NivaarExam PrepOfficial exam papers ↗

21-Mat-B6 Ceramic Materials · May 2013

Question 1 of 7: Microstructure of a Hypoeutectoid Steel — Micrograph Interpretation

Nivaar worked solution (AI-drafted; not reviewed by a licensed engineer)

Notes on this paper

Reference texts: Reed-Hill & Abbaschian, Physical Metallurgy Principles, 4th ed.; Callister & Rethwisch, Materials Science and Engineering: An Introduction, 10th ed.; ASM Handbook, Vol. 4, Heat Treating; Porter, Easterling & Sherif, Phase Transformations in Metals and Alloys, 3rd ed.

Question I: Microstructure of a Hypoeutectoid Steel — Micrograph Interpretation (10 marks)

Question text not reproduced: the examination questions are © Engineers and Geoscientists BC. Open the official past paper (linked at the top of this page) to read the question, then follow the worked solution below.

1.1 — (i) Phases at the two marked regions

The exam states the sample's carbon content is below the eutectoid composition (0.77 wt% C), i.e. this is a hypoeutectoid steel. On slow cooling through the austenite (γ) field, such a steel always deposits its excess-over-eutectoid ferrite FIRST, as a proeutectoid phase, before the remaining (now eutectoid-composition) austenite transforms at 727 °C. That two-population story is exactly what the micrograph shows.

[Figure not reproduced: Micrograph of a hypoeutectoid steel as printed on the exam, with the two boxed/arrowed regions. See the official exam paper or the cited reference text.]

Fig. 1.1 — Micrograph as printed on the exam. Left arrow/box: fine, dark, needle/lamellar-textured region filling most of the field. Right arrow/box: a light, blocky patch that is part of a light-toned network tracing the prior-austenite grain boundaries.

The left arrow/box sits inside the fine, dark, closely spaced needle/plate-textured region that fills most of the field — this is pearlite, the lamellar eutectoid mixture of ferrite and cementite (α + Fe3C) formed when the carbon-enriched residual austenite crossed 727 °C. The fine alternating lamellae scatter light at this magnification and read dark/textured rather than as two distinct grey levels. The right arrow/box sits on a lighter, blockier patch that is part of a continuous light-toned network tracing what were the prior-austenite grain boundaries — this is proeutectoid ferrite (α), the primary phase that nucleated and grew along those boundaries while the steel was still above 727 °C.

1.2 — (ii) How this microstructure was produced

The specimen was first fully austenitized — heated above its upper critical (A3) temperature into single-phase γ — then cooled slowly (furnace-cooled/full-annealed, or at most air-cooled) through the α+γ two-phase field down past 727 °C. Slow, near-equilibrium cooling gives carbon time to diffuse: proeutectoid ferrite nucleates heterogeneously at the prior-austenite grain boundaries (the lowest-energy, easiest nucleation site) and grows inward, rejecting carbon into the shrinking pool of untransformed austenite as it does. By the time the sample reaches 727 °C, the remaining austenite has been enriched to the eutectoid composition (0.77 wt% C) and transforms there by the eutectoid reaction γ → α + Fe3C (pearlite), filling the grain interiors. The continuous, boundary-hugging character of the light ferrite network (rather than isolated equiaxed grains or acicular/Widmanstätten plates driven into the grain interior) is itself evidence of a slow, diffusion-controlled anneal rather than a fast air- or oil-quench.

1.3 — (iii) Higher or lower than 0.4 wt% C?

Check: the qualitative reading below is supported by the printed micrograph. Treating the printed image as a two-population halftone (smooth, bright patches = ferrite; finely textured patches, bright or dark, = pearlite) gives an estimated ferrite area fraction of roughly 10% of the field — a rough estimate, but unambiguously a minority phase, not close to half the field.

By the lever rule on the Fe–Fe3C diagram, the proeutectoid-ferrite weight fraction expected in a hypoeutectoid steel of composition C0 just below 727 °C is

$$W_\alpha=\dfrac{0.77-C_0}{0.77-0.022}$$

A steel at exactly the 0.4 wt% C threshold named in the question would give $W_\alpha=(0.77-0.40)/(0.77-0.022)\approx0.49$, i.e. proeutectoid ferrite should occupy roughly half the field. The micrograph instead shows pearlite as the overwhelming majority phase and ferrite confined to a thin grain-boundary network — nowhere near 50%. That is only consistent with a carbon content higher than 0.4 wt% (closer to, but still below, the 0.77 wt% eutectoid composition — the ∼10% ferrite estimate above corresponds to roughly 0.7 wt% C by the same lever rule, offered as an illustrative order-of-magnitude figure rather than a graded number).

← Paper overview