Question 2 of 10: Gamma Ray Log Character by Lithology
Nivaar worked solution (AI-drafted; not reviewed by a licensed engineer)
Notes on this paper
National Exams, 98-Pet-B1, Well Logging and Formation Evaluation — December 2015, 3 hours, closed book (approved calculators permitted), 10 questions, all marked.
Reference texts: Bassiouni, Theory, Measurement, and Interpretation of Well Logs (SPE Textbook Series Vol. 4); Asquith & Krygowski, Basic Well Log Analysis, 2nd ed. (AAPG); Ellis & Singer, Well Logging for Earth Scientists, 2nd ed.; Schlumberger, Log Interpretation Charts / Log Interpretation Principles and Applications.
Question 2: Gamma Ray Log Character by Lithology (7 marks)
The printed figure is a clean box-car (step-function) gamma-ray trace — depth increasing down the page, radioactivity increasing to the right, no API scale and no serration. Digitising the printed trace gives ten beds at seven distinct radioactivity levels: one level recurs four times (the background the section keeps returning to), and six further levels each occur once. Because the tool measures only total natural radioactivity, the seven listed lithologies are located by RANKING those seven levels, and the recurring background level is necessarily the shale.
Normalising the printed deflections so that the least radioactive bed reads 0% and the most radioactive reads 100% of the trace width:
Bed (top→bottom)
Relative deflection
Lithology
1
83%
Shale (1)
2
0%
Anhydrite (6)
3
83%
Shale (1)
4
64%
Sandy shale (5)
5
83%
Shale (1)
6
4%
Limestone (3)
7
100%
Black marine shale (7)
8
12%
Sandstone (2)
9
45%
Shaly sand (4)
10
83%
Shale (1)
The reasoning behind the ranking, in order of increasing radioactivity:
Anhydrite (6) — the extreme left-hand bed (0%). A pure sulphate evaporite contains no potassium, uranium or thorium at all, so it gives the lowest reading on any gamma-ray log; a clean salt or anhydrite bed is routinely used as the zero-API reference.
Limestone (3) — 4%. Clean calcite is likewise essentially free of K, U and Th; it reads marginally above anhydrite only because of trace clay or organic matter in the matrix.
Sandstone (2) — 12%. Clean quartz sand reads low but characteristically a little HIGHER than a clean carbonate or evaporite, because of the accessory feldspar, mica, glauconite and heavy minerals (zircon, monazite) that almost always accompany a quartz framework.
Shaly sand (4) — 45%. A sand framework carrying dispersed or laminated clay reads roughly half-way between the clean-sand and shale levels, because its clay fraction is intermediate.
Sandy shale (5) — 64%. The complementary mixture — shale-dominated with a sand fraction — therefore reads above shaly sand but still short of the full shale level.
Shale (1) — 83%, the recurring background. The level the trace returns to four times is the ordinary, laterally continuous shale that encloses the whole section; its potassium-bearing clay minerals (illite, mixed-layer clay) set the shale base line.
Black marine shale (7) — 100%, the single most radioactive bed. An organic-rich shale deposited under reducing bottom water adsorbs uranium from sea water, so it reads distinctly ABOVE the ordinary shale base line — the one bed on this trace that exceeds the background shale level.
[Figure not reproduced: The exam's gamma-ray trace redrawn to the printed geometry (bed boundaries and relative deflections read from the printed figure), with the seven lithologies located. Seven distinct radioactivity levels are present; the 83% level recurs four times and is therefore the enclosing shale. See the official exam paper.]
Check: the printed figure carries no API scale, so the deflections above are expressed as a percentage of the printed trace width (least radioactive bed = 0%, most radioactive = 100%), read from the figure. The ranking is unambiguous, but gamma ray alone cannot prove which of the three lowest beds is anhydrite, which is limestone and which is clean sandstone — they are assigned in the conventional order (anhydrite < clean carbonate < clean quartz sand), and separating them definitively needs the density/neutron/PEF combination used in Question 8.