23-Ind-A5 Quality Planning, Control, and Assurance · May 2017
Nivaar worked solution (AI-drafted; not reviewed by a licensed engineer)
National Exams, May 2017. Closed-book examination. Any five of the six questions constitute a complete paper; all six are answered in full below. Relevant statistical tables (cumulative standard normal distribution, factors for constructing variables control charts, the F distribution, and a blank Weibull probability chart) are reproduced/applied from the paper's own attached appendices.
Reference texts: Montgomery, Introduction to Statistical Quality Control (8th ed.) — Ch. 1–2 (quality philosophy, cost of quality, Six Sigma/DMAIC), Ch. 5–6 (variables control charts: X̄-R, X̄-S, process capability), Ch. 7 (attributes charts: p, np, c, u, demerit systems), Ch. 9 (CUSUM and EWMA control charts), Ch. 8 & 13 (reliability, life testing and Weibull analysis; designed experiments and factorial designs).
Question text not reproduced: the examination questions are © Engineers and Geoscientists BC. Open the official past paper (linked at the top of this page) to read the question, then follow the worked solution below.
Production processes exhibit two types of variation. Common-cause (chance) variation is the aggregate of many small, inherent sources — material, machine, environment, operator — that are always present; it is random, stable, and describable by a fixed probability distribution. Special-cause (assignable) variation arises from a specific, identifiable event (a tool wearing out, a bad lot of raw material, an untrained operator) that shifts the process away from its stable distribution. A process is said to be in statistical control when only common-cause variation is present, so that the process mean and variance are constant over time and all future output can be predicted from the historical distribution — operationally, this is the state in which every point on the control chart falls within the control limits with no non-random patterns.
Standard Shewhart charts assume a stationary mean and can give a very poor (often misleadingly "in control") picture when the process exhibits a genuine natural trend (e.g. gradual tool wear steadily shrinking a bore diameter). Two adaptations handle this: (1) fit and subtract the deterministic trend first, then chart the residuals on an ordinary X̄ chart (residuals are approximately stationary if the trend model is adequate); or (2) use a chart designed for trending/autocorrelated data, such as a regression control chart with control limits around the fitted trend line, or an EWMA/CUSUM tuned as an engineering-process-control adjustment. Example: a chart of bore diameter vs. tool-change cycle shows a steady downward drift of about 0.001 mm per part; plotting the residuals from a fitted regression line on a standard X̄ chart correctly separates the expected wear trend from a genuine special-cause jump.
The run length (RL) is the number of samples plotted before a chart first signals (a point outside the control limits, or a run-rule violation). The average run length (ARL) is its expectation; for a chart with false-alarm/detection probability $p$ per sample, $RL$ is geometric with $E[RL]=1/p$. The average time to signal (ATS) converts this to real time: $ATS=ARL\times h$, where $h$ is the sampling interval. Sample size effect: increasing $n$ narrows the control limits (they scale as $1/\sqrt n$ around the centre line) for a FIXED shift size, so a given real shift produces a larger standardized deviation and is detected faster — ARL decreases (chart becomes more sensitive) as $n$ increases, at the cost of more inspection per sample.
Given. $m=40$ samples of size $n=5$; $\sum\bar X_i=18{,}740$; $\sum R_i=680$. From the paper's own Appendix VI (Factors for Constructing Variables Control Charts), for $n=5$: $A_2=0.577$, $D_3=0$, $D_4=2.115$, $d_2=2.326$.
Find. The X̄ and R chart control limits and the in-control estimates $\hat\mu$, $\hat\sigma$.
Approach. Compute the grand average $\bar{\bar X}$ and average range $\bar R$ from the given sums, then apply the standard $A_2$/$D_3$/$D_4$ factor relations for the control limits and $\bar R/d_2$ for the process standard deviation.
| Quantity | Value |
|---|---|
| Grand average $\bar{\bar X}$ | 468.5 |
| Average range $\bar R$ | 17.0 |
| X̄ chart limits | LCL = 458.69, UCL = 478.31 |
| R chart limits | LCL = 0, UCL = 35.96 |
| In-control mean $\hat\mu_0$ | 468.5 |
| In-control std. dev. $\hat\sigma_0$ | 7.309 |
Given. From part (b): $\hat\mu_0=468.5$, $\hat\sigma_0=7.309$. Specification $470\pm25$, i.e. $LSL=445$, $USL=495$. The chart is to be re-designed with 3-sigma limits so that $ARL\le5$ when the mean shifts from $\mu_0$ to $\mu_0+1.2\sigma$.
Find. $C_p$, $C_{pk}$, the process fraction nonconforming, and the sample size $n$ (with resulting control limits) that meets the ARL target.
Approach. Compute $C_p$/$C_{pk}$ from the spec width and $\hat\sigma_0$; get the nonconforming fraction from the standard normal CDF at each specification limit; then scan integer $n$ in the ARL formula for a $k=3$-sigma chart until the target shift's ARL first drops to 5 or below.
| Quantity | Value |
|---|---|
| $C_p$ | 1.140 |
| $C_{pk}$ | 1.072 |
| Process fraction nonconforming | 0.0795% (795 ppm) |
| Required sample size for $ARL\le5$ at a $1.2\sigma$ shift | $n=4$ |
| Re-designed X̄ chart limits ($n=4$) | LCL = 457.54, UCL = 479.46 |