25-Nav-A1 Fundamentals of Naval Architecture · May-98-Mar-A1 2016
Question 6 of 8: Oil-Heating Tube in Cross-Flow Hot Gas
Nivaar worked solution (AI-drafted; not reviewed by a licensed engineer)
Notes on this paper
National Examinations, May 2016 — 98-Mar-A1 Applied Thermodynamics and Heat Transfer, 3 hours, open book (Part A: Thermodynamics, Part B: Heat Transfer; 5 of 8 questions required, all 8 answered below for full study coverage).
Reference texts: Cengel & Boles, Thermodynamics: An Engineering Approach; Sonntag, Borgnakke & Van Wylen, Fundamentals of Thermodynamics; Incropera & DeWitt, Fundamentals of Heat and Mass Transfer.
It is solved as the thermodynamics/heat-transfer exam it actually is.
Question 6: Oil-Heating Tube in Cross-Flow Hot Gas
Given. Unused engine oil is warmed inside a thin-walled tube by a hot gas (air properties) in cross-flow outside.
Given data
Quantity
Symbol
Value
Oil mass flow rate
$\dot{m}$
0.25 kg/s
Tube diameter, length
$D,\,L$
50 mm, 6 m
Oil inlet temperature
$T_{m,i}$
23°C
Gas (crossflow) temperature, velocity
$T_\infty,\,V$
300°C, 10 m/s
Maximum allowable wall temperature
$T_t$
100°C
Find. Whether the tube-wall temperature exceeds $100^\circ\text{C}$ anywhere along its length.
Oil inside a thin-walled tube, heated by hot gas in cross-flow outside — two convective resistances in series through a negligible tube wall.
Approach. Compute the oil-side (internal, laminar-entry) and gas-side (external, cross-flow cylinder) convection coefficients, combine into an overall $U$ to get the oil outlet temperature, then find the local wall temperature from the two resistances in parallel-balance — and check it against every point along the tube, not just the outlet.
Oil-side coefficient (internal, laminar, combined entry). At a mean bulk oil temperature near 30°C, unused-engine-oil properties (Incropera Table A.5) give $Re_D=4\dot m/(\pi D\mu)\approx16$ (deeply laminar) and $Re_D Pr_D D/L\approx706$ (strong entry effects over the full 6 m). The Sieder–Tate combined-entry correlation,
$$Nu_D=1.86\left(Re_DPr_D\frac{D}{L}\right)^{1/3}\left(\frac{\mu}{\mu_s}\right)^{0.14}$$
gives
$$\boxed{h_i\approx60.4\text{ W/m}^2\text{K}}$$
Gas-side coefficient (external cross-flow over a cylinder). At the gas film temperature ($\approx500\text{ K}$, consistent with the converged wall temperature below), $Re_D=VD/\nu\approx1.32\times10^4$; the Churchill–Bernstein correlation gives $Nu_D\approx61.7$, so
$$\boxed{h_o\approx50.2\text{ W/m}^2\text{K}}$$
Oil outlet temperature. With the tube wall thin (negligible conduction resistance), the overall coefficient is $U=(1/h_i+1/h_o)^{-1}\approx27.4\text{ W/m}^2\text{K}$ on area $A_s=\pi DL=0.9425\text{ m}^2$. Treating the hot gas as an effectively constant-temperature reservoir:
$$\frac{T_\infty-T_{m,o}}{T_\infty-T_{m,i}}=\exp\!\left(-\frac{UA_s}{\dot mc_p}\right)\ \Rightarrow\ \boxed{T_{m,o}\approx37.5^\circ\text{C}}$$
Local wall temperature (inlet and outlet). With the wall thin, the two convective fluxes balance locally: $h_o(T_\infty-T_w)=h_i(T_w-T_m)$, so $T_w=\dfrac{h_oT_\infty+h_iT_m}{h_o+h_i}$. Since $h_o$ and $h_i$ are comparable in magnitude, $T_w$ sits roughly *midway* between the gas and oil temperatures, not close to the oil:
$$T_w(\text{inlet}, T_m=23^\circ\text{C})\approx148.7^\circ\text{C},\qquad T_w(\text{outlet}, T_m=37.5^\circ\text{C})\approx156.6^\circ\text{C}$$
Both are far above the $100^\circ\text{C}$ decomposition limit — and since $T_w$ increases monotonically with $T_m$ along the tube, the wall exceeds $100^\circ\text{C}$ at every point from inlet to outlet, not merely at the ends.
$$\boxed{\text{Yes: the wall temperature (}\approx149\text{--}157^\circ\text{C) exceeds }100^\circ\text{C everywhere along the tube.}}$$