22-Mec-A4 Design and Manufacture of Machine Elements · December 2014
Nivaar worked solution (AI-drafted; not reviewed by a licensed engineer)
Paper format. National Examinations, December 2014 — 07-Mec-A4, Design and Manufacture of Machine Elements. Three hours, open book, any non-communicating calculator permitted. Six questions divided into Part A (Q1–Q3, manufacturing processes) and Part B (Q4–Q6, machine elements); candidates answer two from Part A and two from Part B, and all questions carry equal value (25 % each). All six questions are worked here.
Reference texts.
it reports a single 5,200 N load and a dimension chain of 750 + 450 + 450 = 1,650 mm that "contradicts" the 2,400 mm overall. Q5 is solved against the drawing, not the caption. Likewise in Q4 the 3,000 lb load is read from the drawing as a horizontal force applied through the bolted plate on the neutral axis, and the section as a 8 in deep I-beam (1⁄2 + 31⁄2 + 31⁄2 + 1⁄2).
Question text not reproduced: the examination questions are © Engineers and Geoscientists BC. Open the official past paper (linked at the top of this page) to read the question, then follow the worked solution below.
Both processes are responses to the same stored driving force. Plastic deformation at low homologous temperature multiplies dislocations from an annealed density of order 1010 m−2 to something approaching 1015 m−2, and tangles them into cells. Perhaps one to five per cent of the plastic work done is retained in the lattice as the elastic strain energy of those dislocations; the remainder appears as heat. That retained energy makes the cold-worked state thermodynamically unstable, and on heating the metal spends it. How it spends it is what distinguishes the two processes.
Recovery proceeds by the motion and mutual annihilation of existing dislocations, without the creation of any new grains. At modestly elevated temperature vacancies become mobile enough to permit dislocation climb, and screw segments cross-slip. Two edge dislocations of opposite sign that lie on nearby slip planes can therefore come together and annihilate, removing both. Those that survive migrate into the lowest-energy arrangement available to them, which is a vertical wall of like-signed edge dislocations — a low-angle tilt boundary. This rearrangement is called polygonization, and it subdivides the original grain into subgrains misoriented from one another by a fraction of a degree up to a few degrees. Crucially, the original grains keep their identity, their shape and their crystallographic orientation: an elongated, cold-rolled grain remains an elongated grain. Point defects also anneal out, which is why electrical resistivity recovers almost fully during this stage, and macroscopic residual stresses relax. Because a substantial dislocation density survives, the strength is only slightly reduced.
Recrystallization proceeds instead by nucleation and growth of entirely new, strain-free grains. Small, nearly perfect volumes — typically subgrains that have grown, or regions at prior grain boundaries and deformation bands where the local misorientation is greatest — develop high-angle boundaries with their surroundings. A high-angle boundary is mobile in a way a low-angle boundary is not, and it sweeps through the deformed matrix. Every atom it passes is transferred from the strained lattice to the new, essentially dislocation-free one. The driving force is the difference in stored dislocation energy across the boundary, and the process consumes the cold-worked structure entirely, replacing elongated grains with new equiaxed ones. Dislocation density falls by four to five orders of magnitude, back to the annealed value. The property changes are therefore drastic rather than marginal.
Three consequences follow that are worth stating explicitly, because they are what an examiner is testing. First, recrystallization requires a minimum amount of prior cold work; below a critical strain (of order a few per cent) there is insufficient stored energy and no driving force, and the metal will only recover. Second, the recrystallization temperature is not a material constant but falls as the prior strain rises and as the annealing time is extended, being roughly 0.3–0.5 of the absolute melting temperature. Third, recrystallization is the reason hot working does not work-harden: above the recrystallization temperature the structure re-forms as fast as it is deformed. If heating continues past recrystallization, the new grains coarsen by grain growth, driven now by grain-boundary area rather than by stored strain energy, which softens the metal further via the Hall–Petch relation and is normally undesirable.
The two diagrams show the characteristic behaviour. Through the recovery range, yield strength and tensile strength fall only slightly and elongation rises only slightly, because the dislocation population is rearranged but not substantially removed. Through the recrystallization range both strengths drop steeply and elongation rises steeply, as the strain-free grains replace the work-hardened matrix. Two details are worth noting. The yield strength falls proportionally further than the tensile strength, so the yield-to-tensile ratio drops and the metal recovers its capacity to strain-harden. And the elongation curve is very nearly the mirror image of the strength curves, which is the familiar strength–ductility trade-off read in reverse: annealing buys back the ductility that cold work spent.