Question 6 of 8: Per-Unit-Length Parameters of a Parallel-Strip Transmission Line
Nivaar worked solution (AI-drafted; not reviewed by a licensed engineer)
Notes on this paper
98-Phys-A3, Electromagnetics — National Exam, May 2016. 3-hour closed-book exam (Casio or Sharp approved calculators only); any FIVE of the eight questions constitute a complete paper and only the first five as they appear in a candidate's answer book are marked, each of equal value. Aids given on the paper: ε0 = 8.85×10-12 F/m, μ0 = 4π×10-7 H/m. All eight printed questions are solved below as a complete study resource.
Reference texts: Sadiku, Elements of Electromagnetics (7th ed.) — transmission lines, waveguides, plane waves, antennas; Hayt & Buck, Engineering Electromagnetics (9th ed.) — transmission-line transients; Pozar, Microwave Engineering (4th ed.) — Smith-chart-free impedance transformation and waveguide cutoff; Balanis, Antenna Theory (4th ed.) — short-dipole far field.
Question 6: Per-Unit-Length Parameters of a Parallel-Strip Transmission Line (equal value)
Approach. Model the ribbons as an ideal parallel-plate capacitor/inductor per unit length (fringing neglected, $w/d=40\gg1$ so this is a good approximation), then combine via $Z_0=\sqrt{L'/C'}$ and $v_p=1/\sqrt{L'C'}$.
Capacitance per unit length.
$$C'=\frac{\varepsilon_0\varepsilon_r w}{d}=\frac{(8.85\times10^{-12})(2.25)(0.02)}{0.0005}=\boxed{796.5\ \text{pF/m}}.$$
Inductance per unit length. For a non-magnetic parallel-plate line, $L'=\mu_0 d/w$:
$$L'=\frac{\mu_0 d}{w}=\frac{(4\pi\times10^{-7})(0.0005)}{0.02}=\boxed{31.42\ \text{nH/m}}.$$
Characteristic impedance.
$$Z_0=\sqrt{\frac{L'}{C'}}=\sqrt{\frac{31.42\times10^{-9}}{796.5\times10^{-12}}}=\boxed{6.28\ \Omega}.$$
(Equivalently, $Z_0=\eta_0\,d/(w\sqrt{\varepsilon_r})$ for a TEM parallel-plate line, which reproduces the same value.)
Propagation velocity. Since $L'C'=\mu_0\varepsilon_0\varepsilon_r$ (the $w,d$ geometry cancels),
$$v_p=\frac{1}{\sqrt{L'C'}}=\frac{c}{\sqrt{\varepsilon_r}}=\frac{3\times10^8}{\sqrt{2.25}}=\boxed{2.00\times10^{8}\ \text{m/s}}.$$
Parallel-strip line cross-section (fringing neglected): dielectric fills the full gap between the two 2 cm ribbons, 0.5 mm apart.