Question 3 of 5: Approximate Equivalent Circuit From Open- and Short-Circuit Tests
Nivaar worked solution (AI-drafted; not reviewed by a licensed engineer)
Notes on this paper
Paper format. 16-Mex-B10, Power Systems and Machine
Drives, National Examinations December 2019 — a three-hour closed-book examination with one double-sided 8½″×11″ aid sheet permitted (no worked solutions or diagrams on it) and an approved Casio or Sharp calculator. The cover page states that FIVE (5) questions constitute a complete exam paper, all of equal value; all five printed questions are worked here. Unless stated otherwise, AC
voltages/currents are rms and three-phase quantities are line-to-line voltages with total
real power.
Reference texts. S.J. Chapman, Electric Machinery
Fundamentals, 5th ed. (Ch. 1 magnetic circuits and reluctance; Ch. 2 transformer
equivalent circuits and open/short-circuit testing; Ch. 4 induction motors and
power-factor correction; Ch. 6 synchronous-motor power-angle characteristics).
Question 3: Approximate Equivalent Circuit From Open- and Short-Circuit Tests (20 marks)
Given. Rating 75 kVA, 2200/220 V, 60 Hz; OC test run on the 220 V (LV)
side: VOC=220 V, IOC=9.6 A, POC=710 W; SC test run on the
2200 V (HV) side: VSC=42 V, ISC=57 A, PSC=1030 W.
Find. The approximate (cantilever) equivalent-circuit elements
Req, Xeq, Rc, Xm referred to the 2200 V side,
and a sketch of the circuit.
Approach. The OC test (rated LV voltage, secondary open) isolates the
shunt exciting branch; the SC test (reduced HV voltage, secondary shorted) isolates the
series branch. Compute each on the side it was tested and refer the OC-side result to the
HV side by the turns ratio squared.
OC test — exciting admittance on the test (LV) side.
$$\begin{aligned}
Y_{OC}&=\frac{I_{OC}}{V_{OC}}=\frac{9.6}{220}=0.04364\ \text{S}\\
\theta_{OC}&=\cos^{-1}\!\left(\frac{P_{OC}}{V_{OC}I_{OC}}\right)=\cos^{-1}\!\left(\frac{710}{2112}\right)=70.36^{\circ}
\end{aligned}$$
$$G_{OC}=Y_{OC}\cos\theta_{OC}=0.01467\ \text{S}\ \Rightarrow\ R_{c,LV}=\frac{1}{G_{OC}}=68.17\ \Omega$$
$$B_{OC}=Y_{OC}\sin\theta_{OC}=0.04110\ \text{S}\ \Rightarrow\ X_{m,LV}=\frac{1}{B_{OC}}=24.33\ \Omega$$
Refer the shunt branch to the HV side. With
a = 2200/220 = 10, impedances scale by a² = 100:
$$R_c=68.17(100)=\boxed{6817\ \Omega},\qquad X_m=24.33(100)=\boxed{2433\ \Omega}$$
SC test — series impedance, already on the HV side.
$$\begin{aligned}
Z_{SC}&=\frac{V_{SC}}{I_{SC}}=\frac{42}{57}=0.7368\ \Omega\\
\theta_{SC}&=\cos^{-1}\!\left(\frac{P_{SC}}{V_{SC}I_{SC}}\right)=\cos^{-1}\!\left(\frac{1030}{2394}\right)=64.52^{\circ}
\end{aligned}$$
(a) Series R and X.
$$R_{eq}=Z_{SC}\cos\theta_{SC}=\boxed{0.317\ \Omega},\qquad
X_{eq}=Z_{SC}\sin\theta_{SC}=\boxed{0.665\ \Omega}$$
(b) Approximate (cantilever) equivalent circuit referred to the
2200 V (HV) side: series Req+jXeq from the SC test, shunt
Rc ∥ jXm (drawn at the input terminals, the standard
"approximate" simplification) from the OC test referred by a².