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18-Geol-B1 Contaminant Hydrogeology · May 2017

Question 1 of 5: Dispersion/Diffusion Fundamentals, Isotope Hydrology, and Effective Diffusion Coefficient

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National Exams — May 2017 — 04-Geol-B1 Contaminant Hydrogeology. Three-hour, open-book exam; any non-communicating calculator permitted. Five questions constitute a complete paper and all five are of equal value; most call for an essay-format answer with clarity and organization counted. Unless stated otherwise, water density = 998 kg/m³, water viscosity = 0.001 kg/m-sec, g = 9.81 m/s², 1 atm = 101300 Pa, and R = 8.314 Pa·m³/gmol·K = 0.082 atm·L/mol·K.

Reference texts: Fetter, C.W., Contaminant Hydrogeology (2nd ed., Prentice Hall, 1999) — molecular diffusion and tortuosity, sorption/retardation, Henry's law partitioning, NAPL fate and free-product recovery, in-situ bioremediation; Domenico, P.A. & Schwartz, F.W., Physical and Chemical Hydrogeology (2nd ed., Wiley, 1997) — the Ogata-Banks advection-dispersion-reaction solution and the instantaneous-pulse (Gaussian) transport solution; Freeze, R.A. & Cherry, J.A., Groundwater (Prentice-Hall, 1979) — Darcy's law, isotope hydrology, and the Brooks-Corey capillary pressure-saturation relation; EGBC Geoscience Professional Practice Guidelines for assumption-disclosure conventions on open-book calculations.

Question 1: Dispersion/Diffusion Fundamentals, Isotope Hydrology, and Effective Diffusion Coefficient (equal value)

Question text not reproduced: the examination questions are © Engineers and Geoscientists BC. Open the official past paper (linked at the top of this page) to read the question, then follow the worked solution below.

Part (a) — True/False. Each statement is judged against the governing physics of dispersion, unsaturated flow, and remediation, with a one-line justification:

Question 1(a) — True/False answers
#Statement (abridged)AnswerReason
1No mechanical dispersion in stationary waterTrueMechanical dispersion is caused by variations in the velocity field; with zero bulk flow there is no advective spreading, so only molecular diffusion operates.
2Hydrodynamic dispersion coefficient increases with dispersivity/diffusion coeff.True$D_L=\alpha_L v+D^{*}$ — both terms add linearly, so a larger $\alpha_L$ or $D^{*}$ directly raises $D_L$.
3Darcy's Law cannot be used for unsaturated flowFalseThe Buckingham-Darcy law extends Darcy's law to unsaturated media by replacing $K$ with the saturation-dependent $K(\theta)$ or $K(\psi)$.
4Coarse-grained soils act as flow barriersFalseCoarse soils (sand/gravel) have high hydraulic conductivity and are preferential flow paths, not barriers; fine-grained clays/silts are the barriers.
5Diffusion always insignificant vs. mechanical dispersionFalseAt very low seepage velocities (e.g. clay aquitards), $D^{*}$ can dominate over $\alpha_L v$; diffusion is only negligible at typical aquifer velocities.
6Lower interfacial tension lowers capillary pressure at fixed saturationTrueYoung-Laplace: $P_c=2\sigma\cos\theta/r$ — $P_c$ is directly proportional to interfacial tension $\sigma$ at a given pore radius/saturation.
7Geothermal good for heating, impractical for cooling in North AmericaFalseGround-source heat pumps use the same shallow-earth loop for both heating (winter) and cooling (summer) — that reversibility is the technology's main advantage.
8Air relative permeability rises as air saturation fallsFalseRelative permeability of a phase increases with that phase's OWN saturation; if $S_{air}$ decreases, $k_{r,air}$ decreases (while $k_{r,water}$ rises).
9Excavation/disposal best for any situationFalseExcavation is limited by depth, footprint, cost, and disposal liability; deep or widespread plumes need in-situ methods (pump-and-treat, bioremediation, SVE).
10Hydrocarbon biodegradation always needs O₂ as electron acceptorFalseAnaerobic pathways (nitrate-, iron-, sulfate-reducing, methanogenic) also degrade hydrocarbons, just more slowly — oxygen is the acceptor, not always required, and the terminology in the question ("electron donor") is itself reversed: hydrocarbons are the donor, O₂ the acceptor.
11Biopiles always use nutrients, air, and acclimated microbesFalseBiopiles rely primarily on aeration and nutrient amendment of the native (indigenous) population; bioaugmentation with acclimated/exogenous microbes is an optional enhancement, not a universal requirement.
12Water pressure always less than air pressure in unsaturated soilTrueBy definition, matric suction $\psi=P_{air}-P_{water}>0$ in the vadose zone, so pore-water pressure is always below the air-phase pressure.

