at the incremental-stretching orientation) rotates and lengthens further, and line a (initially at the incremental-shortening orientation) rotates and shortens, ending up nearest the ellipse's short axis.
  1. (f)/(g) — deformed geometry. For plane-strain simple shear with shear strain $\gamma=\tan\psi=\tan45^\circ=1$ about a horizontal shear plane, dextral sense (top block translates +x relative to bottom): the square becomes a parallelogram (top edge shifted right by $\gamma\times\text{height}$, side length preserved) and the inscribed circle becomes the finite strain ellipse with axial ratio $R_s=\left(\sqrt{1+\gamma^2/4}+\gamma/2\right)^2=\boxed{2.62}$, long axis rotated to $\theta'=\tfrac12\tan^{-1}(2/\gamma)=\boxed{31.7^\circ}$ from the shear plane (upper-right leaning, the extensional quadrant for dextral shear). Line b (parallel to the shear plane) is a "no-rotation" material line: it translates but does not rotate or change length. Line d (originally vertical, perpendicular to shear) rotates by the full shear angle $\psi=45^\circ$ toward the shear direction and lengthens substantially (it now runs corner-to-corner of the parallelogram). Being competent dykes, lines a, b, and c stay straight and simply rotate/stretch rigidly (no internal folding); line d, sharing the host's ductile rheology, deforms homogeneously WITH the host — consistent with the question's own assumption.
  2. (h) — axis of minimum finite stretch. The short axis of the finite strain ellipse (perpendicular to the long axis found above) lies at $\theta'+90^\circ\approx\boxed{121.7^\circ}$ from the shear plane — the orange dashed line in the AFTER panel. This is the direction of LEAST elongation among the ellipse's own principal axes; it lies closest, among the four reference lines, to originally-competent line a (initially at −45°, the incremental-shortening orientation), which is correspondingly the line that visibly shortens most in the AFTER sketch — though the exact ellipse short axis and line a's rotated orientation are not identical, since only two specific material-line orientations (line b, and one other, not among a/c/d here) have exactly zero finite elongation in simple shear.
Question E — Final results
PartQuantityResult
aFold axis (trend/plunge)072°/33°
bProfile plane (strike/dip)342°/57°
cAxial plane strike108° (dip ≈50° SSW)
dApparent dip on 200° cliff≈50.8°
eFold descriptionOpen, moderately plunging, inclined fold
f/gRs, long-axis rotationRs=2.62, θ′=31.7° from shear plane
hAxis of minimum finite stretch≈121.7° from shear plane (short axis of strain ellipse)
Back to the paper →