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24-MMP-A6 Mining and the Environment · Undated paper

Question 3 of 6: Mining Waste and Management – Waste Rock

Nivaar worked solution (AI-drafted; not reviewed by a licensed engineer)

Notes on this paper

EGBC National Exam — Mining and Mineral Processing Engineering, 09-MMP-A6 Mining and the Environment, undated sitting (the exam's own page header reads "National Examinations, May 2019"). 3 hours duration, open book (any non-communicating calculator permitted). Unlike most sittings of this subject, this paper's own Note 3 states "Complete all SIX questions" – there is no five-of-six choice, so all 120 marks are compulsory. Most questions require an essay-format or point-form answer; clarity and organization are explicitly assessed.

Reference texts: International Network for Acid Prevention (INAP), Global Acid Rock Drainage (GARD) Guide (ARD prediction, static and kinetic testing, treatment); Price, W.A., MEND Report 1.20.1, Prediction Manual for Drainage Chemistry from Sulphidic Geologic Materials (1997/2009); Government of Canada, Metal and Diamond Mining Effluent Regulations (MDMER, SOR/2002-222, the current name for the exam's "MMER") under the Fisheries Act (R.S.C. 1985, c. F-14); Government of Canada, Canadian Environmental Protection Act, 1999 (S.C. 1999, c. 33); Government of Canada, Impact Assessment Act (S.C. 2019, c. 28, successor to the 2012 Canadian Environmental Assessment Act); Government of Canada, Species at Risk Act (S.C. 2002, c. 29); BC Ministry of Energy, Mines and Low Carbon Innovation, Health, Safety and Reclamation Code for Mines in British Columbia (current edition); Canadian Dam Association (CDA), Dam Safety Guidelines (2013/2019 update); Global Industry Standard on Tailings Management (GISTM, 2020); Vick, S.G., Planning, Design, and Analysis of Tailings Dams (1990).

Question 3: Mining Waste and Management – Waste Rock (20 marks)

Question text not reproduced: the examination questions are © Engineers and Geoscientists BC. Open the official past paper (linked at the top of this page) to read the question, then follow the worked solution below.

A. General

i. Waste rock is uneconomic, sub-cut-off-grade rock and overburden that must be removed to access ore, and which is not sent to the mill for processing; it is typically stored in surface piles or dumps.

ii. Static vs. kinetic testing. Static testing (acid-base accounting) is a single-point laboratory measurement comparing a sample's acid potential (from total/sulphide sulphur) against its neutralization potential to give a snapshot ratio (NPR); it is fast and cheap but says nothing about reaction rate. Kinetic testing (humidity cells, column tests) instead cycles a sample through repeated wet/dry leaching over weeks to months, measuring the actual rate and lag time before acid generation begins – essential for samples that static testing flags as "possible/uncertain."

iii. Top-Down vs. Bottom-Up storage. Top-down (end-dump) construction places waste rock by tipping from the crest of an advancing dump face, letting coarser material roll and segregate to the toe; it is fast and low-cost but offers little control over material placement or compaction. Bottom-up (paddock-dump) construction places and compacts waste rock in engineered horizontal lifts from the base upward, which is slower and costlier but is used where selective handling – e.g. keeping potentially acid-generating (PAG) material encapsulated away from the surface and water table – is required.

iv. A common sulfide mineral in waste rock is pyrite ($FeS_2$).

v. AMD vs. ARD. Acid Rock Drainage (ARD) is the broad term for acidic, metal-laden drainage from the oxidation of sulphide minerals in any exposed rock, including natural, unmined outcrops. Acid Mine Drainage (AMD) is the narrower term specifically for such drainage originating from mine wastes – waste rock, tailings, pit walls and underground workings – i.e. AMD is a subset of ARD caused directly by mining activity.

vi. Electrochemical mechanism. Pyrite oxidation proceeds as an electrochemical cell reaction on the mineral grain surface: an anodic site oxidizes Fe and S (releasing electrons, Fe$^{2+}\rightarrow$Fe$^{3+}$ and S$\rightarrow$SO$_4^{2-}$), while a spatially separate cathodic site on the same (semi-conductive) sulphide grain consumes those electrons by reducing dissolved oxygen; electrons flow slowly through the mineral lattice from anode to cathode, which is why the overall reaction proceeds gradually rather than instantaneously once sulphides are exposed to oxygen and water.

B. The four acid-generation equations, and balancing Equation 4

$$FeS_2 + \tfrac{7}{2}O_2 + H_2O \rightarrow Fe^{2+} + 2SO_4^{2-} + 2H^+ \quad (1)$$

Equation (1) is the primary oxidation of pyrite by dissolved oxygen, releasing ferrous iron, sulphate and acidity (H$^+$) directly – this is the initiating step of acid generation.

$$Fe^{2+} + \tfrac{1}{4}O_2 + H^+ \rightarrow Fe^{3+} + \tfrac{1}{2}H_2O \quad (2)$$

Equation (2) oxidizes the ferrous iron produced in (1) to ferric iron; at pH below about 4 this step is very slow abiotically and becomes the rate-limiting step of the overall process, but is strongly catalyzed biologically by iron-oxidizing bacteria such as Acidithiobacillus ferrooxidans.

$$Fe^{3+} + 3H_2O \rightarrow Fe(OH)_3 + 3H^+ \quad (3)$$

Equation (3) is the hydrolysis and precipitation of ferric iron as ferric hydroxide (the orange "yellow boy" precipitate seen in AMD-impacted streams), which itself releases further acidity.

Equation (4) as printed on the exam ($FeS_2 + Fe^{3+} + H_2O \leftrightarrow Fe^{2+} + SO_4^{2-} + H^+$) is the self-propagating step: ferric iron generated in (2) now acts as the oxidant attacking fresh pyrite directly (faster than dissolved oxygen at low pH), which is what makes AMD a self-sustaining cycle once initiated. Balancing it by conserving Fe, S, O, H and charge gives:

$$FeS_2 + 14Fe^{3+} + 8H_2O \rightarrow 15Fe^{2+} + 2SO_4^{2-} + 16H^+ \quad \boxed{(4,\ \text{balanced})}$$

Check: Fe, $1+14=15$ both sides; S, $2=2\times1$; O, $8\times1=2\times4$; H, $8\times2=16\times1$; charge, $14(+3)=+42$ on the left equals $15(+2)+2(-2)+16(+1)=+42$ on the right.

C. Negative effects of AMD on the environment

D. Prevention/treatment methods

E. Northern Canada considerations