Part (b) — tritium and the meteoric water line. Tritium (³H, a radioactive hydrogen isotope with a 12.32-year half-life) enters groundwater as tritiated water molecules formed in the atmosphere by cosmic-ray spallation and, historically, by above-ground nuclear weapons testing (a large pulse peaking around 1963). Because it decays with a known half-life and its atmospheric input history is documented, tritium is used as an age tracer: a sample with tritium activity near modern atmospheric levels (or bearing the 1960s "bomb pulse" signature) contains water recharged within the last ~50-60 years, while tritium-dead water (below detection) indicates recharge that pre-dates the 1950s nuclear era. It is therefore widely used to distinguish young, recently-recharged groundwater (vulnerable to surface contamination) from old, pre-bomb water, and to estimate mean residence times in shallow flow systems when combined with a lumped-parameter age model. The stable isotopes oxygen-18 and deuterium (²H) are used differently: because both undergo similar equilibrium and kinetic fractionation during evaporation and condensation, a plot of $\delta^2\text{H}$ against $\delta^{18}\text{O}$ for global precipitation falls close to a straight line, $\delta^2\text{H}\approx 8\,\delta^{18}\text{O}+10$ (Craig, 1961), known as the Global Meteoric Water Line (GMWL). Precipitation and groundwater recharged directly from precipitation plot on or near this line; samples that plot to the right of/below the line (a lower slope, an "evaporation trend") have undergone evaporative enrichment of the heavy isotopes before or during infiltration — e.g. water that stood in a surface reservoir, wetland, or was affected by evapotranspiration in the unsaturated zone. Comparing a groundwater sample's isotopic composition against the local/global meteoric water line is therefore a standard tool for identifying the recharge source and whether evaporation has modified the water before it entered the aquifer.

Given. Part (c): free-water molecular diffusion coefficient $D_0=2\times10^{-5}\ \text{cm}^2/\text{s}$ for Cl⁻, porosity $n=0.3$, tortuosity $\tau=1.22$.

Find. The effective diffusion coefficient $D_e$ of Cl⁻ in the saturated porous medium.

Approach. Convert the free-solution diffusion coefficient to a porous-medium value using the standard tortuosity correction, which scales $D_0$ down by the medium's porosity and up by the reciprocal of its tortuosity (the actual diffusion path is longer and partly obstructed by solids).

  1. Effective diffusion coefficient. $$D_e=\frac{D_0\,n}{\tau}=\frac{(2\times10^{-5})(0.3)}{1.22}=\boxed{4.92\times10^{-6}\ \text{cm}^2/\text{s}}.$$ The porous medium diffuses Cl⁻ roughly four times slower than free water, because only 30% of the cross-section is available for transport and the tortuous path is about 1.22× longer than a straight line.
Question 1 — Final Results
ItemResult
1(a) True/False (12 items)T,T,F,F,F,T,F,F,F,F,F,T (see table above)
1(b)Tritium = radioactive age tracer (bomb-pulse/decay); meteoric water line = $\delta^2\text{H}=8\delta^{18}\text{O}+10$, the precipitation baseline for spotting evaporation
1(c) Effective diffusion coefficient $D_e$$4.92\times10^{-6}\ \text{cm}^2/\text{s}$
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