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24-Pet-A3 Fundamental Reservoir Engineering · May 2016

Question 5 of 7: Capillary Pressure — Water-Oil Contact and Transition-Zone Thickness

Nivaar worked solution (AI-drafted; not reviewed by a licensed engineer)

Notes on this paper

98-Pet-A3 — Fundamental Reservoir Engineering · National Exams, May 2016 · 3 hours, closed book, non-communicating calculator only · five (5) questions constitute a complete exam paper (the first five as they appear in the answer book are marked), all questions equal value, all parts of a multipart question equal weight.

Reference texts: Ahmed, T., Reservoir Engineering Handbook, 5th ed. (Darcy's law, transient well testing and image wells, p/Z and oil material balance, capillary pressure/relative permeability); Craft, B.C. & Hawkins, M.F., Applied Petroleum Reservoir Engineering, 3rd ed. (steady-state radial flow, reservoir drive mechanisms); Lyons, W.C. (ed.), Standard Handbook of Petroleum and Natural Gas Engineering, 3rd ed.; McCain, W.D., The Properties of Petroleum Fluids, 3rd ed. (capillary pressure and relative permeability laboratory data).

Question 5: Capillary Pressure — Water-Oil Contact and Transition-Zone Thickness (20 marks)

Question text not reproduced: the examination questions are © Engineers and Geoscientists BC. Open the official past paper (linked at the top of this page) to read the question, then follow the worked solution below.

Given.

Free water level, FWL6000 ft
Oil / water density, $\rho_o,\rho_w$50, 65 lb/ft$^3$
Capillary curve, entry (threshold) point$P_c\approx58$ psi at $S_w=0.30$ (top of near-vertical rise)
Capillary curve, $S_w\to1$ asymptote$P_c\approx14$ psi

Find. (a) Depth of the water-oil contact (WOC); (b) thickness of the transition zone.

00.10.20.30.40.50.60.70.80.91010203040506070Water saturation, SwCapillary pressure, Pc (psi)entry Pc ≈ 58 psi (Sw=0.30)Pc ≈ 14 psi as Sw→1
Fig. 2 — Capillary pressure vs. water saturation. The curve rises sharply from $S_w=0.30$ (entry pressure, top of the oil zone) and flattens toward $\approx14$ psi as $S_w\to1$ (practical 100%-water level, the WOC) — it never reaches $P_c=0$, which defines the deeper FWL.

Approach. Convert capillary pressure to height above the FWL via the buoyancy relation $h=144P_c/(\rho_w-\rho_o)$. The WOC is the depth at which the curve's own data first read $S_w\approx1$ (its low-$P_c$ asymptote, not $P_c=0$); the top of the transition zone is the depth at which $S_w$ first reaches its irreducible value (the curve's near-vertical entry/threshold point). The transition-zone thickness is the height difference between those two levels.

  1. Height-pressure conversion factor. $h=\dfrac{144P_c}{\rho_w-\rho_o}=\dfrac{144P_c}{65-50}=9.6\,P_c$ ft above the FWL.
  2. WOC (practical 100%-water level). The curve flattens to $P_c\approx14$ psi as $S_w\to1$, so $h_{\text{WOC}}=9.6(14)=134.4$ ft above the FWL: $\boxed{\text{WOC}=6000-134.4=5865.6\ \text{ft}}$.
  3. Top of the transition zone (irreducible water saturation reached). The curve's near-vertical rise begins at the entry pressure $P_c\approx58$ psi ($S_w=0.30$, effectively the irreducible saturation for this rock): $h_{\text{top}}=9.6(58)=556.8$ ft above the FWL, at a depth of $6000-556.8=5443.2$ ft.
  4. Transition-zone thickness. The zone spans from the WOC down to where irreducible saturation is reached: $\boxed{\Delta h=h_{\text{top}}-h_{\text{WOC}}=556.8-134.4=422.4\ \text{ft}}$ (equivalently $9.6\times(58-14)$).
QuantityValue
Height/pressure factor, $144/(\rho_w-\rho_o)$9.6 ft/psi
(a) WOC depth5865.6 ft
Top-of-transition-zone depth5443.2 ft
(b) Transition-zone thickness422.4 ft
Check: the source supplies the capillary-pressure curve graphically with axes 0–1 ($S_w$) and 0–70 psi ($P_c$); the entry pressure ($\approx58$ psi at $S_w=0.30$, top of the near-vertical rise) and the high-$S_w$ asymptote ($\approx14$ psi) were read directly off the printed chart, the only two features the curve's own shape calls out numerically.