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22-Mec-B8 Engineering Materials · December 2016

Question 2 of 8: Composition of a barium-borate glass-ceramic in weight percent

Nivaar worked solution (AI-drafted; not reviewed by a licensed engineer)

Notes on this paper

Paper format. National Exams, December 2016 — 07-Mec-B8 Engineering Materials. Three hours, open book; any non-communicating calculator permitted. Eight problems, all of equal value; any FIVE constitute a complete paper, so each problem is worth 20 marks. Candidates are urged to submit a clear statement of any assumptions made. All eight problems are solved below, because the set as a whole is the study resource.

Reference texts (22-Mec-B8 Engineering Materials).

  • Askeland & Wright, The Science and Engineering of Materials, 7th ed. — the primary syllabus text.
  • Callister & Rethwisch, Materials Science and Engineering: An Introduction, 10th ed.
  • Dieter, Mechanical Metallurgy, 3rd ed. — Considère's construction and plastic instability.
  • Shackelford, Introduction to Materials Science for Engineers, 8th ed. — ceramics, glasses and glass-ceramics.
  • Fontana, Corrosion Engineering, 3rd ed. — galvanic series, sacrificial protection and Faraday's law.
  • Ashby, Materials Selection in Mechanical Design, 5th ed. — selection criteria and material indices.
  • Polmear, Light Alloys, 5th ed. — aluminium tempers, Al–Li alloys and maraging steels.

Question 2: Composition of a barium-borate glass-ceramic in weight percent (20 marks)

Question text not reproduced: the examination questions are © Engineers and Geoscientists BC. Open the official past paper (linked at the top of this page) to read the question, then follow the worked solution below.

Given. A batch of 8.5 mole per cent TiO2 nucleating agent in 91.5 mole per cent of the barium-borate glass BaO·4B2O3, with atomic weights read from the periodic table.

Given data
QuantityValue
Glass formerBaO·4B2O3
Nucleating agentTiO2, 8.5 mole%
Atomic weight of Ba137.33
Atomic weight of B10.81
Atomic weight of O16.00
Atomic weight of Ti47.87

Find. The composition of the resulting glass-ceramic in weight percent. The question asks for the atomic weights “of each component element,” so the answer is reported on the oxide basis (which is how a batch is actually weighed out) and again on the elemental basis (which is what those atomic weights directly give).

Approach. Take a convenient basis of 100 moles of batch, convert each constituent from moles to mass through its formula weight, and express each mass as a percentage of the total. The whole calculation is one mole-to-mass conversion carried out three ways.

  1. Build the formula weights from the atomic weights. Adding the constituent atoms, $$M_{\text{BaO}} = 137.33 + 16.00 = 153.33$$ $$M_{\text{B}_{2}\text{O}_{3}} = 2(10.81) + 3(16.00) = 69.62$$ so the glass itself, one BaO with four B2O3, weighs $$M_{g} = 153.33 + 4(69.62) = \boxed{431.81\ \text{g/mol}}$$ and the nucleating agent weighs $M_{\text{TiO}_{2}} = 47.87 + 2(16.00) = 79.87$ g/mol. The glass unit is 5.4 times heavier than the titania unit, and that single ratio governs everything that follows.
  2. Choose a basis and convert moles to mass. Taking 100 mol of batch, of which 8.5 mol is TiO2 and the remaining 91.5 mol is glass: $$m_{g} = 91.5(431.81) = 39\,510.62\ \text{g}$$ $$m_{t} = 8.5(79.87) = 678.90\ \text{g}$$ and the batch total is $m_{tot} = 40\,189.51$ g. Every percentage below is a fraction of this one number.
  3. Report the two batch constituents in weight percent. Dividing through, $$\text{wt\% glass} = \frac{39\,510.62}{40\,189.51}\times100, \; \text{wt\% TiO}_{2} = \frac{678.90}{40\,189.51}\times100$$ which gives $$\boxed{98.31\ \text{wt\% BaO}\cdot4\text{B}_{2}\text{O}_{3} \; \text{and} \; 1.69\ \text{wt\% TiO}_{2}}$$ The contrast with the 8.5 mole per cent charged is the point of the question: a noticeable molar addition is a very small weight addition, because the heavy component is the one present in the majority.
  4. Break the glass into its own oxides. Each of the 91.5 mol of glass carries one mole of BaO and four of B2O3, so $$\text{wt\% BaO} = \frac{91.5(153.33)}{40\,189.51}\times100 = 34.91\%$$ $$\text{wt\% B}_{2}\text{O}_{3} = \frac{91.5\times4\times69.62}{40\,189.51}\times100 = 63.40\%$$ Together with the 1.69 per cent TiO2 these sum to 100.00 per cent, which is the arithmetic check.
Glass-ceramic composition on an oxide basis (weight percent)BaO 34.91%B₂O₃ 63.40%TiO₂ 1.69%Eight and a half mole percent of the nucleating agent is under two weight percent,because TiO₂ is by far the lightest of the three formula units.
Composition of the glass-ceramic on an oxide basis. Boron oxide dominates the mass even though barium is by far the heaviest element present, because there are four B2O3 units for every BaO.

The oxide statement above is what a batch house would weigh out. The question, however, asks for the atomic weights of each component element, so the same 40 189.51 g is now split element by element.

  1. Count the atoms of each element in 100 mol of batch. The glass contributes 91.5 mol Ba, $91.5\times4\times2 = 732$ mol B and $91.5(1 + 12) = 1189.5$ mol O; the nucleating agent contributes 8.5 mol Ti and 17 mol O, for 1206.5 mol O in all.
  2. Convert to mass and divide. Multiplying each count by its atomic weight, $$m_{\text{Ba}} = 12\,565.70,\; m_{\text{B}} = 7\,912.92,\; m_{\text{Ti}} = 406.90,\; m_{\text{O}} = 19\,304.00\ \text{g}$$ These sum to 40 189.51 g, matching the batch total exactly, so no atom has been lost. Expressed as percentages, $$\boxed{31.27\%\ \text{Ba},\; 19.69\%\ \text{B},\; 1.01\%\ \text{Ti},\; 48.03\%\ \text{O}}$$

Oxygen is very nearly half the mass of the material, which is characteristic of every oxide glass and is worth carrying as a sanity check: an elemental analysis of a borate or silicate that does not return roughly 45 to 55 per cent oxygen has an arithmetic error in it. The titanium content, at barely one per cent by weight, is equally typical — a nucleating agent has only to seed crystallisation, not to build the network, so it is added in small amounts. On the reheat, the TiO2 phase-separates into a dense population of nuclei on which the barium-borate crystals then grow, converting the parent glass into a fine-grained glass-ceramic with far better strength and thermal-shock resistance.

Composition of the glass-ceramic in weight percent
BasisConstituentWeight percent
Batch constituentsBaO·4B2O3 glass98.31%
TiO21.69%
OxidesBaO34.91%
B2O363.40%
TiO21.69%
ElementsBa31.27%
B19.69%
Ti1.01%
O48.03%