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21-Mat-B6 Ceramic Materials · December 2013

Question 5 of 7: Driving Forces and the Micro-Mechanism of Martensite Formation

Nivaar worked solution (AI-drafted; not reviewed by a licensed engineer)

Notes on this paper

Reference texts: Reed-Hill & Abbaschian, Physical Metallurgy Principles, 4th ed.; Callister & Rethwisch, Materials Science and Engineering: An Introduction, 10th ed.; ASM Handbook, Vol. 4, Heat Treating; Porter, Easterling & Sherif, Phase Transformations in Metals and Alloys, 3rd ed.; Krauss, Steels: Processing, Structure, and Performance, 2nd ed.


Question V: Driving Forces and the Micro-Mechanism of Martensite Formation (15 marks)

Question text not reproduced: the examination questions are © Engineers and Geoscientists BC. Open the official past paper (linked at the top of this page) to read the question, then follow the worked solution below.

Check: sub-part (iii) here is printed identically as Question IV(iii) on the exam — both ask, word for word, "Why does the hardness of martensite increase[s] with increasing C content for most structural steels?" The paper genuinely repeats this sub-question, so the full answer is given at both locations below for a self-contained reading of each question.

5.1 — (i) Driving force: martensite vs. pearlite

Both transformations are ultimately driven by the same thermodynamic quantity — the Gibbs free-energy difference $\Delta G_v = G_{austenite}-G_{product}$, which becomes negative (favourable) as the steel is undercooled below a reference equilibrium temperature: $A_1$ (the eutectoid temperature) for pearlite, and $T_0$ (the temperature at which austenite and diffusionless martensite of the SAME composition have equal free energy) for martensite. The key DIFFERENCE is how much undercooling each needs, and why. Austenite→pearlite is a diffusional, nucleation-and-growth transformation that is overall composition-invariant (pearlite's average composition equals the parent austenite's) but requires long-range carbon partitioning between the forming ferrite and cementite lamellae; a comparatively small undercooling below $A_1$ (tens of degrees) already supplies enough driving force, because atomic mobility just below $A_1$ is still fast and does the rest of the work. Austenite→martensite is diffusionless (see part ii) and forms with NO change in composition at all, so it gets no assistance from a diffusion/partitioning contribution to the free energy; it must instead be driven by the chemical free-energy difference ALONE, which only becomes large enough to nucleate martensite — overcoming a substantial shear-strain and interfacial-energy barrier as well — at a much larger undercooling, i.e. cooling well below $T_0$, down to $M_s$, which lies far below $A_1$ for essentially every steel. In short: both are driven by undercooling-generated $\Delta G_v$, but pearlite needs only a small $\Delta G_v$ because diffusion assists it, while martensite needs a very large $\Delta G_v$ because it must unassisted supply both the chemical driving force and the extra non-chemical energy a diffusionless shear transformation demands.

5.2 — (ii) Micro-mechanism of martensite formation

Martensite forms by a diffusionless, cooperative SHEAR ("military," not "civilian") mechanism: on cooling below $M_s$, small regions of austenite transform almost instantaneously (an individual plate/lath forms in roughly $10^{-7}$ s, propagating near the speed of sound in the lattice) by a coordinated, homogeneous shear-plus-volume-change distortion of the parent FCC austenite lattice into the body-centred tetragonal (BCT) martensite lattice. This is classically described by the Bain distortion — a compression along one FCC axis and an expansion along the other two converts the FCC cell into the BCT cell — modified by additional, lattice-invariant shears (fine internal slip or twinning within the plate) that accommodate the overall shape change while keeping a coherent, unrotated HABIT PLANE with the surrounding parent austenite. Because there is no long-range diffusion, EVERY carbon atom that was in interstitial solution in the parent austenite is carried over, trapped, into the martensite's own octahedral interstitial sites — this supersaturation is what produces the tetragonal distortion and high hardness discussed in part (iii). The transformation is ATHERMAL: the fraction transformed depends only on how far below $M_s$ the steel has been cooled (each further increment of undercooling triggers a fresh burst of new plates), not on how long it is held at a given temperature — unlike the isothermal, diffusional pearlite/bainite reactions — and it proceeds only while temperature keeps falling, stopping at $M_f$ (or earlier, if remaining retained austenite becomes mechanically stabilized).

5.3 — (iii) Why martensite hardness rises with carbon content

As in Question IV(iii): martensite is a diffusionless, supersaturated interstitial solid solution of carbon trapped in a body-centred tetragonal (BCT) iron lattice, rather than the cubic lattice a diffusional product would allow. Carbon that would ordinarily partition into cementite is instead frozen in octahedral interstitial sites, distorting the surrounding lattice anisotropically along the tetragonal $c$-axis (the $c/a$ ratio rises roughly linearly with wt% C). This distortion generates strong local strain fields that strongly resist dislocation motion — interstitial solid-solution strengthening — so a higher parent-austenite carbon content, carried over unchanged into the martensite, produces a larger $c/a$ distortion and correspondingly higher hardness, up to the point (roughly 0.6–0.8 wt% C) where the benefit saturates and increasing retained-austenite content begins to work against further hardness gain.